创建Swift类来发出Http请求
创建Swift类来发出Http请求
提问于 2017-05-22 21:07:36
我在下面创建了这个类，以帮助从我的应用程序中的任何地方发出http请求，但是当我调用该类时，它不会像预期的那样发出请求。我看到我可以从函数中打印，所以我知道它至少有那么远。我还需要什么才能提出这个要求？api参数也被正确传递。
在viewController中：
let url = "post/test"
MakeHttpRequest.sharedInstance.postRequest(api: url)在课堂上：
import Foundation
final class MakeHttpRequest {
static let sharedInstance = MakeHttpRequest()
var api_token = "token_here"
var url_base = "https://test.frb.io/"
func postRequest (api : String) {
let parameters = ["email": "testing123@gmail.com"]
guard let destination = URL(string: url_base + api) else { return }
var request = URLRequest(url: destination)
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
// request.setValue("clientIDhere", forHTTPHeaderField: "Authorization")
guard let httpBody = try? JSONSerialization.data(withJSONObject: parameters, options: [])
else { return }
request.httpBody = httpBody
let session = URLSession.shared
session.dataTask(with: request) { (data, response, error) in
if let data = data {
do {
let json = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
if (json["response"]) != nil {
}
} catch {
print(error)
}
}
}.resume()
print(url_base + api)
}
private init() {
}
}回答 1
Stack Overflow用户
回答已采纳
发布于 2017-05-22 21:49:52
所以有两件事要检查。有时快速功能链不能正常工作。因此，尝试将session.dataTask拆分并恢复为两个语句。第二，尝试将错误处理添加到响应中。你可能在不知道的情况下犯了一个错误。请参阅下面的代码示例。
import Foundation
final class MakeHttpRequest {
static let sharedInstance = MakeHttpRequest()
var api_token = "token_here"
var url_base = "https://test.frb.io/"
func postRequest (api: String, parameters: [String: Any]? = nil) {
guard let destination = URL(string: url_base + api) else { return }
var request = URLRequest(url: destination)
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
// request.setValue("clientIDhere", forHTTPHeaderField: "Authorization")
if let parameters = parameters {
guard let httpBody = try? JSONSerialization.data(withJSONObject: parameters, options: []) else { return
}
request.httpBody = httpBody
}
let session = URLSession.shared
let task = session.dataTask(with: request) { (data, response, error) in
if let data = data {
do {
let json = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject
if (json["response"]) != nil {
print("1234")
} else {
print("ABCD")
}
} catch {
print(error)
}
} else {
print(error ?? "")
}
}
task.resume()
print(url_base + api)
}
private init() {
}
}
let url = "post/test"
MakeHttpRequest.sharedInstance.postRequest(api: url)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/44122171
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