问Python:在不运行的if语句中打印

EN

#bullets is the variable for pistol ammo. During my testing of this function, it is at 5 when it should start
bullets=5

owned_items=[]
ronald_items=["a glass bottle", "a pistol", "a torch", "a small glass of      oil", "a box of matches", "a can of spray paint", "a small knife", "a pair of      surgical gloves", "a blessed amulet"]
owned_items.append(random.choice(ronald_items))
ronald_items.remove(owned_items[0]
owned_items.append(random.choice(ronald_items))
ronald_items.remove(owned_items[1])


#This part is in the actual definition where the problem appears when it should run
def skeleton_choice():
    if "a glass bottle" in owned_items:
        print('type "glass bottle" to attack the skeletons with that bottle')
    if "a pistol" in owned_items and bullets>1:
        print('type "shoot" to try firing your pistol at the skeletons')
    if "a small knife" in owned_items:
        print('type "small knife" to use your small knife against the skeletons')
    if "a kitchen knife" in owned_items:
        print('Type "kitchen knife" to use your kitchen knife against the skeletons')
    if "a blessed amulet" in owned_items:
        print('Type "amulet" to use the blessed amulet to make this a fairer fight')
    print('Type "hands" to just fight the skeletons with your body')
    print('Type "run" to try and get away from the skeletons')