关于进口csv,我有三个问题:
发布于 2017-04-15 19:18:03
1)是的,您也可以在LOAD中使用SKIP:
LOAD CSV WITH HEADERS FROM "file:///dummyfile.csv" AS row
WITH row
SKIP 1
MERGE (n:Node {id: row[0]})2)如果csv列值为空,则相应的属性值也为空。如果该属性为空,则不会创建该属性。
假设以下CSV:
id,title,desc
1,title 1,desc1
2,,desc 2和以下负载CSV:
LOAD CSV WITH HEADERS FROM "https://gist.githubusercontent.com/ikwattro/ed85bfc98c9298924c154ecf3e0ab2aa/raw/54a9303c365a7698c87728d458f8de703a9c22e1/load.csv" AS row
CREATE (n:Post {id: row['id'], title: row['title'], description: row['desc']})这将产生以下情况:
╒══════════════════════════════════════════════════╕
│"n" │
╞══════════════════════════════════════════════════╡
│{"description":"desc1","id":"1","title":"title 1"}│
├──────────────────────────────────────────────────┤
│{"description":"desc 2","id":"2"} │
└──────────────────────────────────────────────────┘3)是的,Neo4j是无模式的,您不需要在具有相同标签的节点上拥有相同数量的属性
https://stackoverflow.com/questions/43429940
复制相似问题