blocks|key|1372724|text|使用Array.find+API。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1372725|示例：|BOLD|1372726|​|1372727|"use+strict";

let+items+=+["component.part",+"random-component",+"prefix-component-name",+"component"];

let+found+=+items.find(item+=>+{+return+item+===+"component.part"+}+);

if+(found)+{
++++console.log("Item+exists.");
}|code-block|syntax|javascript|1372728|1372729|有关更多用法的示例。|1372730|见：+Objects/Array/find|1372731|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/find^0|2|A|0|0|3|0|0|0|0|0|0|2|3|I|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|15|8|@$9|16|A|17|B|H]]|D|@]|E|$]]|$1|I|3|J|5|6|7|18|8|@]|D|@]|E|$]]|$1|K|3|L|5|M|7|19|8|@]|D|@]|E|$N|O]]|$1|P|3|J|5|6|7|1A|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1B|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|1C|8|@$9|1D|A|1E|B|H]]|D|@$9|1F|A|1G|1|1H]]|E|$]]|$1|U|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|11]]]]

Use the <code>Array.find</code> API.

Example:

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>"use strict";

let items = ["component.part", "random-component", "prefix-component-name", "component"];

let found = items.find(item =&gt; { return item === "component.part" } );

if (found) {
 console.log("Item exists.");
}</code></pre>
</div>
</div>


For more usage example.

See:
<a href="https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/find" rel="nofollow">https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/find</a>

blocks|key|1372674|text|一种方法是使用.find()从数组中获取所需的字符串。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1372675|entityMap^0|7|7|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

One way is to use <code>.find()</code> to get the string you want from the Array.

blocks|key|949708|text|尝试使用$.inArray()方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|949709|var+list=["component.part",+"random-component",+"prefix-component-name",+"component"];
if($.inArray("+component",list)+!=+-1){
++++console.log("Item+found");
}|code-block|syntax|javascript|949710|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try using $.inArray() method.

<pre><code>var list=["component.part", "random-component", "prefix-component-name", "component"];
if($.inArray(" component",list) != -1){
 console.log("Item found");
}
</code></pre>

blocks|key|1372750|text|有谁知道在不使用indexOf的情况下检查列表是否包含字符串的方法？在我的数组中，有些字符串可以包含其他字符串的一部分，因此indexOf将产生假阳性。|type|blockquote|depth|inlineStyleRanges|entityRanges|data|1372751|假阳性？Array.prototype.indexOf和Array.prototype.includes都使用严格的等式，这使得这里不可能这样做。|unstyled|offset|length|style|CODE|1372752|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/indexOf|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes^0|0|4|N|S|O|4|N|0|S|O|1|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@$E|U|F|V|G|H]|$E|W|F|X|G|H]]|9|@$E|Y|F|Z|1|10]|$E|11|F|12|1|13]]|A|$]]|$1|I|3|-4|5|D|7|14|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]|Q|$5|L|M|N|A|$O|R]]]]

<blockquote>
 Does anyone know of a way to check if a list contains a string without using indexOf? In my array some strings can contains parts of others, so indexOf will produce false positives.
</blockquote>

false positives? <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/indexOf" rel="nofollow"><code>Array.prototype.indexOf</code></a> and <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes" rel="nofollow"><code>Array.prototype.includes</code></a> both use strict equality which makes that impossible here.

blocks|key|1372770|text|IndexOf不会给你假阳性。如果你想找到所有有“其他组件”的元素，你可以循环你的数组并检查String.includes()|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1372771|这里是一个初学者友好的解决方案。|1372772|​|1372773|++++var+arr+=+["component.part",+"random-component",+
++++"prefix-component-name",+"component",+"asdf"];+
++++
++++console.log(arr.indexOf('component'));+//+give+u+3
++++
++++for+(var+i+=+0;+i+<+arr.length;+i%2B%2B){
++++++if+(arr[i].includes('component')){
++++++++console.log(arr[i]);
++++++}
++++}|code-block|syntax|javascript|1372774|1372775|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|P|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|Q|8|@]|9|@]|A|$I|J]]|$1|K|3|E|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

IndexOf won't give you false positive. It will give you 3. If you want to find all elements that has "otherstuff componenet" you can loop through your array and check with String.includes()

Here is a beginner friendly solution.

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code> var arr = ["component.part", "random-component", 
 "prefix-component-name", "component", "asdf"]; 
 
 console.log(arr.indexOf('component')); // give u 3
 
 for (var i = 0; i &lt; arr.length; i++){
 if (arr[i].includes('component')){
 console.log(arr[i]);
 }
 }</code></pre>
</div>
</div>

Does anyone know of a way to check if a list contains a string without using indexOf? In my array some strings can contains parts of others, so indexOf will produce false positives.

As an example, how would I determine if "component" is in the array below?

<pre><code>["component.part", "random-component", "prefix-component-name", "component"]
</code></pre>

Update:

It seems like my use of false positive was misleading. I meant that it would say that component was in there 4 times, when I want to match the string by itself.

ie. It should return false when checking for the presence of "component" in the below array.

<pre><code>["component.part", "random-component", "prefix-component-name"]
</code></pre>

Javascript list contains a string

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋 

腾讯云代码助手

CODING DevOps

Cloud Studio

SDK中心

API中心

命令行工具

有谁知道在不使用indexOf的情况下检查列表是否包含字符串的方法？在我的数组中，有些字符串可以包含其他字符串的一部分，因此indexOf将产生假阳性。例如，如何确定“组件”是否在下面的数组中？["component.part", "random-component", "prefix-component-name", "component"]更新：看来我的假阳性是误导性的。我的意思是，当我想要自

问Javascript列表包含一个字符串
EN

回答 5

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Javascript列表包含一个字符串EN

回答 5

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Javascript列表包含一个字符串
EN