在游戏中添加经过时间的时钟(Java)
在游戏中添加经过时间的时钟(Java)
提问于 2016-11-14 21:38:23
我正在开发一个游戏/模拟器，我需要一个计时器来显示游戏开始后经过的时间。
我使用一个"SimpleWindow“类作为窗口，称为SimulationWindow，用于显示仿真的可视化。main类(名为Simulate)执行大部分计算。
我希望时钟显示在SimulationWindow中，而不是在主类中。我的意思是我不想使用System.out.println在主类模拟中显示结果(我知道怎么做)，但是结果需要在SimulationWindow中每秒钟自动更新。
我试图在SimulationWindow类中创建一个函数，但无法让它工作。它需要开始计数，一旦SimulationeWindow打开(当游戏开始)。
来自主类的代码，模拟类：
import java.util.ArrayList;
import java.util.Random;
public class Simulate {
public static void main(String[] args)
throws InterruptedException {
SimulationWindow w = new SimulationWindow();
Random rand = new Random();
ArrayList<Player> player = new ArrayList<Player>();
ArrayList<Player> hPlaying= new ArrayList<Player>();
// long startTime = System.nanoTime();
int gameOn = 1;
// Adds all players to the game before it starts.
for (int i = 1; i < 11; i++) {
int randNbr = rand.nextInt(3);
if (randNbr == 0) {
player.add(new BlueM(w, i, randNbr));
} else if (randNbr == 1) {
player.add(new RedM(w, i, randNbr));
} else if (randNbr == 2) {
player.add(new BlueS(w, i));
} else if (randNbr == 3) {
player.add(new RedS(w, i));
} else if (randNbr == 4) {
player.add(new BlueJ(w, i,
1 + rand.nextInt(5)));
} else if (randNbr == 5) {
player.add(new RedJ(w, i,
1 + rand.nextInt(5)));
} else if (randNbr == 6) {
player.add(new BlueA(w, i,
rand.nextInt(50)));
} else if (randNbr == 7) {
player.add(new RedA(w, i,
1 + rand.nextInt(5)));
} else if (randNbr == 8) {
player.add(new BlueT(w, i,
1 + rand.nextInt(5)));
} else if (randNbr == 9) {
player.add(new RedT(w, i,
rand.nextInt(50)));
}
}
// Makes all players alive.
for (Player h : player) {
hPlaying.add(h);
}
// Starts the game.
while (gameOn > 0) {
long startTime = System.nanoTime();
for (Player h : player) {
// If the player is alive, continue
if (hPlaying.contains(h)) {
h.Step();
}
}
SimulationWindow.delay(10);
long currentTime = System.nanoTime() - startTime;
SimulationWindow.timer(currentTime);
}
// long currentTime = System.nanoTime() - startTime;
}}
但是我不知道如何将主类中的currentTime发送到SimulationWindow中的函数，该函数应该返回时间，这样就可以在这个SimulationWindow中显示它，并且每秒钟更新一次(或者每次玩家迈出一步，这都不重要)。
这就是我在SimulationWindow中所拥有的；
import se.lth.cs.pt.window.SimpleWindow;
public class SimulationWindow extends SimpleWindow {
public static final int X_START_POS_BLUE = 790;
public static final int X_END_POS_BLUE = 10;
public static final int Y_LINE_START_BLUE = 10;
public static final int Y_LINE_END_BLUE = 790;
public static final int X_START_POS_RED = 10;
public static final int X_END_POS_RED = 790;
public static final int Y_LINE_START_RED = 790;
public static final int Y_LINE_END_RED = 10;
public SimulationWindow() {
super(800, 690, "game x");
setUp();
}
private void setUp() {
super.moveTo(X_START_POS_BLUE - 2,
Y_LINE_START_BLUE + 2);
super.writeText("1");
super.moveTo(X_START_POS_RED - 2,
Y_LINE_START_RED + 2);
super.writeText("2");
super.moveTo(X_START_POS_BLUE - 2,
Y_LINE_START_BLUE + 0);
super.writeText("3");
super.moveTo(X_START_POS_RED - 2,
Y_LINE_START_RED + 0);
super.writeText("4");
super.moveTo(X_START_POS_BLUE - 0,
Y_LINE_START_BLUE + 2);
super.writeText("5");
super.moveTo(X_START_POS_RED - 0,
Y_LINE_START_RED + 2);
super.writeText("6");
super.moveTo(X_START_POS_BLUE - 0,
Y_LINE_START_BLUE + 4);
super.writeText("7");
super.moveTo(X_START_POS_RED - 0,
Y_LINE_START_RED + 4);
super.writeText("8");
super.moveTo(X_START_POS_BLUE - 4,
Y_LINE_START_BLUE + 0);
super.writeText("9");
super.moveTo(X_START_POS_RED - 4,
Y_LINE_START_RED + 0);
super.writeText("10");
super.moveTo(395, 780);
super.println("Time passed: "+ timer())
}
public static int getStartXPos(int startNbr) {
if (startNbr == 1 || startNbr == 3 || startNbr == 5
|| startNbr == 7 || startNbr == 9) {
return X_START_POS_BLUE;
} else {
return X_START_POS_RED;
}
}
public static int getStartYPos(int startNbr) {
if (startNbr == 1 || startNbr == 3 || startNbr == 5
|| startNbr == 7 || startNbr == 9) {
return Y_LINE_START_BLUE + startNbr * 20;
} else {
return Y_LINE_START_RED + startNbr * 20;
}
}
public static long timer(long time) {
return time;
}}
在SimulationWindow类中，这是我无法工作的代码：
super.writeText("Time passed: "+ timer())感谢你的帮助！
回答 1
Stack Overflow用户
发布于 2016-11-14 22:21:22
正如我的注释中所给出的，您可以使timer()方法static，然后将其称为SimulationWindow.timer(currentTime);
静态定时器方法：
public static long timer(long time); {
return time;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/40598261
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