用PHP迭代JSON
用PHP迭代JSON
提问于 2017-03-29 03:41:29
我不知道如何从下面的JSON获取以下键/值：
我需要打印出一个for循环：
“项目”，即“测试-项目-1”
“数据集”，即“dataset1”
‘权限’i.e‘角色:作者，组: test1@test.com’
{
"projects":{
"test-project-1":{
"datasets":{
"dataset1":{
"permissions":{
"role":"WRITER",
"group":"test1@test.com"
}
},
"dataset2":{
"permissions":{
"role":"READER",
"group":"test2@test.com"
}
},
"dataset3":{
"permissions":{
"role":"READER",
"group":"test3@test.com"
}
},
"dataset4":{
"permissions":{
"role":"READER",
"group":"test4@test.com"
}
},
"dataset5":{
"permissions":{
"role":"READER",
"group":"test5@test.com"
}
}
}
},
"test-project-2":{
"datasets":{
"dataset1":{
"permissions":{
"role":"WRITER",
"group":"test1@test.com"
}
},
"dataset2":{
"permissions":{
"role":"READER",
"group":"test2@test.com"
}
},
"dataset3":{
"permissions":{
"role":"READER",
"group":"test3@test.com"
}
},
"dataset4":{
"permissions":{
"role":"READER",
"group":"test4@test.com"
}
},
"dataset5":{
"permissions":{
"role":"READER",
"group":"test5@test.com"
}
}
}
}
}
}我试过了，但唯一能打印出来的就是“数组”。
像这样的事情行不通：
$new_json = {path_to_json};
$new_projects = $new_json['projects'];
foreach ($new_projects as $project) {
echo $project . "<br>";
foreach ($new_projects['datasets'] as $datasets){
echo $datasets . "<br>";
}
}回答 3
Stack Overflow用户
回答已采纳
发布于 2017-03-29 03:48:24
$json='{
"projects":{
"test-project-1":{
"datasets":{
"dataset1":{
"permissions":{
"role":"WRITER",
"group":"test1@test.com"
}
},
"dataset2":{
"permissions":{
"role":"READER",
"group":"test2@test.com"
}
},
"dataset3":{
"permissions":{
"role":"READER",
"group":"test3@test.com"
}
},
"dataset4":{
"permissions":{
"role":"READER",
"group":"test4@test.com"
}
},
"dataset5":{
"permissions":{
"role":"READER",
"group":"test5@test.com"
}
}
}
},
"test-project-2":{
"datasets":{
"dataset1":{
"permissions":{
"role":"WRITER",
"group":"test1@test.com"
}
},
"dataset2":{
"permissions":{
"role":"READER",
"group":"test2@test.com"
}
},
"dataset3":{
"permissions":{
"role":"READER",
"group":"test3@test.com"
}
},
"dataset4":{
"permissions":{
"role":"READER",
"group":"test4@test.com"
}
},
"dataset5":{
"permissions":{
"role":"READER",
"group":"test5@test.com"
}
}
}
}
}
}';
$array= json_decode($json,true);
foreach($array["projects"] as $projectName => $projects)
{
echo "Project name ".$projectName."<br/>";
foreach($projects["datasets"] as $databaseNames => $databaseData)
{
echo " Database name ".$databaseNames."<br/>";
echo " Database role ".$databaseData["permissions"]["role"]."<br/>";
echo " Database group ".$databaseData["permissions"]["group"]."<br/>";
}
}Stack Overflow用户
发布于 2017-03-29 04:03:47
格式为foreach (“数组”作为“数组中的键”)
foreach ($new_json as $new_projects) {
echo $new_projects . "<br>";
$datasets=$new_projects['datasets'];
foreach ($new_projects as $datasets){
echo $datasets . "<br>";
}
}Stack Overflow用户
发布于 2017-03-29 04:04:06
您需要使用json_decode PHP手册
$jsonArray = json_decode($jsonData, true);
foreach($jsonArray as $project){
echo $project . '<br>';
foreach($project['datasets'] as $dataset)
{
echo $dataset . '<br>';
foreach($dataset['permissions'] as $permissions)
{
echo sprintf('Role: %s, group: %s<br>', $permissions['role'], $permissions['group'];
}
}
}如果不希望json转换为数组，则需要将false作为第二个参数传递，然后返回stdClass。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/43083870
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