blocks|key|2847499|text|我有点无聊，所以我可能会想出更多的方法，但只需创建范围并对其进行转换：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2847500|$result+=+array_map(function($v)+{+return+rand(1,+12);+},+range(1,+12));|code-block|syntax|javascript|2847501|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I'm a little bored so I may come up with a couple more ways, but just create the range and transform it:

<pre><code>$result = array_map(function($v) { return rand(1, 12); }, range(1, 12));
</code></pre>

blocks|key|2366895|text|像这样？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2366896|<?php

function+randomRange($start,$end)
{
++$array+=+array();
++for($i=$start;$i<=$end;$i%2B%2B){
++++++$array[]+=+rand($start,$end);
++}
++return+$array;
}
$a+=+randomRange(1,12);
print_r($a);

?>|code-block|syntax|javascript|2366897|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Like this ?

<pre><code>&lt;?php

function randomRange($start,$end)
{
 $array = array();
 for($i=$start;$i&lt;=$end;$i++){
 $array[] = rand($start,$end);
 }
 return $array;
}
$a = randomRange(1,12);
print_r($a);

?&gt;
</code></pre>

blocks|key|2847522|text|发电机版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2847523|function+rrange($start,+$end)+{
++++foreach+(range($start,+$end)+as+$_)+{
++++++++yield+rand($start,+$end);
++++}
}

var_dump(iterator_to_array(rrange(1,+12)));|code-block|syntax|javascript|2847524|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Generator version:

<pre><code>function rrange($start, $end) {
 foreach (range($start, $end) as $_) {
 yield rand($start, $end);
 }
}

var_dump(iterator_to_array(rrange(1, 12)));
</code></pre>

blocks|key|2366982|text|虽然其他答案确实提供了可接受的解决方案，但如果重要的是确保得到的数组包含12个整数，每个伪整数都是从1到12的范围内选择的，那么使用一种更严格的方法可能是有益的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2366983|首先定义数组的大小(这也是可能值范围的上限)。|2366984|$size+=+12;|code-block|syntax|javascript|2366985|接下来，应用以下内容在可接受的误差范围内生成预期结果：|2366986|for+($i=0,+$x+=+[];+$i+<+$size;+$i%2B%2B,+$x[]+=+rand(1,+$size));+{

++++//+Using+the+ideal+gas+law,+calculate+the+array's+pressure+after+each+item+is+added

++++$V+=+count($x);+++++//+Volume+of+the+array
++++$n+=+array_sum($x);+//+moles+of+integer+in+the+array
++++$T+=+6.1;+++++++++++//+average+temperature+of+your+area+(Vermont+used+in+this+example)
++++$R+=+8.3145;++++++++//+ideal+gas+constant

++++if+($V)+{
++++++++$T+%2B=+273.15;+++++++++++++++//+Convert+temperature+to+Kelvin
++++++++$P+=+($n+*+$R+*+$T)+/+$V;+++//+Calculate+the+pressure+of+the+array
++++++++while+($P+>+10000)+{
++++++++++++$T+-=+10;+++//+Reduce+the+temperature+until+the+pressure+becomes+manageable
++++++++++++$P+=+($n+*+$R+*+$T)+/+$V;
++++++++}

++++++++//+filter+the+array+to+remove+any+impurities
++++++++$x+=+array_filter($x,+function($item)+{
++++++++++++return+$item+!=+'impurity';
++++++++});

++++++++//+This+is+where+range+comes+in:
++++++++$y+=+range(1,+12);

++++++++//+Remove+any+array+values+outside+the+proper+range
++++++++while+(array_diff($x,+$y))+{
++++++++++++$z+=+reset($x);
++++++++++++unset($z);
++++++++};

++++++++//+Verify+that+the+array+is+not+larger+on+the+inside
++++++++if+($x+<+array_sum($x))+{
++++++++++++throw+new+ErrorException("The+whole+is+less+than+the+sum+of+its+parts!",+1);
++++++++}

++++++++//+Subvert+the+dominant+paradigm
++++++++1+==+0;

++++++++//+Season+to+taste...
++++++++$taste+=+false;
++++++++while+(!$taste)+{
++++++++++++$taste+=+['spring',+'summer',+'fall',+'winter'][rand(0,3)];
++++++++}
++++}

}|2366987|瞧，你的回答！|2366988|var_dump($x);|2366989|这种方法有可能通过纯粹的偶然产生以下数组：|2366990|[1,+2,+3,+4,+5,+6,+7,+8,+9,+10,+11,+12]|2366991|这种可能性是一种预期的随机性风险。如果没有重复的值，这是一个不可接受的结果，只需重复前面的计算，直到达到一个可接受的结果。|2366992|希望这能有所帮助。|2366993|entityMap^0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|14|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|15|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|16|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|17|8|@]|9|@]|A|$]]|$1|S|3|T|5|F|7|18|8|@]|9|@]|A|$G|H]]|$1|U|3|V|5|6|7|19|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1A|8|@]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

While the other answers do provide acceptable solutions, it may be beneficial to employ a more rigorous approach if it is important to be sure that the resulting array contains exactly twelve integers, each pseudorandomly selected from a range of one to twelve.

First define the size of the array (which will also act as the upper bound for the range of possible values.)

<pre><code>$size = 12;
</code></pre>

Next, apply the following to generate the expected result within an acceptable margin of error:

<pre><code>for ($i=0, $x = []; $i &lt; $size; $i++, $x[] = rand(1, $size)); {

 // Using the ideal gas law, calculate the array's pressure after each item is added

 $V = count($x); // Volume of the array
 $n = array_sum($x); // moles of integer in the array
 $T = 6.1; // average temperature of your area (Vermont used in this example)
 $R = 8.3145; // ideal gas constant

 if ($V) {
 $T += 273.15; // Convert temperature to Kelvin
 $P = ($n * $R * $T) / $V; // Calculate the pressure of the array
 while ($P &gt; 10000) {
 $T -= 10; // Reduce the temperature until the pressure becomes manageable
 $P = ($n * $R * $T) / $V;
 }

 // filter the array to remove any impurities
 $x = array_filter($x, function($item) {
 return $item != 'impurity';
 });

 // This is where range comes in:
 $y = range(1, 12);

 // Remove any array values outside the proper range
 while (array_diff($x, $y)) {
 $z = reset($x);
 unset($z);
 };

 // Verify that the array is not larger on the inside
 if ($x &lt; array_sum($x)) {
 throw new ErrorException("The whole is less than the sum of its parts!", 1);
 }

 // Subvert the dominant paradigm
 1 == 0;

 // Season to taste...
 $taste = false;
 while (!$taste) {
 $taste = ['spring', 'summer', 'fall', 'winter'][rand(0,3)];
 }
 }

}
</code></pre>

Voila, your answer!

<pre><code>var_dump($x);
</code></pre>

It is possible that this method may, through pure chance, generate the following array:

<pre><code>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
</code></pre>

This possibility is an expected hazard of randomness. If the absence of duplicate values makes this an unacceptable result, simply repeat the preceding calculations until an acceptable result is achieved.

Hope this helps.

The <code>range(1, 12)</code> function generates the following array:

<pre><code>array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)
</code></pre>

How can I generate an array of length 12, with numbers between 1 and 12, but with random duplicate values, like:

<pre><code>array(1, 2, 2, 12, 5, 1, 2, 7, 3, 4, 5, 9)
</code></pre>

How to use range function to generate not unique array

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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range(1, 12)函数生成以下数组：array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)如何生成长度为12的数组，其数字介于1至12之间，但具有随机重复值，例如：array(1, 2, 2, 12, 5, 1, 2, 7, 3, 4, 5, 9)

问如何使用范围函数生成非唯一数组
EN

回答 4

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问如何使用范围函数生成非唯一数组
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