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社区首页 >问答首页 >从进程列表中获取图标而不是文件

从进程列表中获取图标而不是文件
EN

Stack Overflow用户
提问于 2017-03-25 00:02:42
回答 3查看 2.2K关注 0票数 1

如何从处理列表中提取图标,而不是从当前的文件名中提取?到目前为止,这个工作通过打开表单对话框,他们点击一个文件,然后它添加到listView与图标。如何才能得到进程图标,并在listView中显示它们?

代码语言:javascript
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[StructLayout(LayoutKind.Sequential)]
public struct SHFILEINFO
{
    public IntPtr hIcon;
    public IntPtr iIcon;
    public uint dwAttributes;
    [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 260)]
    public string szDisplayName;
    [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 80)]
    public string szTypeName;
};

class Win32
{
    public const uint SHGFI_ICON = 0x100;
    public const uint SHGFI_LARGEICON = 0x0;    // 'Large icon
    public const uint SHGFI_SMALLICON = 0x1;    // 'Small icon

    [DllImport("shell32.dll")]
    public static extern IntPtr SHGetFileInfo(string pszPath,
                                uint dwFileAttributes,
                                ref SHFILEINFO psfi,
                                uint cbSizeFileInfo,
                                uint uFlags);
}

private int nIndex = 0;
private void materialFlatButton13_Click_1(object sender, EventArgs e)
{
    IntPtr hImgSmall;    //the handle to the system image list
    IntPtr hImgLarge;    //the handle to the system image list
    string fName;        // 'the file name to get icon from
    SHFILEINFO shinfo = new SHFILEINFO();

    OpenFileDialog openFileDialog1 = new OpenFileDialog();
    openFileDialog1.InitialDirectory = "c:\\temp\\";
    openFileDialog1.Filter = "All files (*.*)|*.*";
    openFileDialog1.FilterIndex = 2;
    openFileDialog1.RestoreDirectory = true;

    listView1.SmallImageList = imageList1;
    listView1.LargeImageList = imageList1;

    if (openFileDialog1.ShowDialog() == DialogResult.OK)
    {
        fName = openFileDialog1.FileName;
        //Use this to get the small Icon
        hImgSmall = Win32.SHGetFileInfo(fName, 0, ref shinfo,
                                       (uint)Marshal.SizeOf(shinfo),
                                        Win32.SHGFI_ICON |
                                        Win32.SHGFI_SMALLICON);

        System.Drawing.Icon myIcon =
               System.Drawing.Icon.FromHandle(shinfo.hIcon);

        imageList1.Images.Add(myIcon);

        //Add file name and icon to listview
        listView1.Items.Add(fName, nIndex++);
    }
EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2017-03-25 03:46:25

您可以在Win32_Process上使用WMI查询查找进程信息,并使用ExecutablePath查找进程的可执行路径。然后可以使用Icon.ExtractAssociatedIcon提取进程的相关图标:

示例

在表单上放置一个ImageList,并将其ColorDepth设置为Depth32Bit,将ImageSize设置为32,32。在表单上放置一个ListView,并将其LargImageList设置为在第一步中创建的imageList1

添加对System.Management.dll的引用并添加using System.Management;,并使用下面的代码填充listView1中的图标:

代码语言:javascript
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var query = "SELECT ProcessId, Name, ExecutablePath FROM Win32_Process";
using (var searcher = new ManagementObjectSearcher(query))
using (var results = searcher.Get())
{
    var processes = results.Cast<ManagementObject>().Select(x => new
    {
        ProcessId = (UInt32)x["ProcessId"],
        Name = (string)x["Name"],
        ExecutablePath = (string)x["ExecutablePath"]
    });
    foreach (var p in processes)
    {
        if (System.IO.File.Exists(p.ExecutablePath))
        {
            var icon = Icon.ExtractAssociatedIcon(p.ExecutablePath);
            var key = p.ProcessId.ToString();
            this.imageList1.Images.Add(key, icon.ToBitmap());
            this.listView1.Items.Add(p.Name, key);
        }
    }
}

那么你就会得到这样的结果:

票数 3
EN

Stack Overflow用户

发布于 2018-01-18 08:30:02

32位和64位进程的解决方案

System.Diagnostics**)** ()(只有)

这将获得主模块( exe文件)的图标。如果访问和目标进程的架构不同,它也将工作:

代码语言:javascript
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var icon = Process.GetProcessById(1234).GetIcon()

使用扩展方法:

代码语言:javascript
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public static class ProcessExtensions {
    [DllImport("Kernel32.dll")]
    private static extern uint QueryFullProcessImageName([In] IntPtr hProcess, [In] uint dwFlags, [Out] StringBuilder lpExeName, [In, Out] ref uint lpdwSize);

    public static string GetMainModuleFileName(this Process process, int buffer = 1024) {
        var fileNameBuilder = new StringBuilder(buffer);
        uint bufferLength = (uint)fileNameBuilder.Capacity + 1;
        return QueryFullProcessImageName(process.Handle, 0, fileNameBuilder, ref bufferLength) != 0 ?
            fileNameBuilder.ToString() :
            null;
    }

    public static Icon GetIcon(this Process process) {
        try {
            string mainModuleFileName = process.GetMainModuleFileName();
            return Icon.ExtractAssociatedIcon(mainModuleFileName);
        }
        catch {
            // Probably no access
            return null;
        }
    }
}
票数 2
EN

Stack Overflow用户

发布于 2017-03-25 00:07:11

见此处:C#: How to get the full path of running process?

代码语言:javascript
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foreach(var process in Process.GetProcesses()){
    string fullPath = process.MainModule.FileName;
    // do your stuff here
}

您可以将其替换到现有代码中。或者,根据你现在正在做的事情量身定制。

编辑:添加了获取进程的代码

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/43011012

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