blocks|key|963875|text|所有Unicode表情符号及其各自的代码点都是这里。它们是1F600到1F64F，所以您可以使用类似范围的迭代器来构建它们。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|963876|entityMap|0|LINK|mutability|MUTABLE|url|http://unicode.org/charts/PDF/U1F600.pdf^0|N|2|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

All the Unicode emojis with their respective code points are <a href="http://unicode.org/charts/PDF/U1F600.pdf" rel="nofollow noreferrer">here</a>. They are 1F600 to 1F64F, so you can just build all of them with a range-like iterator.

blocks|key|688744|text|您可以使用emoji库。您可以通过检查是否包含在emoji.UNICODE_EMOJI中来检查单个代码点是否是表情符号编码点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|688745|import+emoji

def+extract_emojis(s):
++return+''.join(c+for+c+in+s+if+c+in+emoji.UNICODE_EMOJI['en'])|code-block|syntax|javascript|688746|entityMap|0|LINK|mutability|MUTABLE|url|https://pypi.python.org/pypi/emoji/^0|5|5|O|J|5|5|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

You can use the <a href="https://pypi.python.org/pypi/emoji/" rel="noreferrer"><code>emoji</code></a> library. You can check if a single codepoint is an emoji codepoint by checking if it is contained in <code>emoji.UNICODE_EMOJI</code>.
<pre><code>import emoji

def extract_emojis(s):
 return ''.join(c for c in s if c in emoji.UNICODE_EMOJI['en'])
</code></pre>

blocks|key|2401679|text|如果不想使用外部库，可以使用正则表达式和带有适当正则表达式的re.findall()查找表情：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2401680|In+[74]:+import+re
In+[75]:+re.findall(r'[%5E\w\s,]',+a_list[0])
Out[75]:+['',+'',+'',+'',+'',+'']|code-block|syntax|javascript|2401681|正则表达式r'[%5E\w\s,]'是一个否定式字符类，它与任何不是单词字符、空格或逗号的字符匹配。|2401682|正如我在注释中提到的，文本通常包含单词字符和标点符号，这些字符和标点符号将很容易通过这种方法处理，对于其他情况，您只需手动将它们添加到字符类中即可。请注意，由于您可以在字符类中指定一系列字符，您甚至可以使其更短、更灵活。|2401683|另一种解决方案是使用接受表情符号的字符类([]不含%5E)来代替不包含非表情符号字符的否定式字符类。因为有大量的emojis+具有不同的unicode值，所以只需要将范围添加到字符类中。如果您想匹配更多的表情符号，这里是一个很好的引用，包含所有标准的表情符号，并为不同的表情符号提供相应的范围http://apps.timwhitlock.info/emoji/tables/unicode。|2401684|entityMap|0|LINK|mutability|MUTABLE|url|http://apps.timwhitlock.info/emoji/tables/unicode|1^0|U|C|0|0|5|B|0|0|L|2|P|1|1P|D|0|40|1D|1|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|16|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]|$9|1F|A|1G|1|1H]]|E|$]]|$1|Q|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]|Y|$5|T|U|V|E|$W|X]]]]

If you don't want to use an external library, as a pythonic way you can simply use regular expressions and <code>re.findall()</code> with a proper regex to find the emojies:

<pre><code>In [74]: import re
In [75]: re.findall(r'[^\w\s,]', a_list[0])
Out[75]: ['', '', '', '', '', '']
</code></pre>

The regular expression <code>r'[^\w\s,]'</code> is a negated character class that matches any character that is not a word character, whitespace or comma.

As I mentioned in comment, a text is generally contain word characters and punctuation which will be easily dealt with by this approach, for other cases you can just add them to the character class manually. Note that since you can specify a range of characters in character class you can even make it shorter and more flexible.

Another solution is instead of a negated character class that excludes the non-emoji characters use a character class that accepts emojies (<code>[]</code> without <code>^</code>). Since there are a lot of emojis <a href="http://apps.timwhitlock.info/emoji/tables/unicode" rel="noreferrer">with different unicode values</a>, you just need to add the ranges to the character class. If you want to match more emojies here is a good reference contain all the standard emojies with the respective range for different emojies <a href="http://apps.timwhitlock.info/emoji/tables/unicode" rel="noreferrer">http://apps.timwhitlock.info/emoji/tables/unicode</a>:

blocks|key|688788|text|最高评价的答案并不总是有效的。例如，将找不到标志表情符号。考虑一下字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|688789|s+=+u'Hello+\U0001f1f7\U0001f1fa+hello'|code-block|syntax|javascript|688790|更好的方法是|688791|import+emoji
emojis_list+=+map(lambda+x:+''.join(x.split()),+emoji.UNICODE_EMOJI.keys())
r+=+re.compile('%7C'.join(re.escape(p)+for+p+in+emojis_list))
print('+'.join(r.findall(s)))|688792|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The top rated answer does not always work. For example flag emojis will not be found. Consider the string:

<pre><code>s = u'Hello \U0001f1f7\U0001f1fa hello'
</code></pre>

What would work better is

<pre><code>import emoji
emojis_list = map(lambda x: ''.join(x.split()), emoji.UNICODE_EMOJI.keys())
r = re.compile('|'.join(re.escape(p) for p in emojis_list))
print(' '.join(r.findall(s)))
</code></pre>

blocks|key|963017|text|要想准确地得到卷烟草的答案，最好的答案和用户594836的答案是混合的。这是在Python3.6中为我工作的代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|963018|import+emoji
import+re

test_list=['++me+así,bla+es,se++ds+']

##+Create+the+function+to+extract+the+emojis
def+extract_emojis(a_list):
++++emojis_list+=+map(lambda+x:+''.join(x.split()),+emoji.UNICODE_EMOJI.keys())
++++r+=+re.compile('%7C'.join(re.escape(p)+for+p+in+emojis_list))
++++aux=['+'.join(r.findall(s))+for+s+in+a_list]
++++return(aux)

##+Execute+the+function
extract_emojis(test_list)

##+the+output
['+++++']|code-block|syntax|javascript|963019|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The solution to get exactly what tumbleweed ask, is a mix between the top rated answer and user594836's answer. This is the code that works for me in Python 3.6. 

<pre><code>import emoji
import re

test_list=[' me así,bla es,se ds ']

## Create the function to extract the emojis
def extract_emojis(a_list):
 emojis_list = map(lambda x: ''.join(x.split()), emoji.UNICODE_EMOJI.keys())
 r = re.compile('|'.join(re.escape(p) for p in emojis_list))
 aux=[' '.join(r.findall(s)) for s in a_list]
 return(aux)

## Execute the function
extract_emojis(test_list)

## the output
[' ']
</code></pre>

blocks|key|963034|text|我认为重要的是要指出，前面的答案不适用于像‍‍‍这样的表情符号，因为它由4个表情符号组成，使用‍‍‍将返回4个不同的表情符号。同样的表情和皮肤颜色类似。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|963035|我的解决方案|963036|包括emoji和regex模块。regex模块支持识别字素簇(呈现为单个字符的Unicode码点序列)，因此我们可以像‍‍‍一样对emojis进行计数。|offset|length|style|CODE|963037|import+emoji
import+regex

def+split_count(text):

++++emoji_list+=+[]
++++data+=+regex.findall(r'\X',+text)
++++for+word+in+data:
++++++++if+any(char+in+emoji.UNICODE_EMOJI['en']+for+char+in+word):
++++++++++++emoji_list.append(word)
++++
++++return+emoji_list|code-block|syntax|javascript|963038|测试|963039|有更多的带有肤色的表情：|963040|line+=+["++me+así,+se++ds++hello+‍+emoji+hello+‍‍‍+how+are++you+today"]

counter+=+split_count(line[0])
print('+'.join(emoji+for+emoji+in+counter))|963041|产出：|963042|++++++‍+‍‍‍+++|963043|包括旗子|963044|如果您希望包括标志，就像Unicode范围将从to，所以添加：|963045|flags+=+regex.findall(u'[\U0001F1E6-\U0001F1FF]',+text)+|963046|到上面的函数和return+emoji_list+%2B+flags。|963047|有关标志的更多信息，请参见这是对“匹配区域指示字符类的python正则表达式”的回答。。|963048|用于更新的emoji版本|963049|要使用emoji+>=+v1.2.0，您必须添加一个语言说明符(如上面代码中的en+)：|963050|emoji.UNICODE_EMOJI['en']|963051|entityMap|0|LINK|mutability|MUTABLE|url|https://pypi.python.org/pypi/emoji/|1|https://pypi.python.org/pypi/regex/|2|https://stackoverflow.com/a/39108371/7252805^0|0|0|2|5|8|5|2|5|0|8|5|1|0|0|0|0|0|0|0|0|0|0|7|P|0|D|U|2|0|5|5|0|13|2|0|0^^$0|@$1|2|3|4|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1R|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|1S|8|@$F|1T|G|1U|H|I]|$F|1V|G|1W|H|I]]|9|@$F|1X|G|1Y|1|1Z]|$F|20|G|21|1|22]]|A|$]]|$1|J|3|K|5|L|7|23|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|24|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|25|8|@]|9|@]|A|$]]|$1|S|3|T|5|L|7|26|8|@]|9|@]|A|$M|N]]|$1|U|3|V|5|6|7|27|8|@]|9|@]|A|$]]|$1|W|3|X|5|L|7|28|8|@]|9|@]|A|$M|N]]|$1|Y|3|Z|5|6|7|29|8|@]|9|@]|A|$]]|$1|10|3|11|5|6|7|2A|8|@]|9|@]|A|$]]|$1|12|3|13|5|L|7|2B|8|@]|9|@]|A|$M|N]]|$1|14|3|15|5|6|7|2C|8|@$F|2D|G|2E|H|I]]|9|@]|A|$]]|$1|16|3|17|5|6|7|2F|8|@]|9|@$F|2G|G|2H|1|2I]]|A|$]]|$1|18|3|19|5|6|7|2J|8|@$F|2K|G|2L|H|I]]|9|@]|A|$]]|$1|1A|3|1B|5|6|7|2M|8|@$F|2N|G|2O|H|I]]|9|@]|A|$]]|$1|1C|3|1D|5|L|7|2P|8|@]|9|@]|A|$M|N]]|$1|1E|3|-4|5|6|7|2Q|8|@]|9|@]|A|$]]]|1F|$1G|$5|1H|1I|1J|A|$1K|1L]]|1M|$5|1H|1I|1J|A|$1K|1N]]|1O|$5|1H|1I|1J|A|$1K|1P]]]]

I think it's important to point out that the previous answers won't work with emojis like ‍‍‍ , because it consists of 4 emojis, and using <code>... in emoji.UNICODE_EMOJI</code> will return 4 different emojis. Same for emojis with skin color like .
<h3>My solution</h3>
Include the <a href="https://pypi.python.org/pypi/emoji/" rel="noreferrer"><code>emoji</code></a> and <a href="https://pypi.python.org/pypi/regex/" rel="noreferrer"><code>regex</code></a> modules. The regex module supports recognizing grapheme clusters (sequences of Unicode codepoints rendered as a single character), so we can count emojis like ‍‍‍
<pre><code>import emoji
import regex

def split_count(text):

 emoji_list = []
 data = regex.findall(r'\X', text)
 for word in data:
 if any(char in emoji.UNICODE_EMOJI['en'] for char in word):
 emoji_list.append(word)
 
 return emoji_list
</code></pre>
<h3>Testing</h3>
with more emojis with skin color:
<pre><code>line = [&quot; me así, se ds hello ‍ emoji hello ‍‍‍ how are you today&quot;]

counter = split_count(line[0])
print(' '.join(emoji for emoji in counter))
</code></pre>
output:
<pre><code> ‍ ‍‍‍ 
</code></pre>
<h3>Include flags</h3>
If you want to include flags, like the Unicode range would be from <a href="http://www.fileformat.info/info/unicode/char/1f1e6/index.htm" rel="noreferrer"></a> to <a href="http://www.fileformat.info/info/unicode/char/1f1ff/index.htm" rel="noreferrer"></a>, so add:
<pre><code>flags = regex.findall(u'[\U0001F1E6-\U0001F1FF]', text) 
</code></pre>
to the function above, and <code>return emoji_list + flags</code>.
See <a href="https://stackoverflow.com/a/39108371/7252805">this answer to &quot;A python regex that matches the regional indicator character class&quot;</a> for more information about the flags.
<h3>For newer <code>emoji</code> versions</h3>
to work with emoji &gt;= v1.2.0 you have to add a language specifier (e.g. <code>en</code> as in above code):
<pre><code>emoji.UNICODE_EMOJI['en']
</code></pre>

blocks|key|2401814|text|第1步:确保您的文本在utf-8+text.decode('utf-8')上解码。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|CODE|entityRanges|data|2401815|[str+for+str+in+decode]第2步：定位到文本中的所有表情符号，您必须按字符分隔文本字符|2401816|[c+for+c+in+allchars+if+c+in+emoji.UNICODE_EMOJI]步骤3:将所有表情符号保存在一个列表中，完整示例如下：|2401817|>>>+import+emoji
>>>+text+++++=+"++me+así,+bla+es+se++ds+"
>>>+decode+++=+text.decode('utf-8')
>>>+allchars+=+[str+for+str+in+decode]
>>>+list+++++=+[c+for+c+in+allchars+if+c+in+emoji.UNICODE_EMOJI]
>>>+print+list
[u'\U0001f914',+u'\U0001f648',+u'\U0001f60c',+u'\U0001f495',+u'\U0001f46d',+u'\U0001f459']|code-block|syntax|javascript|2401818|如果要从文本中删除|2401819|>>>+filtred++=+[str+for+str+in+decode.split()+if+not+any(i+in+str+for+i+in+list)]
>>>+clean_text+=+'+'.join(filtred)
>>>+print+clean_text
me+así,+bla+es+se+ds|2401820|entityMap^0|H|K|H|K|0|0|N|R|Q|0|N|0|0|1H|1X|7|0|1D|0|0|0|9|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|D]]|E|@]|F|$]]|$1|G|3|H|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|D]]|E|@]|F|$]]|$1|I|3|J|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|D]]|E|@]|F|$]]|$1|K|3|L|5|M|7|1E|8|@]|E|@]|F|$N|O]]|$1|P|3|Q|5|6|7|1F|8|@$9|1G|A|1H|B|C]]|E|@]|F|$]]|$1|R|3|S|5|M|7|1I|8|@]|E|@]|F|$N|O]]|$1|T|3|-4|5|6|7|1J|8|@]|E|@]|F|$]]]|U|$]]

Step 1: Make sure that your text it's decoded on utf-8 <code>text.decode('utf-8')</code> 

Step 2: Locate all emoji from your text, you must separate the text character by character <code>[str for str in decode]</code>

Step 3: Saves all emoji in a list <code>[c for c in allchars if c in emoji.UNICODE_EMOJI]</code> full example bellow:

<pre><code>&gt;&gt;&gt; import emoji
&gt;&gt;&gt; text = " me así, bla es se ds "
&gt;&gt;&gt; decode = text.decode('utf-8')
&gt;&gt;&gt; allchars = [str for str in decode]
&gt;&gt;&gt; list = [c for c in allchars if c in emoji.UNICODE_EMOJI]
&gt;&gt;&gt; print list
[u'\U0001f914', u'\U0001f648', u'\U0001f60c', u'\U0001f495', u'\U0001f46d', u'\U0001f459']
</code></pre>

if you want to remove from text

<pre><code>&gt;&gt;&gt; filtred = [str for str in decode.split() if not any(i in str for i in list)]
&gt;&gt;&gt; clean_text = ' '.join(filtred)
&gt;&gt;&gt; print clean_text
me así, bla es se ds
</code></pre>

blocks|key|2401854|text|好的--我也遇到了同样的问题，我想出了一个解决方案，它不需要您导入任何库(比如emoji或re)，它是一行代码。它将返回字符串中的所有表情符号：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2401855|def+extract_emojis(sentence):
++++return+[word+for+word+in+sentence.split()+if+str(word.encode('unicode-escape'))[2]+==+'\\'+]|code-block|syntax|javascript|2401856|这让我创造了一个轻量级的解决方案，我希望它能帮助你们所有人。实际上，我需要一个可以过滤掉字符串中的任何表情符号的符号--这与上面的代码相同，但只需做一个小改动：|2401857|def+filter_emojis(sentence):
++++++++return+[word+for+word+in+sentence.split()+if+str(word.encode('unicode-escape'))[2]+!=+'\\'+]|2401858|下面是一个实际行动的例子：|2401859|+>>>+a+=+'++me+así,+bla+es+se++ds+'
+>>>+b+=+extract_emojis(a)
+>>>+b
+['',+'',+'',+'']|2401860|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Ok - i had this same problem and I worked out a solution which doesn't require you to import any libraries (like emoji or re) and is a single line of code. It will return all the emojis in the string:
<pre><code>def extract_emojis(sentence):
 return [word for word in sentence.split() if str(word.encode('unicode-escape'))[2] == '\\' ]
</code></pre>
This allowed me to create a light-weight solution and i hope it helps you all. Actually - i needed one which would filter out any emojis in a string - and thats the same as the code above but with one minor change:
<pre><code>def filter_emojis(sentence):
 return [word for word in sentence.split() if str(word.encode('unicode-escape'))[2] != '\\' ]
</code></pre>
Here is an example of it in action:
<pre><code> &gt;&gt;&gt; a = ' me así, bla es se ds '
 &gt;&gt;&gt; b = extract_emojis(a)
 &gt;&gt;&gt; b
 ['', '', '', '']
</code></pre>

blocks|key|688929|text|from+emoji+import+*

EMOJI_SET+=+set()

#+populate+EMOJI_DICT
def+pop_emoji_dict():
++++for+emoji+in+UNICODE_EMOJI:
++++++++EMOJI_SET.add(emoji)

#+check+if+emoji
def+is_emoji(s):
++++for+letter+in+s:
++++++++if+letter+in+EMOJI_SET:
++++++++++++return+True
++++return+False|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|688930|在使用大型数据集时，这是一个更好的解决方案，因为您不必每次循环使用所有的表情符号。发现这个给我更好的结果:)|unstyled|688931|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>from emoji import *

EMOJI_SET = set()

# populate EMOJI_DICT
def pop_emoji_dict():
 for emoji in UNICODE_EMOJI:
 EMOJI_SET.add(emoji)

# check if emoji
def is_emoji(s):
 for letter in s:
 if letter in EMOJI_SET:
 return True
 return False
</code></pre>

This is a better solution when working with large datasets since you dont have to loop through all emojis each time. Found this to give me better results :)

blocks|key|963993|text|此函数需要一个字符串，因此将输入列表转换为字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|963994|a_list+=+'++me+así,+bla+es+se++ds+'

#+Import+the+necessary+modules
from+nltk.tokenize+import+regexp_tokenize

#+Tokenize+and+print+only+emoji
emoji+=+"['\U0001F300-\U0001F5FF'%7C'\U0001F600-\U0001F64F'%7C'\U0001F680-+
+\U0001F6FF'%7C'\u2600-\u26FF\u2700-\u27BF']"

print(regexp_tokenize(a_list,+emoji))+

output+:['',+'',+'',+'',+'']|code-block|syntax|javascript|963995|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This function expects a string so converting the list of input to string

<pre><code>a_list = ' me así, bla es se ds '

# Import the necessary modules
from nltk.tokenize import regexp_tokenize

# Tokenize and print only emoji
emoji = "['\U0001F300-\U0001F5FF'|'\U0001F600-\U0001F64F'|'\U0001F680- 
 \U0001F6FF'|'\u2600-\u26FF\u2700-\u27BF']"

print(regexp_tokenize(a_list, emoji)) 

output :['', '', '', '', '']
</code></pre>

blocks|key|688984|text|使用表情符号的另一种方法是使用emoji.demojize并将它们转换为表情符号的文本表示形式。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|688985|例:将转换为:grinning_face:+等等。|688986|然后查找所有:.*:模式，并在这些模式上使用emoji.emojize。|688987|#+-*-+coding:+utf-8+-*-
import+emoji
import+re

text+=+"""
Of+course,+too+many+emoji+characters+\
+like+,+#@%5E!*&#@%5E#++helps++people+read+aaaaaa+#douchebag
"""

text+=+emoji.demojize(text)
text+=+re.findall(r'(:[%5E:]*:)',+text)
list_emoji+=+[emoji.emojize(x)+for+x+in+text]
print(list_emoji)|code-block|syntax|javascript|688988|这可能是一种多余的方法，但它是如何使用emoji.emojize和emoji.demojize的一个例子。|688989|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/carpedm20/emoji/|1|https://www.webfx.com/tools/emoji-cheat-sheet/^0|F|E|2|4|0|0|6|F|M|3|1|0|6|4|M|D|0|0|J|D|X|E|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|H|3|I|5|6|7|1C|8|@$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|1H|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1I|8|@$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]|Y|$5|T|U|V|E|$W|Z]]]]

Another way to do it using <a href="https://github.com/carpedm20/emoji/" rel="nofollow noreferrer">emoji</a> is to use <code>emoji.demojize</code> and convert them into text representations of emojis.

Ex: will be converted to <code>:grinning_face:</code> <a href="https://www.webfx.com/tools/emoji-cheat-sheet/" rel="nofollow noreferrer">etc..</a>

Then find all <code>:.*:</code> patterns, and use <code>emoji.emojize</code> on those.

<pre class="lang-py prettyprint-override"><code># -*- coding: utf-8 -*-
import emoji
import re

text = """
Of course, too many emoji characters \
 like , #@^!*&amp;#@^# helps people read aaaaaa #douchebag
"""

text = emoji.demojize(text)
text = re.findall(r'(:[^:]*:)', text)
list_emoji = [emoji.emojize(x) for x in text]
print(list_emoji)

</code></pre>

This might be a redundant way but it's an example of how <code>emoji.emojize</code> and <code>emoji.demojize</code> can be used.

blocks|key|689010|text|首先，您需要安装以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|689011|conda+install+-c+conda-forge+emoji|code-block|syntax|javascript|689012|现在我们可以编写以下代码：|689013|import+emoji
import+re
text=+'++me+así,+bla+es+se++ds+'
text_de=+emoji.demojize(text)|689014|如果我们打印text_de输出是：|689015|':thinking_face:+:see-no-evil_monkey:+me+así,+bla+es+se+:relieved_face:+ds+
+:two_hearts::two_women_holding_hands::bikini:'|689016|现在我们可以用regex找到表情符号了。|689017|emojis_list_de=+re.findall(r'(:[!_\-\w]%2B:)',+text_de)
list_emoji=+[emoji.emojize(x)+for+x+in+emojis_list_de]|689018|如果我们打印lis_emoji，输出：|689019|['',+'',+'',+'',+'',+'']|689020|因此，我们可以使用连接函数：|689021|[''.join(list_emoji)]
OutPut:+['']|689022|如果要删除表情符号，可以使用以下代码：|689023|def+remove_emoji(text):
+++'''
+++remove+all+of+emojis+from+text
+++-------------------------
+++'''
+++text=++emoji.demojize(text)
+++text=+re.sub(r'(:[!_\-\w]%2B:)',+'',+text)

+++return+text|689024|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|18|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1A|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1C|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1E|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1H|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1I|8|@]|9|@]|A|$]]|$1|12|3|13|5|D|7|1J|8|@]|9|@]|A|$E|F]]|$1|14|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|15|$]]

First of all you need to install this:

<pre><code>conda install -c conda-forge emoji
</code></pre>

Now we can write the following code:

<pre><code>import emoji
import re
text= ' me así, bla es se ds '
text_de= emoji.demojize(text)
</code></pre>

If we print text_de Output is:

<pre><code>':thinking_face: :see-no-evil_monkey: me así, bla es se :relieved_face: ds 
 :two_hearts::two_women_holding_hands::bikini:'
</code></pre>

Now we can use regex to find emojis.

<pre><code>emojis_list_de= re.findall(r'(:[!_\-\w]+:)', text_de)
list_emoji= [emoji.emojize(x) for x in emojis_list_de]
</code></pre>

If we print lis_emoji, output:

<pre><code>['', '', '', '', '', '']
</code></pre>

So, we can use Join function:

<pre><code>[''.join(list_emoji)]
OutPut: ['']
</code></pre>

If you want to remove emojis you can use following code:

<pre><code>def remove_emoji(text):
 '''
 remove all of emojis from text
 -------------------------
 '''
 text= emoji.demojize(text)
 text= re.sub(r'(:[!_\-\w]+:)', '', text)

 return text
</code></pre>

blocks|key|689040|text|import+emojis
new_list+=+emojis.get('++me+así,+bla+es+se++ds+')
print(new_list)

output>>>{'',+'',+'',+'',+'',+''}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|689041|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import emojis
new_list = emojis.get(' me así, bla es se ds ')
print(new_list)

output&gt;&gt;&gt;{'', '', '', '', '', ''}
</code></pre>

blocks|key|2401987|text|下面是另一个使用emoji.get_emoji_regexp()和re的选项|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2401988|import+re
import+emoji

def+extract_emojis(text):
++++return+re.findall(emoji.get_emoji_regexp(),+text)

test_str+=+'+some++various++emojis+‍+and++flags+‍‍‍'
emojis+=+extract_emojis(test_str)|code-block|syntax|javascript|2401989|这产生了：|2401990|['',+'',+'',+'\u200d',+'',+'\u200d\u200d\u200d']|2401991|或者，查看字形星系团：|2401992|print('+'.join(emoji+for+emoji+in+emojis))|2401993|产量|2401994|+++‍++‍‍‍|2401995|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/carpedm20/emoji/blob/d60e69ab9e39f6bc882d29e224943a86184273de/emoji/core.py#L112^0|8|O|X|2|8|O|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|F|3|G|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1D|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1F|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1G|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1H|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|W|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]]]

Here's another option that uses <a href="https://github.com/carpedm20/emoji/blob/d60e69ab9e39f6bc882d29e224943a86184273de/emoji/core.py#L112" rel="nofollow noreferrer"><code>emoji.get_emoji_regexp()</code></a> and <code>re</code>:
<pre class="lang-py prettyprint-override"><code>import re
import emoji

def extract_emojis(text):
 return re.findall(emoji.get_emoji_regexp(), text)

test_str = ' some various emojis ‍ and flags ‍‍‍'
emojis = extract_emojis(test_str)
</code></pre>
This yields:
<pre class="lang-py prettyprint-override"><code>['', '', '', '\u200d', '', '\u200d\u200d\u200d']
</code></pre>
Or, to view the grapheme clusters:
<pre class="lang-py prettyprint-override"><code>print(' '.join(emoji for emoji in emojis))
</code></pre>
Yields
<pre class="lang-py prettyprint-override"><code> ‍ ‍‍‍
</code></pre>

If a library seems like overkill, try this regular expression - it works by matching the longest emojis first in a big alternation. Parses all emojis, all skin tones, and all flags. (v14.0) <a href="https://github.com/sweaver2112/Regex-combined-emojis" rel="nofollow noreferrer">more info</a>
<pre><code># coding=utf8
import re
a_list = [' me así, bla es se ds ']
ret = re.findall(r'(?:‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍||||‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍|‍❤️‍‍|‍❤️‍‍|‍❤️‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍‍|‍‍|‍❤️‍|‍❤️‍|‍❤️‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|‍‍|️‍️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍⚕️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍⚖️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍✈️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍♂️|‍♂️|‍♂️|‍♂️|‍♂️|‍♀️|‍♀️|‍♀️|‍♀️|‍♀️|‍️|️‍♂️|️‍♀️|️‍♂️|️‍♀️|️‍♂️|️‍♀️|️‍|️‍⚧️|⛹‍♂️|⛹‍♂️|⛹‍♂️|⛹‍♂️|⛹‍♂️|⛹‍♀️|⛹‍♀️|⛹‍♀️|⛹‍♀️|⛹‍♀️|‍|‍|❤️‍|❤️‍|‍♂️|‍♀️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍♀️|‍♂️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍⚕️|‍⚕️|‍⚕️|‍|‍|‍|‍|‍|‍|‍⚖️|‍⚖️|‍⚖️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍✈️|‍✈️|‍✈️|‍|‍|‍|‍|‍|‍|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍|‍|‍|‍|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍|‍|‍|‍|‍|‍|‍|‍|‍|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|⛹️‍♂️|⛹️‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍♂️|‍♀️|‍|‍|‍|‍|‍|‍❄️|‍☠️|‍⬛||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||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a_list[0])
print(ret)
#['', '', '', '', '', '']
</code></pre>

blocks|key|964069|text|建立在穆罕默德特里杰克回答，只有工作的每一个表情符号是由一个空间隔开。请参阅以下已删除此要求的修改版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|964070|def+extract_emojis(sentence):+++++
++++return+[sentence[i]+for+i+in+range(len(sentence))+if+str(sentence[i].encode('unicode-escape'))[2]+==+'\\'+]|code-block|syntax|javascript|964071|预期结果：|964072|+>>>+a+=+'++me+así,+bla+es+se++ds+'
+>>>+b+=+extract_emojis(a)
+>>>+b
+['',+'',+'',+'',+'',+'']|964073|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Building on Mohammed Terry Jack answer which only works where each emoji is separated by a space. See a modified version below which has removed this requirement:
<pre><code>def extract_emojis(sentence): 
 return [sentence[i] for i in range(len(sentence)) if str(sentence[i].encode('unicode-escape'))[2] == '\\' ]
</code></pre>
Expected result:
<pre><code> &gt;&gt;&gt; a = ' me así, bla es se ds '
 &gt;&gt;&gt; b = extract_emojis(a)
 &gt;&gt;&gt; b
 ['', '', '', '', '', '']
</code></pre>

Consider the following list:

<pre><code>a_list = [' me así, bla es se ds ']
</code></pre>

How can I extract in a new list all the emojis inside <code>a_list</code>?:

<pre><code>new_lis = [' ']
</code></pre>

I tried to use regex, but I do not have all the possible emojis encodings.

How to extract all the emojis from text?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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考虑以下清单：a_list = ['  me así, bla es se  ds ']如何在新列表中提取a_list中的所有表情符号？：new_lis = ['     ']我尝试使用regex，但我没有所有可能的表情编码。

问如何从文本中提取所有表情符号？
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问如何从文本中提取所有表情符号？EN

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问如何从文本中提取所有表情符号？
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