我有2个php文件(function.php,dp.php)在dp.php中,我调用update函数如下
include('function.php');
$db = new Database();
$db->connect();
$db->update('classes', array('level'=> '(CASE WHEN level = 1 THEN 2
WHEN level = 2 THEN 3
WHEN level = 3 THEN 4
END)','modifiedTime'=>date("Y-m-d H:i:s")), 'level IN (1,2,3)');
$res = $db->getResult();
print_r($res);和更新功能:
public function update($table,$params=array(),$where){
if($this->tableExists($table)){
$args=array();
foreach($params as $field=>$value){
$args[]=$field.'="'.$value.'"';
}
$sql='UPDATE '.$table.' SET '.implode(',',$args).' WHERE '.$where;
$this->myQuery = $sql; // Pass back the SQL
if($query = $this->myconn->query($sql)){
array_push($this->result,$this->myconn->affected_rows);
return true;
}else{
array_push($this->result,$this->myconn->error);
return false;
}
}else{
return false;
}
}我总是得到的结果是0,其中应该是2,3,或4。
在执行phpmyadmin时,is工作的实际语句是:
update classes set level = (CASE WHEN level = 1 THEN 2
WHEN level = 2 THEN 3
WHEN level = 3 THEN 4
END), modifiedTime = date("Y-m-d H:i:s")) WHERE level IN (1,2,3));提前感谢
发布于 2016-06-18 01:27:23
您可以尝试使用current_timestamp而不是使用日期(..)在你的db.php里
include('function.php');
$db = new Database();
$db->connect();
$db->update('tbl_class', array('level'=> '(CASE WHEN level = 1 THEN 2
WHEN level = 2 THEN 3
WHEN level = 3 THEN 4
END)','update_time' => CURRENT_TIMESTAMP), 'level IN (1,2,3)');
$res = $db->getResult();
print_r($res);还有一件事要做,就是纠正你的函数。
public function update($table,$params=array(),$where){
if($this->tableExists($table)){
$args=array();
foreach($params as $field=>$value){
$args[]=$field.' = '.$value.' ';
}
$sql='UPDATE '.$table.' SET '.implode(' , ',$args).' WHERE '.$where;
$this->myQuery = $sql;
if($query = $this->myconn->query($sql)){
array_push($this->result,$this->myconn->affected_rows);
return true;
}else{
array_push($this->result,$this->myconn->error);
return false;
}
}else{
return false;
}
}https://stackoverflow.com/questions/37891913
复制相似问题