blocks|key|4595910|text|我不知道为什么会发生这种情况，但对于任何有我同样问题的未来男性来说，这是我的解决办法，我正在努力解决这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4595911|基本思想是让键盘出现，然后按下我需要的每一个键来构建我的字符串。|4595912|func+testPlayground()+{

++++let+app+=+XCUIApplication()
++++waitAndTap(app.textFields["MyTextField"])
++++type(app,+text:+"hej")

}

func+waitAndTap(elm:+XCUIElement){
++++let+exists+=+NSPredicate(format:+"exists+==+true")
++++expectationForPredicate(exists,+evaluatedWithObject:+elm,+handler:+nil)
++++waitForExpectationsWithTimeout(10.0,+handler:+nil)
++++elm.tap()
}


func+type(app:+XCUIApplication,+text+:+String){
++++//Wait+for+the+keyboard+to+appear.
++++let+k+=+app.keyboards;
++++waitForContent(k,+time:+10.0)

++++//Capitalize+the+string.
++++var+s+=+text.lowercaseString;
++++s.replaceRange(s.startIndex...s.startIndex,+with:+String(s[s.startIndex]).capitalizedString)

++++//For+each+char+I+type+the+corrispondant+key.
++++var+key:+XCUIElement;

++++for+i+in+s.characters+{
++++++++if+"0"..."9"+~=+i+%7C%7C++"a"..."z"+~=+i+%7C%7C+"A"..."Z"+~=+i+{
++++++++++++//+Then+it's+alphanumeric!
++++++++++++key+=+app.keys[String(i)];
++++++++}
++++++++else+{
++++++++++++//+Then+is+special+character+and+is+necessary+re-map+them.
++++++++++++switch+i+{
++++++++++++case+"\n":
++++++++++++++++key+=+app.keys["Next:"];+//+This+is+to+generalize+A+LOT.
++++++++++++default:
++++++++++++++++key+=+app.keys["space"];
++++++++++++}

++++++++}

++++++++waitAndTap(key);
++++}|code-block|syntax|javascript|4595913|因此：waitAndTap()是我在测试中经常使用的函数。它等待一个元素的存在并点击它。如果十秒内它没有出现，那就考试不及格。|offset|length|style|CODE|4595914|testPlayground()点击我想要写入的文本字段，然后调用type()|4595915|type()是核心。基本上，查看字符串中的每个字符并点击它。问题：|4595916|如果我在没有激活shift的键盘中查找字符H，就永远找不到大写字母。我的解决方案是将字符串大写，但它只在特定情况下起作用。这是可以增强的|ordered-list-item|4595917|它不适用于特殊字符，在那里您无法准确地查找它，而是查找键的名称("space“而不是”")。好吧，这里没有解决办法，除了那个可怕的开关箱，但是，好吧，我需要做的事情起作用了。|4595918|希望这能帮到别人！|4595919|entityMap^0|0|0|0|3|C|0|0|G|X|6|0|0|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|12|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|13|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|14|8|@$K|15|L|16|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|17|8|@$K|18|L|19|M|N]|$K|1A|L|1B|M|N]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1C|8|@$K|1D|L|1E|M|N]]|9|@]|A|$]]|$1|S|3|T|5|U|7|1F|8|@]|9|@]|A|$]]|$1|V|3|W|5|U|7|1G|8|@]|9|@]|A|$]]|$1|X|3|Y|5|6|7|1H|8|@]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]]|10|$]]

I don't have an answer on why this is happening, but for any future guy that has my same problem here is my workaround, on which I'm working on.

Basic idea is to make the keyboard appear, and then hit every single key I need to build my string.

<pre><code>func testPlayground() {

 let app = XCUIApplication()
 waitAndTap(app.textFields["MyTextField"])
 type(app, text: "hej")

}

func waitAndTap(elm: XCUIElement){
 let exists = NSPredicate(format: "exists == true")
 expectationForPredicate(exists, evaluatedWithObject: elm, handler: nil)
 waitForExpectationsWithTimeout(10.0, handler: nil)
 elm.tap()
}


func type(app: XCUIApplication, text : String){
 //Wait for the keyboard to appear.
 let k = app.keyboards;
 waitForContent(k, time: 10.0)

 //Capitalize the string.
 var s = text.lowercaseString;
 s.replaceRange(s.startIndex...s.startIndex, with: String(s[s.startIndex]).capitalizedString)

 //For each char I type the corrispondant key.
 var key: XCUIElement;

 for i in s.characters {
 if "0"..."9" ~= i || "a"..."z" ~= i || "A"..."Z" ~= i {
 // Then it's alphanumeric!
 key = app.keys[String(i)];
 }
 else {
 // Then is special character and is necessary re-map them.
 switch i {
 case "\n":
 key = app.keys["Next:"]; // This is to generalize A LOT.
 default:
 key = app.keys["space"];
 }

 }

 waitAndTap(key);
 }
</code></pre>

So: <code>waitAndTap()</code> is a function that I use A LOT in my tests. It waits for the existence of an element and it taps it. If in ten seconds it doesn't show up, fail the test.

<code>testPlayground()</code> taps the textfield in which I wanna write and then calls <code>type()</code>

<code>type()</code> is the core. Basically, look at every single character in the string and tap it. Problems:

<ol>
<li>If I look for character H in a keyboard where shift is not activated it will never find an uppercase letter. My solution is to capitalize the string, but it works only in specific cases. This is enhanceable</li>
<li>It doesn't work with special characters, where you cannot look for it exactly, but for the key´s name ("space" instead of " "). Well, no solution here, aside that horrible switch-case, but well, for what I need to do it works.</li>
</ol>

Hope this can help someone!

blocks|key|4595936|text|此方法允许您输入大写和小写字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4595937|func+enterUsername(username:+String?)+{
++++++++guard
++++++++++++let+input+=+username,
++++++++++++var+previousCharaterIsLowerCase+=+input.first?.isUppercase+else+{
++++++++++++++++XCTFail("Username+is+not+set")
++++++++++++++++return
++++++++}

++++++++for+char+in+input+{
++++++++++++if+char.isUppercase+&&+previousCharaterIsLowerCase+{
++++++++++++++++//+Switch+on+capslock
++++++++++++++++app.buttons["shift"].tap()
++++++++++++++++app.buttons["shift"].tap()
++++++++++++}
++++++++++++if+char.isLowercase+&&+previousCharaterIsLowerCase+==+false+{
++++++++++++++++//+Switch+off+capslock
++++++++++++++++app.buttons["shift"].tap()
++++++++++++++++app.buttons["shift"].tap()
++++++++++++++++app.buttons["shift"].tap()
++++++++++++}
++++++++++++previousCharaterIsLowerCase+=+char.isLowercase
++++++++++++app.keys[String(char)].tap()
++++++++}
++++}|code-block|syntax|javascript|4595938|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This method allows you to enter Uppercase and Lowercase strings

<pre><code>func enterUsername(username: String?) {
 guard
 let input = username,
 var previousCharaterIsLowerCase = input.first?.isUppercase else {
 XCTFail("Username is not set")
 return
 }

 for char in input {
 if char.isUppercase &amp;&amp; previousCharaterIsLowerCase {
 // Switch on capslock
 app.buttons["shift"].tap()
 app.buttons["shift"].tap()
 }
 if char.isLowercase &amp;&amp; previousCharaterIsLowerCase == false {
 // Switch off capslock
 app.buttons["shift"].tap()
 app.buttons["shift"].tap()
 app.buttons["shift"].tap()
 }
 previousCharaterIsLowerCase = char.isLowercase
 app.keys[String(char)].tap()
 }
 }
</code></pre>

blocks|key|2510545|text|首先，尝试禁用I/O+->硬件键盘，看看会发生什么。如果仍然不起作用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2510546|而不是|2510547|searchField.tap()
searchField.typeText("Holy+Grail")|code-block|syntax|javascript|2510548|尝尝这个|2510549|++++++++++++app.keys["H"].tap()
++++++++++++app.keys["o"].tap()
++++++++++++app.keys["l"].tap()
++++++++++++app.keys["y"].tap()|2510550|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

First try to disable I/O -> Hardware Keyboard and see what will happen.
If still not working

instead of

<pre><code>searchField.tap()
searchField.typeText("Holy Grail")
</code></pre>

try this

<pre><code> app.keys["H"].tap()
 app.keys["o"].tap()
 app.keys["l"].tap()
 app.keys["y"].tap()
</code></pre>

I'm trying to make a simple UI Test in my iOS Application. I'd like to fill a <code>textfield</code> with some text but an error always appears.

First try:

<pre><code>let searchField = app.textFields.elementBoundByIndex(0);
searchField.tap()
searchField.typeText("Holy Grail")
</code></pre>

The field is highlighted, the keyboard appears and, after some seconds, randomly one of these:

<pre><code>- Timed out waiting for IDE barrier message to complete
- failed to get attributes within 15.0s ui test
- failed to get snaphots within 15.0s ui test
</code></pre>

Second try:

<pre><code>func setText(text: String, application: XCUIApplication) {
 //Instead of typing the text, it pastes the given text.
 UIPasteboard.generalPasteboard().string = text
 doubleTap()
 application.menuItems["Paste"].tap()
}

...

let searchField = app.textFields.elementBoundByIndex(0);
searchField.tap()
searchField.setText("Holy Grail")
</code></pre>

Same result.
Tried with <code>Connect Hardware Keyboard</code> on and off.
Tried with iPhone 6s simulator, iPad Retina simulator, iPad 2 simulator.
Tried only with Xcode 7 (8 will break the project)

Ideas? Thanks in advance!

Fill TextField in UI Test Fails

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图在我的iOS应用程序中做一个简单的UI测试。我想用一些文本填充textfield，但是总是会出现错误。第一次尝试：let searchField = app.textFields.elementBoundByIndex(0);searchField.tap()searchField.typeText("Holy ...

问在UI测试中填充TextField失败
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