各位,
我正在使用zip4j API提取java中的文件,并能够提取这些文件。
问题是在提取之后,应该将文件解压缩到zipFile.extractAll(path)
方法提供的路径上,但是正在创建另一个目录。如何将文件解压缩到实际指定的目录中?
类似:提取路径 C:\ExtractionPath
文件路径 C:\SelectingPath\File1 1
C:\SelectingPath\File2 2
C:\SelectingPath\Directory1 1\File1 1
C:\SelectingPath\Directory2 2\File1 1
我将选择要压缩的C:\SelectingPath目录
我将选择C:\ExtractionPath目录来解压缩文件。
提取之后,所有提取的文件都将进入
**C:\ExtractionPath\SelectingPath**
我需要目录中的所有文件
**C:\ExtractionPath**本身。
请帮我解决这个问题。
提前感谢
发布于 2016-09-26 05:05:17
谢谢安德烈亚斯!
我们需要将ArrayList<File>
作为参数传递给addFiles(ArrayList, ZipParameters)
方法,以便归档目录的整个目录内容。我得到了预期的输出
遵循归档代码流:
public void archieveFiles(File fileDirectory, String stringPassword) throws Exception {
try{
String[] filesDirectoryList = fileDirectory.list();
ArrayList<File> listFileDirectory = new ArrayList<>(); //To list the files to archive
for(int iListCount = 0; iListCount < filesDirectoryList.length; iListCount++){
listFileDirectory.add(new File(fileDirectory+"\\"+filesDirectoryList[iListCount]));
}
ZipFile zipFile = new ZipFile("C:\\CreateZIP\\FileArchive.zip");
//Initiate Zip Parameters which define various properties
ZipParameters parameters = new ZipParameters();
// Set compression method to deflate compression
parameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
//Set the encryption flag to true
parameters.setEncryptFiles(true);
//Set the encryption method to AES Zip Encryption
parameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES);
//file encrypted with key strength of 192, then Zip4j can decrypt this file
parameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256);
//Set password
parameters.setPassword(stringPassword);
// Zip the directory files
zipFile.addFiles(listFileDirectory, parameters);
}
catch(ZipException ex){
Logj.errorLog(ex);
}
catch(Exception ex){
Logj.errorLog(ex);
}
}
提取是
public void extractFilesForFirmwareZip(String stringArchievedFile, String stringExtractingFilePath, String stringFileEncrypt) throws Exception{
try{
// Initiate ZipFile object with the path/name of the zip file.
ZipFile zipFile = new ZipFile(stringArchievedFile);
//Initiate Zip Parameters which define various properties
//UnzipParameters parameters = new UnzipParameters();
if(zipFile.isEncrypted())
zipFile.setPassword(stringFileEncrypt);
//Extracts all files to the path specified
zipFile.extractAll(stringExtractingFilePath);
}
catch(ZipException ex){
isValidArchiveFile = false;
Logj.doLog(ex.getMessage(), ex);
}
catch(Exception ex){
throw ex;
}
}
发布于 2016-09-24 08:50:38
您是否尝试过Zip4j站点中的示例:
/*
* Copyright 2010 Srikanth Reddy Lingala
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing,
* software distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package net.lingala.zip4j.examples.extract;
import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.exception.ZipException;
/**
* Demonstrates extracting all files from a zip file
*
* @author Srikanth Reddy Lingala
*
*/
public class ExtractAllFiles {
public ExtractAllFiles() {
try {
// Initiate ZipFile object with the path/name of the zip file.
ZipFile zipFile = new ZipFile("c:\\ZipTest\\ExtractAllFiles.zip");
// Extracts all files to the path specified
zipFile.extractAll("c:\\ZipTest");
} catch (ZipException e) {
e.printStackTrace();
}
}
/**
* @param args
*/
public static void main(String[] args) {
new ExtractAllFiles();
}
}
https://stackoverflow.com/questions/39673776
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