最近,我使用if- use语句在CodeWars中完成了一个问题,但是我想重试它并使用一个开关语句。可惜它没有像我想的那样工作!
我要解决的问题是,一名铁人三项运动员已经完成并返回了一个物体,根据运动员是否应该游泳、骑自行车或跑步的长度值来显示关键。
我的如果-其他解决方案:
function iTri(s) {
var triLength = 140.60;
var result = {};
var str = ' to go!';
var lengthLeft = (triLength - s).toFixed(2);
if (s === 0) {
return 'Starting Line... Good Luck!';
} else if (s <= 2.4) {
result.Swim = lengthLeft + str;
} else if (s <= 114.4) {
result.Bike = lengthLeft + str;
} else if (s < 130.60) {
result.Run = lengthLeft + str;
} else if (s < 140.60) {
result.Run = 'Nearly there!';
} else {
return 'You\'re done! Stop running!';
}
return result;
}(不工作)开关语句:
function iTri(s){
let tri = (2.4 + 112 + 26.2).toFixed(2);
let left = tri - s;
let str = ' to go!'
let result = {};
switch(s) {
case (s === 0):
return "Starting Line... Good Luck!";
break;
case (s <= 2.4):
result.Swim = left + str;
return result;
break;
case (s <= 114.4):
result.Bike = left + str;
return result;
break;
case (s <= 130.60):
result.Run = left + str;
return result;
break;
case (s < 140.60):
result.Run = 'Nearly there!';
return result;
break;
default:
return 'You\'re done! Stop running!';
}
}这些都是测试:
Test.describe("Example tests",_=>{
Test.assertSimilar(iTri(36),{'Bike':'104.60 to go!'});
Test.assertSimilar(iTri(103.5),{'Bike':'37.10 to go!'});
Test.assertSimilar(iTri(2),{'Swim':'138.60 to go!'});
});以及产出:
✘ Expected: '{ Bike: \'104.60 to go!\' }', instead got: '\'You\\\'re done! Stop running!\''
✘ Expected: '{ Bike: \'37.10 to go!\' }', instead got: '\'You\\\'re done! Stop running!\''
✘ Expected: '{ Swim: \'138.60 to go!\' }', instead got: '\'You\\\'re done! Stop running!\'' 另外,将其转换为switch语句值得吗?这样做有什么好处/缺点,就像/else.开关?
发布于 2016-11-28 17:47:37
是否值得尝试将其转换为switch语句?
不是的。只有在有多个精确匹配的情况下,switch才会有用。对你来说不是这样。
发布于 2016-11-28 18:45:59
如果稍微将问题转过来,那么您可以像这样使用开关。您的交换机已经非常接近于此了。
function iTri(s) {
var triLength = 140.60;
var result = {};
var str = ' to go!';
var lengthLeft = (triLength - s).toFixed(2);
switch(true) {
case s === 0:
return 'Starting Line... Good Luck!';
case s <= 2.4:
result.Swim = lengthLeft + str;
break;
case s <= 114.4:
result.Bike = lengthLeft + str;
break;
case s < 130.60:
result.Run = lengthLeft + str;
break;
case s < 140.60:
result.Run = 'Nearly there!';
break;
default:
return 'You\'re done! Stop running!';
}
return result;
}
console.log(iTri(0));
console.log(iTri(2));
console.log(iTri(50));
console.log(iTri(120));
console.log(iTri(135));
console.log(iTri(145));
https://stackoverflow.com/questions/40850229
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