blocks|key|3695954|text|您的结果似乎是一个对象，而不是数组。因此，您需要创建一个类来存储反序列化结果，其中包含属性总计(int)和产品(数组)。然后可以通过products属性访问数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3695955|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Your result seems to be an object and not an array. So you need to create a class to store the deserialized result, with attributes total (int) and products (array). And then you can access the array by the products property.

blocks|key|3284425|text|您似乎试图将对象反序列化为数组。您需要创建一个包含内部数组的类。就像这样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3284426|using+System.Collections.Generic;
using+Newtonsoft.Json;
using+System.Diagnostics;

namespace+ConsoleApp1
{
++++class+Program
++++{
++++++++static+void+Main(string[]+args)
++++++++{
++++++++++++const+string+result+=+"{\"TOTAL\":177,\"PRODUCTS\":[{\"CODE\":\"T55-2A\",\"PRICE\":59.9500,\"NAME\":\"Arrive+In+Style\"},{\"CODE\":\"F1-231\",\"PRICE\":49.9500}]}";

++++++++++++var+deserialized+=+JsonConvert.DeserializeObject<Result>(result);

++++++++++++Debug.Assert(deserialized.Books.Count+==+2);
++++++++}
++++}

++++public+class+Result
++++{
++++++++[JsonProperty("TOTAL")]
++++++++public+int+Total+{+get;+set;+}

++++++++[JsonProperty("PRODUCTS")]
++++++++public+List<Book>+Books+{+get;+set;+}
++++}

++++public+class+Book
++++{
++++++++[JsonProperty("CODE")]
++++++++public+string+Code+{+get;+set;+}

++++++++[JsonProperty("PRICE")]
++++++++public+float+Price+{+get;+set;+}

++++++++[JsonProperty("NAME")]
++++++++public+string+Name+{+get;+set;+}
++++}
}|code-block|syntax|javascript|3284427|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You seem to be trying to deserialize an object into an array. You need to create a class that contains an array inside. Something like this:

<pre><code>using System.Collections.Generic;
using Newtonsoft.Json;
using System.Diagnostics;

namespace ConsoleApp1
{
 class Program
 {
 static void Main(string[] args)
 {
 const string result = "{\"TOTAL\":177,\"PRODUCTS\":[{\"CODE\":\"T55-2A\",\"PRICE\":59.9500,\"NAME\":\"Arrive In Style\"},{\"CODE\":\"F1-231\",\"PRICE\":49.9500}]}";

 var deserialized = JsonConvert.DeserializeObject&lt;Result&gt;(result);

 Debug.Assert(deserialized.Books.Count == 2);
 }
 }

 public class Result
 {
 [JsonProperty("TOTAL")]
 public int Total { get; set; }

 [JsonProperty("PRODUCTS")]
 public List&lt;Book&gt; Books { get; set; }
 }

 public class Book
 {
 [JsonProperty("CODE")]
 public string Code { get; set; }

 [JsonProperty("PRICE")]
 public float Price { get; set; }

 [JsonProperty("NAME")]
 public string Name { get; set; }
 }
}
</code></pre>

blocks|key|3284461|text|这个错误实际上有点令人困惑。错误的真正含义是，代码不可能知道要反序列化到哪种类型。想想看-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3284462|public+interface+I+
{
++++public+int+v+{+get;+set;}
}

public+class+A:+I+
{
++++public+int+v+{+get;+set;}
}

public+class+B:+I
{
++++public+int+v+{+get;+set;}
}|code-block|syntax|javascript|3284463|现在考虑一下这个代码块-|3284464|var+result+=+JsonConvert.DeserializeObject("{\"v\"+:+10}");|3284465|你能告诉我结果是什么吗？Interface不能被实例化。所以要么是A要么是B？结果是哪一类？A还是B？实际上，没有人不知道-编译器也是如此。|offset|length|style|CODE|3284466|这里也发生了同样的事情。-|3284467|JsonConvert.DeserializeObject<IEnumerable<Book>>(result);|3284468|您正在反序列化为IEnumerable<Book>，但是IEnumerable<Book>不是一个具体的实现。这只是一个接口，一个结果的签名，而不是结果类型本身。因此转换器无法判断要使用哪个类。这就是为什么它告诉您使用原始类型或可以创建的东西。|3284469|从它试图使用List<Book>反序列化到的错误的外观来看，但是它也不能这样做，因为提供的JSON字符串不是一个数组，它是一个对象，因此错误-|3284470|无法将当前JSON对象(例如，{“名称”：“值”})反序列化为'System.Collections.Generic.List`1BookClient.Data.Book‘类型，因为该类型需要一个JSON数组(例如，1,2,3)才能正确反序列化。要修复此错误，要么将JSON更改为JSON数组(例如，1,2,3)，要么更改反序列化类型，使之成为可以从JSON对象反序列化的普通.NET类型(例如，不像整数这样的原始类型，而不是数组或列表之类的集合类型)。还可以将JsonObjectAttribute添加到类型中，以强制它从JSON对象反序列化|blockquote|3284471|如果您正在寻找解决方案，请遵循@的答案。这是一个很好的解决你的问题。|3284472|entityMap^0|0|0|0|0|C|9|X|1|11|1|1A|1|1D|1|0|0|0|8|H|S|H|0|6|A|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|17|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|18|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|19|8|@$M|1A|N|1B|O|P]|$M|1C|N|1D|O|P]|$M|1E|N|1F|O|P]|$M|1G|N|1H|O|P]|$M|1I|N|1J|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1K|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|1L|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|1M|8|@$M|1N|N|1O|O|P]|$M|1P|N|1Q|O|P]]|9|@]|A|$]]|$1|W|3|X|5|6|7|1R|8|@$M|1S|N|1T|O|P]]|9|@]|A|$]]|$1|Y|3|Z|5|10|7|1U|8|@]|9|@]|A|$]]|$1|11|3|12|5|6|7|1V|8|@]|9|@]|A|$]]|$1|13|3|-4|5|6|7|1W|8|@]|9|@]|A|$]]]|14|$]]

The error actually is kind of confusing. The real meaning of the error is that there is no way the code knows which type to deserialize to. Consider the scenario - 

<pre><code>public interface I 
{
 public int v { get; set;}
}

public class A: I 
{
 public int v { get; set;}
}

public class B: I
{
 public int v { get; set;}
}
</code></pre>

Now consider this code block - 

<pre><code>var result = JsonConvert.DeserializeObject&lt;I&gt;("{\"v\" : 10}");
</code></pre>

Can you tell me what will be the outcome? <code>Interface</code> cannot be instantiated. So it either have to be <code>A</code> or <code>B</code>? Which class will the result be? <code>A</code> or <code>B</code>? Actually no one cannot tell - so does the compiler.

The same thing is happening here. - 

<pre><code>JsonConvert.DeserializeObject&lt;IEnumerable&lt;Book&gt;&gt;(result);
</code></pre>

You are deserializing to <code>IEnumerable&lt;Book&gt;</code>, but <code>IEnumerable&lt;Book&gt;</code> is not a concrete implementation. This is just an interface, a signature of the result but not the resultant type itself. So the converter cannot tell which class to use. That is why it is telling you to use primitive types or something that can be created.

And from the looks of the error it is trying to use <code>List&lt;Book&gt;</code> to deserialize to, but it cannot do that either, because the JSON string provided is not an array, it is an object, hence the error- 

<blockquote>
 Cannot deserialize the current JSON object (e.g. {"name":"value"})
 into type 'System.Collections.Generic.List`1[BookClient.Data.Book]'
 because the type requires a JSON array (e.g. [1,2,3]) to deserialize
 correctly. To fix this error either change the JSON to a JSON array
 (e.g. [1,2,3]) or change the deserialized type so that it is a normal
 .NET type (e.g. not a primitive type like integer, not a collection
 type like an array or List) that can be deserialized from a JSON
 object. JsonObjectAttribute can also be added to the type to force it
 to deserialize from a JSON object
</blockquote>

If you are looking for a solution then follow @Maria Ines Parnisari answer. That is a good solution to your problem.

I want to know why I get this error when I use these statements:

<pre><code>string result = await client.GetStringAsync(RestUrl);

return JsonConvert.DeserializeObject&lt;IEnumerable&lt;Book&gt;&gt;(result);
</code></pre>

<blockquote>
 Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[BookClient.Data.Book]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.
 To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object 
</blockquote>

this is the result string File:

<pre><code>"{\"TOTAL\":177,\"PRODUCTS\":[{\"CODE\":\"T55-2A\",\"PRICE\":59.9500,\"NAME\":\"Arrive In Style\"},{\"CODE\":\"F1-231\",\"PRICE\":49.9500}]}"
</code></pre>

Thanks

JsonConvert.DeserializeObject<IEnumerable<Book>>

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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当我使用以下语句时，我想知道为什么会出现这个错误：string result = await client.GetStringAsync(RestUrl);return JsonConvert.DeserializeObject<IEnumerable<Book>>(result);无法将当前JSON对象(例如，{“名...

问JsonConvert.DeserializeObject<IEnumerable<Book>>
EN

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