我有带有数组对的JSON对象,如下所示:
对象{x: Array36159,y: Array36159,年份: Array36159}
小样本为例:
{
"x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -39360182208.042145],
"y": [13950252.45052416, 1158787.402385158, -4368238.261400843, 1339913.7393283844, 2085336.6277048483],
"year": [1991, 1991, 1992, 1992, 1992]
}我想每年过滤这个物体。如果JSON数据是数组或键、值对,我可以使用筛选器:
data.filter(function (x) {
return x.year == 1991
});但是由于JSON结构是对平面数组,我不知道如何处理。
预期的结果是:
{
"x": [309339618361.619, 102862032084.12102],
"y": [13950252.45052416, 1158787.402385158],
"year": [1991, 1991]
}发布于 2016-07-02 15:00:38
您可以对属性使用回调和比较以及数组,您需要将筛选器应用到上面。
var object = {
"x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -39360182208.042145],
"y": [13950252.45052416, 1158787.402385158, -4368238.261400843, 1339913.7393283844, 2085336.6277048483],
"year": [1991, 1991, 1992, 1992, 1992]
},
result = {};
['x', 'y', 'year'].forEach(function (p) {
result[p] = object[p].filter(function (a, i) {
return object.year[i] === 1991;
});
});
console.log(result);
发布于 2016-07-02 15:04:16
您可以使用reduce()并按要筛选的年份索引添加值。
var obj = {
"x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -39360182208.042145],
"y": [13950252.45052416, 1158787.402385158, -4368238.261400843, 1339913.7393283844, 2085336.6277048483],
"year": [1991, 1991, 1992, 1992, 1992]
}
var result = obj.year.reduce(function(r, e, i) {
if (e == 1991) {
r.x = (r.x || []).concat(obj.x[i]);
r.y = (r.y || []).concat(obj.y[i]);
r.year = (r.year || []).concat(obj.year[i])
}
return r;
}, {});
console.log(result)
发布于 2016-07-02 15:16:55
只需复制obj并迭代year属性的元素并删除不等于1991的元素。
var obj = {
x: [309339618361.619, 102862032084.12102],
y: [13950252.45052416, 1158787.402385158],
year: [1991, 1991]
},
scan = {};
Object.assign(scan, obj);
for(var i = 0, len = scan.year.length; i < len; i ++) {
if(scan.year[i] !== 1991) {
scan.year.splice(i, 1);
}
}
console.log(scan);https://stackoverflow.com/questions/38161363
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