blocks|key|1893896|text|我想一个好的老式循环是最简单的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1893897|++++Bundle+bundle+=+new+Bundle();
++++for+(Map.Entry<String,+String>+entry+:+getData().entrySet())+{
++++++++bundle.putString(entry.getKey(),+entry.getValue());
++++}|code-block|syntax|javascript|1893898|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I guess a good old fashioned for loop is the easiest way:

<pre><code> Bundle bundle = new Bundle();
 for (Map.Entry&lt;String, String&gt; entry : getData().entrySet()) {
 bundle.putString(entry.getKey(), entry.getValue());
 }
</code></pre>

blocks|key|1893907|text|+private+ArrayList<Bundle>+convertMapToBundleList(ArrayList<HashMap<String,+String>>+mapList)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1893908|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> private ArrayList&lt;Bundle&gt; convertMapToBundleList(ArrayList&lt;HashMap&lt;String, String&gt;&gt; mapList)
</code></pre>

blocks|key|1140727|text|您可以使用writeToParcel(Parcel+out,+int+flags)生成类似有用的Parcel，因为它是Bundle的父类，并且作为RemoteMessage类的一部分轻松地内置到Firebase框架中。文档是这里。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1140728|entityMap|0|LINK|mutability|MUTABLE|url|https://firebase.google.com/docs/reference/android/com/google/firebase/messaging/RemoteMessage.html#writeToParcel(android.os.Parcel,%2520int))^0|5|10|1C|6|1N|6|21|D|34|2|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@$9|W|A|X|1|Y]]|E|$]]|$1|F|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

You can use <code>writeToParcel(Parcel out, int flags)</code>to generate a <code>Parcel</code> that could be similarly useful, since it's a parent class of <code>Bundle</code>, and it's handily built into the Firebase framework as part of the <code>RemoteMessage</code> class. Documentation is <a href="https://firebase.google.com/docs/reference/android/com/google/firebase/messaging/RemoteMessage.html#writeToParcel(android.os.Parcel,%20int)" rel="nofollow noreferrer">here</a>.

blocks|key|1140759|text|在firebase消息传递中遇到了同样的问题，并为此创建了一个kotlin扩展函数。吉斯特来了，下面的代码。尽管我正在使用这种方法，但还是有一些注意事项：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1140760|它没有涵盖所有可以放入一个包中的类型|unordered-list-item|1140761|它还在开发中，还没有经过充分的测试。|1140762|考虑到这一点，请使用它作为指南，而不是一个明确的解决方案。随着它的发展，我会保持最新的要旨。|1140763|import+android.os.Bundle+
import+android.os.IBinder
import+android.os.Parcelable
import+java.io.Serializable

fun+<V>+Map<String,+V>.toBundle(bundle:+Bundle+=+Bundle()):+Bundle+=+bundle.apply+{
++forEach+{
++++val+k+=+it.key
++++val+v+=+it.value
++++when+(v)+{
++++++is+IBinder+->+putBinder(k,+v)
++++++is+Bundle+->+putBundle(k,+v)
++++++is+Byte+->+putByte(k,+v)
++++++is+ByteArray+->+putByteArray(k,+v)
++++++is+Char+->+putChar(k,+v)
++++++is+CharArray+->+putCharArray(k,+v)
++++++is+CharSequence+->+putCharSequence(k,+v)
++++++is+Float+->+putFloat(k,+v)
++++++is+FloatArray+->+putFloatArray(k,+v)
++++++is+Parcelable+->+putParcelable(k,+v)
++++++is+Serializable+->+putSerializable(k,+v)
++++++is+Short+->+putShort(k,+v)
++++++is+ShortArray+->+putShortArray(k,+v)

//++++++is+Size+->+putSize(k,+v)+//api+21
//++++++is+SizeF+->+putSizeF(k,+v)+//api+21

++++++else+->+throw+IllegalArgumentException("$v+is+of+a+type+that+is+not+currently+supported")
//++++++is+Array<*>+->+TODO()
//++++++is+List<*>+->+TODO()
++++}
++}
}|code-block|syntax|javascript|1140764|entityMap|0|LINK|mutability|MUTABLE|url|https://gist.github.com/bulwinkel/60f2d06314c0d43225204c00251f1f48^0|16|5|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]]|C|$]]|$1|D|3|E|5|F|7|11|8|@]|9|@]|C|$]]|$1|G|3|H|5|F|7|12|8|@]|9|@]|C|$]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|C|$]]|$1|K|3|L|5|M|7|14|8|@]|9|@]|C|$N|O]]|$1|P|3|-4|5|6|7|15|8|@]|9|@]|C|$]]]|Q|$R|$5|S|T|U|C|$V|W]]]]

Came across this same issue with firebase messaging and created a kotlin extension function for it. The <a href="https://gist.github.com/bulwinkel/60f2d06314c0d43225204c00251f1f48" rel="noreferrer">gist is here</a>, code below. Although I am using this method there are some caveats:

<ul>
<li>it doesn't cover all of the types that can be put into a bundle</li>
<li>it is still under development and hasn't been fully tested</li>
</ul>

With this in mind, please use it as a guide not a definitive solution. I will keep the gist up to date as it evolves.

<pre><code>import android.os.Bundle 
import android.os.IBinder
import android.os.Parcelable
import java.io.Serializable

fun &lt;V&gt; Map&lt;String, V&gt;.toBundle(bundle: Bundle = Bundle()): Bundle = bundle.apply {
 forEach {
 val k = it.key
 val v = it.value
 when (v) {
 is IBinder -&gt; putBinder(k, v)
 is Bundle -&gt; putBundle(k, v)
 is Byte -&gt; putByte(k, v)
 is ByteArray -&gt; putByteArray(k, v)
 is Char -&gt; putChar(k, v)
 is CharArray -&gt; putCharArray(k, v)
 is CharSequence -&gt; putCharSequence(k, v)
 is Float -&gt; putFloat(k, v)
 is FloatArray -&gt; putFloatArray(k, v)
 is Parcelable -&gt; putParcelable(k, v)
 is Serializable -&gt; putSerializable(k, v)
 is Short -&gt; putShort(k, v)
 is ShortArray -&gt; putShortArray(k, v)

// is Size -&gt; putSize(k, v) //api 21
// is SizeF -&gt; putSizeF(k, v) //api 21

 else -&gt; throw IllegalArgumentException("$v is of a type that is not currently supported")
// is Array&lt;*&gt; -&gt; TODO()
// is List&lt;*&gt; -&gt; TODO()
 }
 }
}
</code></pre>

blocks|key|1893980|text|这是我在科特林做的事|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1893981|val+bundle+=+Bundle()

for+(entry+in+data.entries)
++++bundle.putString(entry.key,+entry.value)|code-block|syntax|javascript|1893982|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

here is how I did it in Kotlin

<pre><code>val bundle = Bundle()

for (entry in data.entries)
 bundle.putString(entry.key, entry.value)
</code></pre>

blocks|key|973651|text|现在你可以使用fun+bundleOf(vararg+pairs:+Pair<String,+Any?>)了|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|973652|entityMap^0|7|1A|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Nowadays you can use <code>fun bundleOf(vararg pairs: Pair&lt;String, Any?&gt;)</code>

blocks|key|1140815|text|使用spread运算符的整洁Kotlin解决方案如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1140816|fun+Map<String,+Any?>.toBundle():+Bundle+=+bundleOf(*this.toList().toTypedArray())|code-block|syntax|javascript|1140817|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Neat Kotlin solution using spread operator will look like that:
<pre><code>fun Map&lt;String, Any?&gt;.toBundle(): Bundle = bundleOf(*this.toList().toTypedArray())
</code></pre>

blocks|key|976291|text|将来可以用来作参考|type|unstyled|depth|inlineStyleRanges|entityRanges|data|976292|将Map转换为String|blockquote|976293|++fun+Map<String,+String>.convertExtraMapToString():+String?+{
++++return+keys.stream()
++++++++.map+{+key:+String+->+"$key="+%2B+this[key]+}.collect(Collectors.joining(",+",+"{",+"}"))
}|code-block|syntax|javascript|976294|将字符串转换为Map，然后转换为Bundle|976295|fun+String.convertExtraMapToBundle():+Bundle+{
++++return+Arrays.stream(split(",".toRegex()).toTypedArray())
++++++++.map+{+entry:+String+->+entry.split("=".toRegex()).toTypedArray()+}
++++++++.collect(Collectors.toMap(
++++++++++++{+entry:+Array<String>+->+entry[0]+})+{+entry:+Array<String>+->+entry[1]+}).let+{
++++++++++++bundleOf(*it.toList().toTypedArray())
++++++++}
}|976296|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|R|8|@]|9|@]|A|$H|I]]|$1|J|3|K|5|D|7|S|8|@]|9|@]|A|$]]|$1|L|3|M|5|G|7|T|8|@]|9|@]|A|$H|I]]|$1|N|3|-4|5|6|7|U|8|@]|9|@]|A|$]]]|O|$]]

For future reference 
<blockquote>
Convert Map to String
</blockquote>
<pre><code> fun Map&lt;String, String&gt;.convertExtraMapToString(): String? {
 return keys.stream()
 .map { key: String -&gt; &quot;$key=&quot; + this[key] }.collect(Collectors.joining(&quot;, &quot;, &quot;{&quot;, &quot;}&quot;))
}
</code></pre>
<blockquote>
Convert String to Map then to Bundle
</blockquote>
<pre><code>fun String.convertExtraMapToBundle(): Bundle {
 return Arrays.stream(split(&quot;,&quot;.toRegex()).toTypedArray())
 .map { entry: String -&gt; entry.split(&quot;=&quot;.toRegex()).toTypedArray() }
 .collect(Collectors.toMap(
 { entry: Array&lt;String&gt; -&gt; entry[0] }) { entry: Array&lt;String&gt; -&gt; entry[1] }).let {
 bundleOf(*it.toList().toTypedArray())
 }
}
</code></pre>

blocks|key|1140830|text|在Kotlin中，您可以构建一个函数扩展来将Map转换为Bundle，而无需显式迭代，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1140831|override+fun+onMessageReceived(remoteMessage:+RemoteMessage)+{
++++++++val+payload+=+remoteMessage.data.toBundle()
++++++++Log.d(TAG,+"Notification+payload:+$payload")
++++++++//+...
}|code-block|syntax|javascript|1140832|其中toBundle()的定义如下：|offset|length|style|BOLD|1140833|inline+fun+<reified+T>+Map<String,+T>.toBundle():+Bundle+=+bundleOf(*toList<String,+T?>().toTypedArray())|1140834|或者再一次：|1140835|inline+fun+<reified+T>+Map<String,+T>.toBundle():+Bundle+=+bundleOf(*map+{+it.key+to+it.value+}.toTypedArray())|1140836|entityMap^0|0|0|2|A|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

In Kotlin you can build a function extension to convert Map to Bundle without explicit iteration like so:
<pre><code>override fun onMessageReceived(remoteMessage: RemoteMessage) {
 val payload = remoteMessage.data.toBundle()
 Log.d(TAG, &quot;Notification payload: $payload&quot;)
 // ...
}
</code></pre>
where toBundle() is defined like so:
<pre><code>inline fun &lt;reified T&gt; Map&lt;String, T&gt;.toBundle(): Bundle = bundleOf(*toList&lt;String, T?&gt;().toTypedArray())
</code></pre>
or again:
<pre><code>inline fun &lt;reified T&gt; Map&lt;String, T&gt;.toBundle(): Bundle = bundleOf(*map { it.key to it.value }.toTypedArray())
</code></pre>

Is there an easy way to convert a Map to a Bundle in android without explicit iteration? 

Why?

Firebase returns a Map for Notification <code>getData()</code>. I need to pass the data to an intent. Formerly GCM gave me a bundle, so I didn't need to worry about this.

Convert Map to Bundle in android

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有没有一种简单的方法可以在没有显式迭代的情况下将Map转换为android中的Bundle？为什么？Firebase返回通知getData()的映射。我需要把数据传递给一个意图。以前GCM给了我一个包，所以我不需要担心这个。

问在android中将Map转换为Bundle
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问在android中将Map转换为BundleEN