因此,我试图创建一个应该死锁的C++程序。使用下面的代码,我认为它应该可以工作,但不会死锁。要么我的mutex.lock()不能正常工作?我的意思是如果mu2.lock()锁定了应该解锁的关键部分,那么它就应该解锁,这意味着funcA不应该运行,或者至少要等到mu2解锁,因为它们都使用了资源rs2?为什么我不能锁定程序呢?
#include <iostream>
#include <thread>
#include <mutex>
#include <pthread.h>
#include <cstdio> // getchar
#include <thread> // this_thread, yield
#include <future> // async
#include <chrono> // seconds
#include <unistd.h>
using namespace std;
mutex mut1, mut2, mut3;
int rs1=1; int rs2 = 2; int rs3=3;
int MAX = 20;
void funcA(){
mut1.lock();
cout<<"mut1 lock for thread A\n";
for(int i=0; i<MAX; i++){
rs2 = i;
cout<<"[Aloop]rs1: "<<rs1<<" rs2: "<<rs2<<" rs3: "<<rs3<<" i:"<<i << endl;
}
rs1 = rs2;
cout<<"[A]rs1: "<<rs1<<" rs2: "<<rs2<<" rs3: "<<rs3 << endl;
mut1.unlock();
cout<<"mut1 unlock for thread A\n";
}
void funcB(){
mut2.lock();
cout<<"mut2 lock for thread B\n";
rs3 = rs1 + rs2;
cout<<"[B]rs3: "<<rs3 << " rs1: "<<rs1 << " rs2: "<<rs2 <<endl;
sleep(50);
mut2.unlock();
cout<<"mut2 unlock for thread B\n";
}
int main(){
thread tA(funcA);
thread tB(funcB);
tA.join();
tB.join();
return 0;
}
//Here is my makefile
#Makefile project 2
project2: project2.o
g++ -std=c++11 -pthread -o project2 project2.o
project2.o: project2.cpp project2.h
g++ -std=c++11 -Wall -pthread -c project2.cpp
//Below is my output线程B的mut2锁 Brs3: 3 rs1: 1 rs2: 99 线程A的mut1锁 Alooprs1: 1 rs2: 0 rs3: 3 i:0 Alooprs1: 1 rs2: 1 rs3: 3 i:1 Alooprs1: 1 rs2: 2 rs3: 3 i:2 Alooprs1: 1 rs2: 3 rs3: 3 i:3 Alooprs1: 1 rs2: 5 rs3: 3 i:5 Alooprs1: 1 rs2: 6 rs3: 3 i:6 Alooprs1: 1 rs2: 7 rs3: 3 i:7 Alooprs1: 1 rs2: 8 rs3: 3 i:8 Alooprs1: 1 rs2: 9 rs3: 3 i:9 Alooprs1: 1 rs2: 10 rs3: 3 i:10 Alooprs1: 1 rs2: 11 rs3: 3 i:11 Alooprs1: 1 rs2: 12 rs3: 3 i:12 Alooprs1: 1 rs2: 13 rs3: 3 i:13 Alooprs1: 1 rs2: 14 rs3: 3 i:14 Alooprs1: 1 rs2: 15 rs3: 3 i:15 Alooprs1: 1 rs2: 16 rs3: 3 i:16 Alooprs1: 1 rs2: 17 rs3: 3 i:17 Alooprs1: 1 rs2: 18 rs3: 3 i:18 Alooprs1: 1 rs2: 19 rs3: 3 i:19 Ars1: 19 rs2: 19 rs3: 3 线程A的mut1解锁 线程B的mut2解锁
发布于 2017-04-07 19:07:48
这两个线程试图锁定不同的互斥对象,因此它们不可能死锁。
虽然有许多不同的方式可以想象线程死锁,但是除非一个线程试图获取另一个线程持有的互斥对象,否则不可能出现带有互斥锁的死锁。(当然,其他事情也需要发生。如果发生这种情况,它只需等待其他线程释放互斥锁,而不是死锁。)
https://stackoverflow.com/questions/43285400
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