我有一个很好的查询。该查询基本上从当前日期开始检索6-8天之间的数据。在测量数据的年龄时,我想不包括周末。
如果一个记录是星期五登记的,那么周一早上就会显示它已经有4天的历史了,但它实际上只有2天的历史,因为Satuday和Sunday不应该算在内。
我试过这个,但似乎不起作用:
Select id, name, CreatedDate
from table
where
CreatedDate <= DATEADD(day, -6, GETDATE()) AND CreatedDate >= DATEADD(day, -8, GETDATE()) -- here I get data between 6-8 days old
AND ((DATEPART(dw, CreatedDate) + @@DATEFIRST) % 7) NOT IN (0, 1) -- Here im trying to exclude weekends
我做错了什么?
发布于 2017-04-10 14:34:07
您可以查看日历并尝试此查询。
// Logic is very simple.
// See calendar and try.
// If today is Monday, then Prev8workingdays will include
// 8 working days + 2 weekends = 12 days.
// Then result will be dateadd(day,-12, getdate()) = 12 days before today.
// Same logic for other days week
DECLARE @Prev8workingdays date = CASE
WHEN datepart(dw, getdate()) IN (2,3,4) THEN dateadd(day,-12, getdate())
WHEN datepart(dw, getdate()) IN (1) THEN dateadd(day,-11, getdate())
ELSE dateadd(day,-10, getdate())
END
DECLARE @Pre6WorkingDay date = CASE
WHEN datepart(dw, getdate()) IN (2) THEN dateadd(day,-10, getdate())
WHEN datepart(dw, getdate()) IN (1) THEN dateadd(day,-9, getdate())
ELSE dateadd(day,-8, getdate())
END
SELECT sd.* FROM
@SampleDate sd
WHERE sd.CreatedDate >= @Prev8workingdays AND sd.CreatedDate <= @Pre6WorkingDay
参考链路DATEADD
发布于 2017-04-10 13:32:19
你可以试试:
WHERE DATEPART(dw, date_created) NOT IN (1, 7);
发布于 2017-04-10 13:54:45
试试这个:
Select id, name, CreatedDate
from table
where CreatedDate < GETDATE()-6 and CreatedDate > GETDATE()-8 and
((DATEPART(dw, CreatedDate) + @@DATEFIRST) % 7) NOT IN (0, 1)
https://stackoverflow.com/questions/43324492
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