blocks|key|1180099|text|使用addObject方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1180100|[array+addObject:@"HEllo"];|code-block|syntax|javascript|1180101|其中数组是一个NSMutableArray|offset|length|style|CODE|1180102|在示例方法中，它将如下所示：|1180103|+-(NSMutableArray+*)arrayByAddingString:(NSString+*)string+toArray:(NSMutableArray+*)array
+++return+[array+addObject:string];

++}|1180104|entityMap^0|0|0|7|E|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Use addObject method: 

<pre><code>[array addObject:@"HEllo"];
</code></pre>

Where array is a <code>NSMutableArray</code> 

In you example method, it will be like this:

<pre><code> -(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array
 return [array addObject:string];

 }
</code></pre>

blocks|key|1180134|text|你只需要做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1180135|+-(NSMutableArray+*)arrayByAddingString:(NSString+*)string+toArray:(NSMutableArray+*)array
+++return+[array+addObject:string];

++}|code-block|syntax|javascript|1180136|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You just need to do is

<pre><code> -(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array
 return [array addObject:string];

 }
</code></pre>

blocks|key|856900|text|U作为NSArray创建新的数组，它不是可变的，并且您试图添加的对象是字符串--为什么要使用[string]，您可以这样做，|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|856901|+-(NSMutableArray+*)arrayByAddingString:(NSString+*)string+toArray:(NSMutableArray+*)array
++{
++++NSMutableArray+*newArray+=+[NSMutableArray+arrayWithArray:array];
++++[newArray+addObject:string];+//no+need+of+square+brace,+because+string+is+an+object+
++++return+newArray;+//return+the+new+array+not+the+`array`
+}|code-block|syntax|javascript|856902|entityMap^0|3|7|1A|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

u are creating the new array as just <code>NSArray</code> which is not mutable, and also the object u are trying to add is string why to use of <code>[string]</code>, u can do like below,

<pre><code> -(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array
 {
 NSMutableArray *newArray = [NSMutableArray arrayWithArray:array];
 [newArray addObject:string]; //no need of square brace, because string is an object 
 return newArray; //return the new array not the `array`
 }
</code></pre>

blocks|key|856904|text|代码中有额外的[]，将其更改为：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|856905|[newArray+arrayByAddingObject:string];|code-block|syntax|javascript|856906|entityMap^0|7|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

There are extra <code>[]</code> in the code, change it to:

<pre><code>[newArray arrayByAddingObject:string];
</code></pre>

blocks|key|856918|text|应该是这样的；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|856919|-(NSMutableArray+*)arrayByAddingString:(NSString+*)string+toArray:(NSMutableArray+*)array
++++{
+++++++++++[array+addObject:string];

++++++++++++return+array;
++++}|code-block|syntax|javascript|856920|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It should be like; 

<pre><code>-(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array
 {
 [array addObject:string];

 return array;
 }
</code></pre>

blocks|key|1594502|text|你可以这样用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1594503|斯威夫特|blockquote|1594504|func+arrayByAddingString(string:+String,+array:+NSMutableArray)+->+{
array.addObject(String)
return+array
}|code-block|syntax|javascript|1594505|在目标C中|1594506|-(NSMutableArray+*)arrayByAddingString:(NSString+*)string+toArray:(NSMutableArray+*)array{
[array+addObject:string];++++
return+array;
}|1594507|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|R|8|@]|9|@]|A|$H|I]]|$1|J|3|K|5|D|7|S|8|@]|9|@]|A|$]]|$1|L|3|M|5|G|7|T|8|@]|9|@]|A|$H|I]]|$1|N|3|-4|5|6|7|U|8|@]|9|@]|A|$]]]|O|$]]

You can use like this

<blockquote>
 In Swift
</blockquote>

<pre><code>func arrayByAddingString(string: String, array: NSMutableArray) -&gt; {
array.addObject(String)
return array
}
</code></pre>

<blockquote>
 In Objective C
</blockquote>

<pre><code>-(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array{
[array addObject:string]; 
return array;
}
</code></pre>

I was wondering how to add a string to a mutable array without having to change the original array. So I'm thinking I have to make a copy of the array argument and then add the string to that. 

<pre><code> -(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array
 {
 NSArray *newArray = [NSMutableArray arrayWithArray:array];

 [newArray arrayByAddingObject:[string]];

return array;
}
</code></pre>

I get the error Expected identifer, not sure what that means.

Adding a string to an Array in IOS

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想知道如何在不更改原始数组的情况下将字符串添加到可变数组中。因此，我认为我必须复制数组参数，然后将字符串添加到其中。    -(NSMutableArray *)arrayByAddingString:(NSString *)string toArray:(NSMutableArray *)array     {  ...

问在IOS中向数组中添加字符串
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问在IOS中向数组中添加字符串EN