创建将字符串解析为数组PHP的函数
创建将字符串解析为数组PHP的函数
提问于 2017-01-27 00:01:20
我想要创建一个php函数，它将一个字符串解析成一个数组(我发现这并不容易)，这些字符串变化很大，我不知道如何对下面的任何字符串正确地工作($text1，.，$textn)：
<?php
$text1 ='balance_check!en:[ussd]Your balance is $balance $currency;ru:[ussd]Vash balans $balance $currency;';
//function outputs: $text_array = array ('type'=>'ussd','en'=>'Your balance is', 'ru'=>'Vash balans');
$text2 = 'voicemail!:[redirect]*44*2*$number';
//function outputs: $text_array = array('type'=>'redirect');
$text3='callerid!en:success=[ussd]$callerid is your Caller-ID/error=[ussd]Bad caller-ID number;';
//function outputs: $text_array = array('type'=>'ussd','en'=>array('success'=>'is your Caller-ID', 'error'=>'Bad caller-ID number'));
$text4 ='voucher_recharge!en:success=[sms]Your balance is $balance $currency. Voucher recharged successfully';
//function outputs: $text_array = array('type'=>'sms','en'=>array('success'=>array('Your balance is','Voucher recharged successfully'),),);
//parse into an array
function multiexplode($text) {
//parse $text into array
// return $text_array;
}
?>回答 1
Stack Overflow用户
回答已采纳
发布于 2017-01-27 16:18:22
我不太确定，但你可以测试一下：
编辑
function transform($string) {
$string = preg_replace('/\$[a-zA-Z0-9]+/i', '', $string); // remove $words pattern
$text = end(explode('!',$string, 2)); // get part of string targeted
preg_match_all('#([a-z]{2})?\:?([a-z]+)?\=?\[([a-zA-Z]+)\]#iU', $text, $matches); // Find all parts needed to build array
$output = array();
$text = str_replace($matches[0], '#SPLITME#', $text);
$sentences = explode( '#SPLITME#', $text);
foreach ($sentences as $k => $v){
if(empty($v) || $v == '') unset($sentences[$k]);
}
$sentences = array_values($sentences);
$lang_memory = null;
foreach ($matches[1] as $key => $lang){
$output['type'] = $matches[3][0]; // get type
if(!empty($lang) ){
if(isset($matches[2][$key]) && !empty($matches[2][$key])){
// success or error key found
$output[$lang][$matches[2][$key]] = $sentences[$key];
$lang_memory = $lang;
}else{
$output[$lang] = $sentences[$key]; // no success of error key found
}
}else if($lang_memory != null){
if(isset($matches[2][$key]) && !empty($matches[2][$key])){
$output[$lang_memory][$matches[2][$key]] = $sentences[$key];
}
}
}
return $output;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/41885152
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