blocks|key|3380113|text|Matcher.match尝试将整个字符串与模式匹配，而当前模式只验证4个字符。下面是测试正则表达式的方法：|type|ordered-list-item|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3380114|-+You+can+put+`.*`+at+the+end+of+regular+expression+to+match+rest+of+the+String
-+You+can+alternatively+use+`Matcher.find`+or+`Matcher.lookingAt`+to+match+against+substring|code-block|syntax|javascript|3380115|​|unstyled|3380116|您的模式有一个错误，第二个间隔是太宽的A-z和A-Z。|3380117|entityMap^0|0|D|0|0|0|J|3|N|3|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|U|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|M|7|V|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|P|3|-4|5|M|7|11|8|@]|D|@]|E|$]]]|Q|$]]

<ol>
<li><code>Matcher.match</code> attempts to match entire String against the pattern and your current pattern validates only 4 characters. Here is what you can do to test you regular expression:

<ul>
<li>You can put <code>.*</code> at the end of regular expression to match rest of the String</li>
<li>You can alternatively use <code>Matcher.find</code> or <code>Matcher.lookingAt</code> to match against substring</li>
</ul></li>
<li>Your pattern has a typo, second interval is too wide <code>A-z</code> vs <code>A-Z</code></li>
</ol>

blocks|key|3380134|text|试试这个Regex模式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3380135|[a-zA-Z]{4}\d{6}[a-zA-Z]{6}\d{2}+|code-block|syntax|javascript|3380136|以上将验证四个字母，六个数字，六个字母，最后两个数字。|3380137|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try this Regex pattern:

<pre><code>[a-zA-Z]{4}\d{6}[a-zA-Z]{6}\d{2} 
</code></pre>

The above will validate for four letters, six numbers, six letters and finally two numbers.

blocks|key|1144842|text|在您的情况下，Regex模式应该是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1144843|[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[0-9]{2}|code-block|syntax|javascript|1144844|查找匹配很简单：|1144845|public+void+name(String+s){
++++String+pattern+=+"[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[0-9]{2}";
++++boolean+match+=+s.matches(pattern);
++++if+(match)+{
++++++++...
++++}+else+{
++++++++...
++++}
}|1144846|您可以在这里测试regex，https://regex101.com/|offset|length|1144847|编辑|style|BOLD|1144848|我使用0-9代替\d来确保只对数字进行安全匹配。更多细节可以在这里找到：Should+I+use+\d+or+[0-9]+to+match+digits+in+a+Perl+regex?|1144849|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/|1|https://stackoverflow.com/questions/890686/should-i-use-d-or-0-9-to-match-digits-in-a-perl-regex^0|0|0|0|0|E|L|0|0|0|2|0|10|1L|1|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|18|8|@]|9|@$M|19|N|1A|1|1B]]|A|$]]|$1|O|3|P|5|6|7|1C|8|@$M|1D|N|1E|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1F|8|@]|9|@$M|1G|N|1H|1|1I]]|A|$]]|$1|U|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]]]

Regex pattern in your case would be:

<pre><code>[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[0-9]{2}
</code></pre>

Find matching is simple:

<pre><code>public void name(String s){
 String pattern = "[a-zA-Z]{4}[0-9]{6}[a-zA-Z]{6}[0-9]{2}";
 boolean match = s.matches(pattern);
 if (match) {
 ...
 } else {
 ...
 }
}
</code></pre>

You can test regex from here <a href="https://regex101.com/" rel="nofollow noreferrer">https://regex101.com/</a>

Edit

I used [0-9] instead of \d to ensure the safety matching for only digits. More details can be found here: <a href="https://stackoverflow.com/questions/890686/should-i-use-d-or-0-9-to-match-digits-in-a-perl-regex">Should I use \d or [0-9] to match digits in a Perl regex?</a>

blocks|key|630240|text|package+com.stackoverflow._42635543;

import+java.util.regex.Pattern;

public+class+Main+{

++public+static+void+main(String[]+args)+{
++++Pattern+pat+=+Pattern.compile("[A-Za-z]{4}[0-9]{6}[A-Za-z]{6}[0-9]{2}");

++++if+(pat.matcher("SAVA950720HMCLZL04").matches())+{
++++++++System.out.println("match");
++++}+else+{
++++++++System.out.println("no+match");
++++}

++++if+(pat.matcher("SAVA950720HMCLZL045").matches())+{
++++++++System.out.println("match");
++++}+else+{
++++++++System.out.println("no+match");
++++}
++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|630241|产生|unstyled|630242|match
no+match|630243|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>package com.stackoverflow._42635543;

import java.util.regex.Pattern;

public class Main {

 public static void main(String[] args) {
 Pattern pat = Pattern.compile("[A-Za-z]{4}[0-9]{6}[A-Za-z]{6}[0-9]{2}");

 if (pat.matcher("SAVA950720HMCLZL04").matches()) {
 System.out.println("match");
 } else {
 System.out.println("no match");
 }

 if (pat.matcher("SAVA950720HMCLZL045").matches()) {
 System.out.println("match");
 } else {
 System.out.println("no match");
 }
 }
}
</code></pre>

produces

<pre><code>match
no match
</code></pre>

I want to validate a String in java that contains the following order: 

<blockquote>
 SAVA950720HMCLZL04
</blockquote>

That is, four letters, six numbers, six letters and finally two numbers.

I was reading about Regular Expressions but I can't understand how to implement it. 

I did this method to validate the first four letters. 

<pre><code> public void name(String s){
 Pattern pat=Pattern.compile("[a-zA-z]{4}");
 Matcher mat=pat.matcher(curp);
 if(mat.matches()){
 JOptionPane.showMessageDialog(null, "Validating");
 }else{
 JOptionPane.showMessageDialog(null, "Check your data. please", "error",JOptionPane.ERROR);
 }
 }
</code></pre>

I think that I might be wrong because I don't know how to implement it correctly, any help about what might be the correct solution to my problem?.

Specific string format in java

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想在java中验证一个字符串，该字符串包含以下顺序：SAVA950720HMCLZL04也就是说，四个字母，六个数字，六个字母，最后是两个数字。我读过关于正则表达式的文章，但是我不知道如何实现它。我做了这个方法来验证前四个字母。 public void name(String s){ Pattern pat=Patt...

问java中的特定字符串格式
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