blocks|key|1139387|text|与jq：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1139388|$+jq+-nR+'[inputs+%7C+split("+")+%7C+{"From":+.[0],+"To":+.[1]}]'+<<EOF
foo+bar
what+ever
EOF

[
++{
++++"From":+"foo",
++++"To":+"bar"
++},
++{
++++"From":+"what",
++++"To":+"ever"
++}
]|code-block|syntax|javascript|1139389|-n告诉jq不要读取任何输入；-R是用于原始输入的，因此它不需要JSON。|offset|length|style|CODE|1139390|输入是用inputs读取的，因此每个输入行都有一个字符串：|1139391|$+jq+-nR+'inputs'+<<EOF
foo+bar
what+ever
EOF
"foo+bar"
"what+ever"|1139392|然后，将这些词分成几个字数组：|1139393|$+jq+-nR+'inputs+%7C+split("+")'+<<EOF
foo+bar
what+ever
EOF

[
++"foo",
++"bar"
]
[
++"what",
++"ever"
]|1139394|由此，我们构造了以下对象：|1139395|$+jq+-nR+'inputs+%7C+split("+")+%7C+{"From":+.[0],+"To":+.[1]}'+<<EOF
foo+bar
what+ever
EOF

{
++"From":+"foo",
++"To":+"bar"
}
{
++"From":+"what",
++"To":+"ever"
}|1139396|最后，我们将所有内容封装在[]中，以便首先显示最后的输出。|1139397|直接拆分输入的更直观的方法失败了，因为将所有内容封装在[]中会导致每个输入行生成一个数组：|1139398|$+jq+-R+'[split("+")+%7C+{+"From":+.[0],+"To":+.[1]+}]'+<<EOF
foo+bar
what+ever
EOF

[
++{
++++"From":+"foo",
++++"To":+"bar"
++}
]
[
++{
++++"From":+"what",
++++"To":+"ever"
++}
]|1139399|因此，有些麻烦的-n/inputs。注意，inputs需要JQVersion1.5。|1139400|entityMap^0|0|0|0|2|F|2|0|4|6|0|0|0|0|0|0|D|2|0|R|2|0|0|8|2|B|6|L|6|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1A|8|@$I|1B|J|1C|K|L]|$I|1D|J|1E|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|1F|8|@$I|1G|J|1H|K|L]]|9|@]|A|$]]|$1|O|3|P|5|D|7|1I|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|1J|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|1K|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|1L|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1M|8|@]|9|@]|A|$E|F]]|$1|Y|3|Z|5|6|7|1N|8|@$I|1O|J|1P|K|L]]|9|@]|A|$]]|$1|10|3|11|5|6|7|1Q|8|@$I|1R|J|1S|K|L]]|9|@]|A|$]]|$1|12|3|13|5|D|7|1T|8|@]|9|@]|A|$E|F]]|$1|14|3|15|5|6|7|1U|8|@$I|1V|J|1W|K|L]|$I|1X|J|1Y|K|L]|$I|1Z|J|20|K|L]]|9|@]|A|$]]|$1|16|3|-4|5|6|7|21|8|@]|9|@]|A|$]]]|17|$]]

With jq:

<pre><code>$ jq -nR '[inputs | split(" ") | {"From": .[0], "To": .[1]}]' &lt;&lt;EOF
foo bar
what ever
EOF

[
 {
 "From": "foo",
 "To": "bar"
 },
 {
 "From": "what",
 "To": "ever"
 }
]
</code></pre>

<code>-n</code> tells jq to not read any input; <code>-R</code> is for raw input so it doesn't expect JSON.

The input is read with <code>inputs</code>, resulting in one string per input line:

<pre><code>$ jq -nR 'inputs' &lt;&lt;EOF
foo bar
what ever
EOF
"foo bar"
"what ever"
</code></pre>

These are then split into arrays of words:

<pre><code>$ jq -nR 'inputs | split(" ")' &lt;&lt;EOF
foo bar
what ever
EOF

[
 "foo",
 "bar"
]
[
 "what",
 "ever"
]
</code></pre>

From this, we construct the objects:

<pre><code>$ jq -nR 'inputs | split(" ") | {"From": .[0], "To": .[1]}' &lt;&lt;EOF
foo bar
what ever
EOF

{
 "From": "foo",
 "To": "bar"
}
{
 "From": "what",
 "To": "ever"
}
</code></pre>

And finally, we wrap everything in <code>[]</code> to get the final output shown first.

The more intuitive approach of splitting input directly fails because wrapping everything in <code>[]</code> results in one array per input line:

<pre><code>$ jq -R '[split(" ") | { "From": .[0], "To": .[1] }]' &lt;&lt;EOF
foo bar
what ever
EOF

[
 {
 "From": "foo",
 "To": "bar"
 }
]
[
 {
 "From": "what",
 "To": "ever"
 }
]
</code></pre>

Hence the somewhat cumbersome <code>-n</code>/<code>inputs</code>. Notice that <code>inputs</code> requires jq version 1.5.

blocks|key|660449|text|下面是一个所有jq解决方案，该解决方案假定"From“和"To”值与您的示例完全相同：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|660450|jq+-R+-n+'[inputs+%7C+split("+")+%7C+{From:+.[0],+To:+.[1]}]'|code-block|syntax|javascript|660451|您可能希望使用gsub/2处理其他空间。|offset|length|style|CODE|660452|如果您的jq没有inputs，那么您可以使用以下咒语：|660453|jq+-R+-s+'split("\n")
++%7C+map(select(length>1)+%7C+split("+")+%7C+{From:+.[0],+To:+.[1]})'|660454|或者，您可以将时间循环的输出输送到jq+-s中。|660455|entityMap^0|0|0|7|6|0|8|6|0|0|H|5|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@$I|10|J|11|K|L]]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|13|8|@$I|14|J|15|K|L]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|T|$]]

Here's an all-jq solution that assumes the "From" and "To" values are presented exactly as in your example:

<pre><code>jq -R -n '[inputs | split(" ") | {From: .[0], To: .[1]}]'
</code></pre>

You might want to handle additional spaces using <code>gsub/2</code>.

If your jq does not have <code>inputs</code> then you can use this incantation:

<pre><code>jq -R -s 'split("\n")
 | map(select(length&gt;1) | split(" ") | {From: .[0], To: .[1]})'
</code></pre>

Or you could just pipe the output from your while-loop into <code>jq -s</code>.

I have a while loop with two variables I have to merge into a single piece of JSON, like so:

<pre><code>#!/bin/bash
while read -r from to
do
 # BONUS: Solution would ideally require no quoting at this point
 echo { \"From\": \"$from\", \"To\": \"$to\" } 
done &lt;&lt; EOF
foo bar
what ever
EOF
</code></pre>

Which currently outputs invalid JSON:

<pre><code>{ "From": "foo", "To": "bar" }
{ "From": "what", "To": "ever" }
</code></pre>

What's the simplest I can create valid JSON like:

<pre><code>[
{ "From": "foo", "To": "bar" },
{ "From": "what", "To": "ever" }
]
</code></pre>

I looked at <code>jq</code> but I couldn't figure out how to do it. I'm not <a href="https://stackoverflow.com/a/30923164/4534">looking to do it in shell</a> ideally because I feel adding commas and such is a bit ugly.

Shell while loop to JSON

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个带两个变量的while循环，我必须合并成一个JSON片段，如下所示：#!/bin/bashwhile read -r from todo    # BONUS: Solution would ideally require no quoting at this point    echo { \"From\":...

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