IOS: kCFErrorDomainCFNetwork错误-1002。错误Domain=NSURLErrorDomain代码=-1002“不支持的URL”
IOS: kCFErrorDomainCFNetwork错误-1002。错误Domain=NSURLErrorDomain代码=-1002“不支持的URL”
提问于 2016-09-15 12:02:09
你好，我知道以前问过的这类问题，但是在我的项目中我没有从他们那里得到任何解决方案，我在登录视图中工作，当我在登录按钮上放置代码时，我得到了一个错误。
错误:错误Domain=NSURLErrorDomain代码=-1002“不支持的URL”UserInfo=0x7fb37b62c9a0 {NSLocalizedDescription=unsupported URL，NSUnderlyingError=0x7fb37b715a20“操作无法完成。(kCFErrorDomainCFNetwork错误-1002.)"}
但我使用的登录代码与我在以前的项目中使用的代码相同，而且在那里运行良好。
这是我的代码：
-(IBAction)login:(id)sender
{
NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
NSURL *url = [NSURL URLWithString:@"http://eyeforweb.info.bh-in-15.webhostbox.net/myconnect/api.php?token={LS0tLS1CRUdJTiBQVUJMSUMgS0VZLS0tLS0KTUc4d0RRWUpLb1pJaHZjTkFRRUJCUUFEWGdBd1d3SlVBeWo0WE9JNjI4cnJRTG9YeEpXNG1zUWI1YmtvYk1hVQpzMnY1WjFKeXJDRWdpOVhoRzZlZk4rYTR0eGlMTVdaRXdNaS9uS1cyL1NCS2pCUnBYUzVGYUdiV0VLRG1WOXkvCkYrWHhsUXVoeER0MEV3YkRBZ01CQUFFPQotLS0tLUVORCBQVUJMSUMgS0VZLS0tLS0K}&method=user.getLogin"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval:60.0];
[request addValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request addValue:@"*/*" forHTTPHeaderField:@"Accept"];
[request setHTTPMethod:@"POST"];
NSString *mapData = [NSString stringWithFormat:@"login=abc@gmail.com&password=123456"];//,username.text, password.text];
NSData *postData = [mapData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
[request setHTTPBody:postData];
NSLog(@"map data is = %@",mapData);
NSURLSessionDataTask * postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData * data, NSURLResponse* response, NSError * error) {
if(error == nil)
{
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSString *text = [[NSString alloc] initWithData: data encoding: NSUTF8StringEncoding];
NSLog(@"Data = %@",text);
NSDictionary *jsonDic = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSLog(@"jsondic= %@",jsonDic);
NSDictionary *userDataDic = [jsonDic objectForKey:@"data"];
NSLog(@"Dict is %@",userDataDic);请帮助我解决这个问题，我已经看到了类似的问题，但是没有从这个问题上克服任何帮助。
回答 1
Stack Overflow用户
发布于 2016-09-15 13:24:07
我试过您的code.Except您的URL，其他代码行是correct.If，传递您的corrct，它工作得很好。
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://eyeforweb.info.bh-in-15.webhostbox.net/myconnect/api.php"]]; //pass your url here
[request setHTTPMethod:@"POST"];
//Passing The String to server
NSString *strUserId = @"pradeep.kumar@eyeforweb.com";
NSString *strPassword = @"admin123";
NSString *userUpdate =[NSString stringWithFormat:@"login=%@&password=%@",strUserId,strPassword, nil];
//Check The Value what we passed
NSLog(@"the data Details is %@", userUpdate);
//Convert the String to Data
NSData *data1 = [userUpdate dataUsingEncoding:NSUTF8StringEncoding];
NSLog(@"The postData is - %@",data1);
//Apply the data to the body
[request setHTTPBody:data1];
NSURLSession *session = [NSURLSession sharedSession];
NSURLSessionDataTask *dataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response;
if(httpResponse.statusCode == 200)
{
NSError *parseError = nil;
NSDictionary *responseDictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
NSLog(@"The response is - %@",responseDictionary);
NSInteger success = [[responseDictionary objectForKey:@"success"] integerValue];
if(success == 1)
{
NSLog(@"Login SUCCESS");
}
else
{
NSLog(@"Login FAILURE");
}
}
else
{
NSLog(@"Error");
}
}];
[dataTask resume];页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/39510552
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