我正在尝试从一个dict创建一个csv,但是我收到了错误:
in create_csv
writer = csv.writer('userInfo.csv')
TypeError: argument 1 must have a "write" method代码:
#Create dict file to test
userInfoDict = {'orgID': '17', 'firstName': 'TestFirstName', 'lastName': 'TesLastName',
'emailAddress': 'test@test.com', 'phoneNumber': '123-456-7890',
'isoCountryCode': 'US'}
def create_csv(userInfoDict):
import csv
userInfo = open('userInfo.csv', 'wb')
for key in userInfoDict:
if len(userInfoDict['orgID']) == 0:
print('Not a valid user: No orgID')
return None
elif len(userInfoDict['firstName']) == 0:
print('Not a valid user: No First Name')
return None
elif len(userInfoDict['emailAddress']) == 0 or len(userInfoDict['phoneNumber']) == 0:
print('Not a valid user: No Email or Phone')
return None
else:
writer = csv.writer(userInfo, delimiter=',')
for key, value in userInfoDict.items():
writer.writerow([key], [value])
return
create_csv(userInfoDict)发布于 2017-02-28 13:07:24
您应该将文件传递给作者,而不是将文件名传递给作者:
with open('userInfo.csv', 'wb') as userInfoCsv:
writer = csv.writer(userInfoCsv)userInfoCsv或user_info_csv。userInfo = open('userInfo.csv', 'wb'),你为什么要用这一行?稍后使用with open('userInfo.csv', 'wb')打开文件csv.DictWriter
使用open('userInfo.csv','wb')作为user_info_csv: writer = csv.DictWriter(user_info_csv,字段名=‘your’,'column',‘name’,定界符=‘;’) writer.writerow(userInfoDict)带有注释更新的更新完整函数代码
def create_csv(userInfoDict):
import csv
with open('userInfo.csv', 'wb') as userInfo:
for key in userInfoDict:
if len(userInfoDict['orgID']) == 0:
print('Not a valid user: No orgID')
return None
elif len(userInfoDict['firstName']) == 0:
print('Not a valid user: No First Name')
return None
elif len(userInfoDict['emailAddress']) == 0 or len(userInfoDict['phoneNumber']) == 0:
print('Not a valid user: No Email or Phone')
return None
else:
writer = csv.DictWriter(userInfo, fieldnames=userInfoDict.keys(), delimiter=';')
# writer.writeheader() # If you want to add header
writer.writerow(userInfoDict)https://stackoverflow.com/questions/42509508
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