blocks|key|1231774|text|我会使用abs，绝对值函数。它使消极的积极和积极的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1231775|number+=+abs(int(input("Type+a+value+for+n.+")))

if+number+>+1:
++++for+i+in+range(2,+number):
++++++++if+(number+%25+i)==0:
++++++++++++print("N")
++++++++++++break
++++else:
++++++++print("Y")
else:
++++for+i+in+range+(number,+-2):
++++++++if+((number)+%25+i)==0:
++++++++++++print("N")
++++++++break
++++else:
++++++++print("Y")|code-block|syntax|javascript|1231776|entityMap^0|4|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I would use the <code>abs</code>, absolute value function. It makes negatives positive and positives positive.

<pre><code>number = abs(int(input("Type a value for n. ")))

if number &gt; 1:
 for i in range(2, number):
 if (number % i)==0:
 print("N")
 break
 else:
 print("Y")
else:
 for i in range (number, -2):
 if ((number) % i)==0:
 print("N")
 break
 else:
 print("Y")
</code></pre>

blocks|key|2944985|text|所有素数都是自然数，也就是大于0的整数。因此，没有负数是素数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2944986|一些资料来源：|2944987|链接|offset|length|2944988|数|2944989|entityMap|0|LINK|mutability|MUTABLE|url|https://web.archive.org/web/20171219043027/http://mathforum.org/library/drmath/view/55940.html|1|https://en.wikipedia.org/wiki/Prime_number^0|0|0|0|2|0|0|0|1|1|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|U|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|V|8|@]|9|@$F|W|G|X|1|Y]]|A|$]]|$1|H|3|I|5|6|7|Z|8|@]|9|@$F|10|G|11|1|12]]|A|$]]|$1|J|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q]]|R|$5|M|N|O|A|$P|S]]]]

All prime numbers are natural numbers, that is to say, integers greater than 0. Therefore, no negative number is prime.
Some sources:
<a href="https://web.archive.org/web/20171219043027/http://mathforum.org/library/drmath/view/55940.html" rel="nofollow noreferrer">Link</a>
<a href="https://en.wikipedia.org/wiki/Prime_number" rel="nofollow noreferrer">https://en.wikipedia.org/wiki/Prime_number</a>

blocks|key|1231833|text|这是因为python中的范围/间隔是部分封闭的；它们是在右边打开的。所以当你这么做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1231834|[i+for+i+in+range(2,10)]|code-block|syntax|javascript|1231835|你会得到|1231836|2，3，4，5，6，7，8，9|blockquote|1231837|注意，2在那里，但10不在|1231838|类似的|1231839|[i+for+i+in+range(-10,-2)]|1231840|将包括-10，(因此数字%25i+==0为真)，但不包括-2。|1231841|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|X|8|@]|9|@]|A|$]]|$1|I|3|J|5|K|7|Y|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|Z|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|10|8|@]|9|@]|A|$]]|$1|P|3|Q|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|R|3|S|5|6|7|12|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|U|$]]

it's because ranges/intervals in python are partially closed; they are open on the right. So when you do

<pre><code>[i for i in range(2,10)]
</code></pre>

you get

<blockquote>
 [2, 3, 4, 5, 6, 7, 8, 9]
</blockquote>

notice, 2 is there, but 10 isn't

similarly

<pre><code>[i for i in range(-10,-2)]
</code></pre>

will include -10, (thus number%i ==0 will be true) but not -2

I've writed this code for to tell if a number is prime (Y) or not (N).

<pre><code>number = int(input("Type a value for n. "))

if number &gt; 1:
 for i in range(2, number):
 if (number % i)==0:
 print("N")
 break
 else:
 print("Y")
else:
 for i in range (number, -2):
 if ((number) % i)==0:
 print("N")
 break
 else:
 print("Y")
</code></pre>

And it is working. But when i put a number less than 1 ( number &lt; 1), like -7, the code give me an wrong answer.

I already made some changes and realized that :

<pre><code>number = int(input("Type a value for n. "))


if number &gt; 1:
 for i in range(2, number):
 if (number % i)==0:
 print("N")
 break
 else:
 print("Y")
else: 
 for i in range (number,-2):
 if (number % i)==0:
 print("N")
 break

 else:
 print("Y")*
</code></pre>

But when I put: -7, the answer is N (wrong). -7 is a prime number

Can someone help me ?

Prime N | Negative numbers don't work

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我编写了这个代码来判断一个数字是否是素数(Y)或非(N)。number = int(input("Type a value for n. "))if number > 1:    for i in range(2, number):        if (number % i)==0:            print...

问素数N个负数不起作用
EN

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问素数N个负数不起作用EN