JSP文件中的Lambda表达式不会编译
我尝试过在堆栈溢出中提到的大多数建议，但还没有找到解决方案。我遇到的错误如下。
An error occurred at line: 379 in the jsp file: /application-new-project_process.jsp
Lambda expressions are allowed only at source level 1.8 or above 我正在使用IntelliJ IDEA 2016.2并应用了这些设置。
Project Structure→Project，Project SDK to 1.8 (java version "1.8.0_102")
Project Structure→Project，Project Language Level to 8.0 - Lambdas, type annotations etc.
Settings→Build, Execution, Deployment→Compiler→Java Compiler，Project bytecode version to 1.8
Settings→Build, Execution, Deployment→Compiler→Java Compiler，Target bytecode version to 1.8
我使用的是Tomcatv8.0.36，并为JSP提供了以下内容。
<servlet>
<servlet-name>jsp</servlet-name>
<servlet-class>org.apache.jasper.servlet.JspServlet</servlet-class>
<init-param>
<param-name>fork</param-name>
<param-value>false</param-value>
</init-param>
<init-param>
<param-name>xpoweredBy</param-name>
<param-value>false</param-value>
</init-param>
<init-param>
<param-name>compiler</param-name>
<param-value>modern</param-value>
</init-param>
<init-param>
<param-name>compilerSourceVM</param-name>
<param-value>1.8</param-value>
</init-param>
<init-param>
<param-name>compilerTargetVM</param-name>
<param-value>1.8</param-value>
</init-param>
<init-param>
<param-name>suppressSmap</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>3</load-on-startup>
</servlet>如有任何建议，将不胜感激！
回答 1
Stack Overflow用户
发布于 2017-12-05 21:35:56
使用Spring和Tomcat的用户的最新答案。由于Spring /MVC中没有Tomcat的XML文件，所以我调整了从这些春天的医生链接的代码，以便在我的基本应用程序类中创建一个定制bean。修复在IntelliJ和Gradle CLI中使用JSP中的Java8语法所引起的问题。
如果使用Spring1.x，则添加EmbeddedServletContainerCustomizer bean：
@Bean
public EmbeddedServletContainerCustomizer containerCustomizer() {
return (ConfigurableEmbeddedServletContainer container) -> {
TomcatEmbeddedServletContainerFactory tomcat = (TomcatEmbeddedServletContainerFactory) container;
JspServlet servlet = tomcat.getJspServlet();
Map<String, String> jspServletInitParams = servlet.getInitParameters();
jspServletInitParams.put("compilerSourceVM", "1.8");
jspServletInitParams.put("compilerTargetVM", "1.8");
servlet.setInitParameters(jspServletInitParams);
};
}如果使用Spring2.x，则添加WebServerFactoryCustomizer bean：
@Bean
public WebServerFactoryCustomizer containerCustomizer() {
return (WebServerFactoryCustomizer<TomcatServletWebServerFactory>) factory -> {
Map<String, String> jspServletInitParams = factory.getInitParameters();
jspServletInitParams.put("compilerSourceVM", "1.8");
jspServletInitParams.put("compilerTargetVM", "1.8");
factory.getJsp().setInitParameters(jspServletInitParams);
};
}https://stackoverflow.com/questions/40035001
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