blocks|key|3115663|text|首先，您使用的是input()，当您在终端中输入数字时返回int。您应该使用raw_input()并逐行获取它。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3115664|第二，您正在尝试将列表转换为整数，您应该循环遍历列表值，然后在结果列表上进行转换和插入。|3115665|固定代码：|3115666|def+arr_input(x):
++++for+i+in+range(6):
++++++++num_list+=+raw_input().split('+')
++++++++for+j,+str_num+in+enumerate(num_list):
++++++++++++n+=+int(str_num)
++++++++++++if+n+>=+-9+and+n+<=+9:
++++++++++++++++x[i][j]+=+n
++++print+"\n"|code-block|syntax|javascript|3115667|在这里，我使用enumerate()通过每次迭代获得它的索引来循环数字列表。|3115668|entityMap^0|8|7|12|B|0|0|0|0|7|B|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|Z|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

First of all, you are using <code>input()</code> which returns int when you enter numbers in terminal. You should use <code>raw_input()</code> and get it line by line.

Second, you are trying to convert a list to integer, you should loop through the list values, convert and insert on the resulting list.

Fixed code:


<pre><code>def arr_input(x):
 for i in range(6):
 num_list = raw_input().split(' ')
 for j, str_num in enumerate(num_list):
 n = int(str_num)
 if n &gt;= -9 and n &lt;= 9:
 x[i][j] = n
 print "\n"
</code></pre>

Here, I used <code>enumerate()</code> to loop though the number list by getting its index each iteration.

blocks|key|3870795|text|你对待输入的方式有不一致之处。在python+2.7中，and+()函数设计为读取stdin中的一个参数，而且只读取一个参数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3870796|我不太清楚你是怎么读输入的。嵌套的for循环表示您试图逐个读取值，但拆分表明您正在逐行地读取这些值。为了涵盖所有的基础，我会解释这两种情况。其中至少有一个是相关的。|3870797|案例1:假设您一直在一个接一个地输入值，即|offset|length|style|BOLD|3870798|1
4
9
4
...|code-block|syntax|javascript|3870799|在本例中，所发生的情况是that+()函数将输入自动解析为整数，当您尝试对整数运行拆分()时，会出现类型错误。Python需要一个字符串，而您正在提供一个int。那会打破的。有一个简单的解决方案--这可以通过简单地将这一行替换为|3870800|n+=+input()|3870801|案例2:假设您正在逐行输入数字，作为字符串输入。我的意思是：|3870802|"1+3+4+5+7+9"
"4+1+8+2+5+1"
...|3870803|这里发生的是int(.)正在尝试将字符串列表转换为整数。这显然会破坏代码。一个可能的解决方案是通过去掉内部for循环来重构代码。像这样的事情应该有效：|3870804|def+arr_input(arr):
++++for+i+in+range(6):
++++++++s+=+input()
++++++++nums_s+=+s.split('+')
++++++++nums+=+[int(x)+for+x+in+nums_s]
++++++++arr.append(nums)
++++print+"\n"
++++return+arr

#+Usage
a+=+[]
print(a)
a+=+arr_input(a)
print(a)|3870805|entityMap^0|0|0|0|L|0|0|0|36|0|0|0|U|0|0|0|23|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|14|8|@$F|15|G|16|H|I]]|9|@]|A|$]]|$1|J|3|K|5|L|7|17|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|18|8|@$F|19|G|1A|H|I]]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1B|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|1C|8|@$F|1D|G|1E|H|I]]|9|@]|A|$]]|$1|U|3|V|5|L|7|1F|8|@]|9|@]|A|$M|N]]|$1|W|3|X|5|6|7|1G|8|@$F|1H|G|1I|H|I]]|9|@]|A|$]]|$1|Y|3|Z|5|L|7|1J|8|@]|9|@]|A|$M|N]]|$1|10|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|11|$]]

There's an inconsistency in how you're treating the input. In python 2.7, the input() function is designed to read one, and only one, argument from stdin. 

I'm not exactly sure which way you're trying to read the input in. The nested for loop suggests that you're trying to read the values in one by one, but the split suggests that you're doing it line by line. To cover all bases, I'll explain both cases. At least one of them will be relevant.

Case 1:
Let's say you've been inputting the values one by one, i.e.

<pre><code>1
4
9
4
...
</code></pre>

In this case, what's happening is that the input() function is automatically parsing the inputs as integers, and when you try running split() on an integer there's a type error. Python is expecting a string and you're providing an int. That's going to break. There's an easy solution--this can be fixed by simply replacing that line with 

<pre><code>n = input()
</code></pre>

Case 2: Let's say you're inputing the numbers line by line, as strings. By this, I mean something like:

<pre><code>"1 3 4 5 7 9"
"4 1 8 2 5 1"
...
</code></pre>

What's occurring here is that int(...) is trying to cast a list of strings into an integer. That will clearly break the code. A possible solution would be to restructure the code by gett rid of the inner for loop. Something like this should work:

<pre><code>def arr_input(arr):
 for i in range(6):
 s = input()
 nums_s = s.split(' ')
 nums = [int(x) for x in nums_s]
 arr.append(nums)
 print "\n"
 return arr

# Usage
a = []
print(a)
a = arr_input(a)
print(a)
</code></pre>

blocks|key|3974666|text|试试看这个单线：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3974667|def+arr_input(N=6):
++++print+'Enter+%25d+by+%25d+array,+one+row+per+line+(elements+separated+by+blanks)'+%25+(N,+N)++++
++++return+[[n+if+abs(n)<=9+else+0+for+n+in+map(int,+raw_input().split())]+for+i+in+range(N)]|code-block|syntax|javascript|3974668|下面的交互式会议演示了它的用法：|3974669|>>>+A+=+arr_input(3)
Enter+3+by+3+array,+one+row+per+line+(elements+separated+by+blanks)
1+2+-3
4+5+-6
8+9+10
>>>+A
[[1,+2,+-3],+[4,+5,+-6],+[8,+9,+0]]|3974670|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Give this one-liner a try:

<pre><code>def arr_input(N=6):
 print 'Enter %d by %d array, one row per line (elements separated by blanks)' % (N, N) 
 return [[n if abs(n)&lt;=9 else 0 for n in map(int, raw_input().split())] for i in range(N)]
</code></pre>

The following interactive session demonstrates its usage:

<pre><code>&gt;&gt;&gt; A = arr_input(3)
Enter 3 by 3 array, one row per line (elements separated by blanks)
1 2 -3
4 5 -6
8 9 10
&gt;&gt;&gt; A
[[1, 2, -3], [4, 5, -6], [8, 9, 0]]
</code></pre>

I have a 2-D 6x6 array, <code>A</code>.
I want its values to be input by the user in the following format or example:

<pre><code>0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
</code></pre>

where the <code>0</code>'s indicate the places where the user would write their values.

This is my code. It returns an error in <code>split()</code>. 

<pre><code>def arr_input(x):
 for i in range(6):
 for j in range(6):
 n = int(input().split(' '))
 if n&gt;=-9 and n&lt;=9:
 x[i][j] = n
 print "\n"
</code></pre>

I don't want input in a single line. Please help!

<hr>

EDIT 1
The code I needed was already provided :D. Nevertheless, I learned something new and helpful. Here is the existing code to do the task I wanted:

<pre><code>arr = []
for arr_i in xrange(6):
 arr_temp = map(int,raw_input().strip().split(' '))
 arr.append(arr_temp)
</code></pre>

Taking user input of 2-D array in a given format

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个二维6x6数组，A。我希望用户以下列格式或示例输入它的值：0 0 0 0 0 00 0 0 0 0 00 0 0 0 0 00 0 0 0 0 00 0 0 0 0 00 0 0 0 0 0其中0表示用户将写入值的位置。这是我的密码。它返回split()中的一个错误。def arr_input(x):    f...

问以给定格式接收二维数组的用户输入。
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问以给定格式接收二维数组的用户输入。EN