blocks|key|4204215|text|您可以使用流|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4204216|arrayList.stream().filter(x+->+x.indexOf("ne")+!=-1).collect(Collectors.toList());|code-block|syntax|javascript|4204217|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use a stream 

<pre><code>arrayList.stream().filter(x -&gt; x.indexOf("ne") !=-1).collect(Collectors.toList());
</code></pre>

blocks|key|3214318|text|List+<String>+filtered+=+arrayList.stream().filter(x+->+x.contains("ne")).collect(Collectors.toList());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3214319|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>List &lt;String&gt; filtered = arrayList.stream().filter(x -&gt; x.contains("ne")).collect(Collectors.toList());
</code></pre>

blocks|key|3214328|text|在android中，用于非java-8。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3214329|1.)遍历数组值|3214330|2.)应用toLowerCase()将值转换为小写，并检查它是否包含ne，如果不包含，则从列表中删除元素|offset|length|style|CODE|3214331|for+(String+s:+numbers)+{
++++if+(!s.toLowerCase().contains("ne"))+{
++++++++arrayList.remove(s);
++++}
}|code-block|syntax|javascript|3214332|列表元素|3214333|One
Nine|3214334|Java+8|3214335|1.)永远不要使用Raw+type|3214336|2.)在filter中应用上述逻辑|3214337|ArrayList<String>+arrayList=new+ArrayList<>(Arrays.asList(numbers));
List<String>+non_ne+=+arrayList.stream()
++++++++++++++++++++.filter(x->!x.toLowerCase().contains("ne"))
++++++++++++++++++++.collect(Collectors.toList());|3214338|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2770321/what-is-a-raw-type-and-why-shouldnt-we-use-it^0|0|0|5|D|Y|2|0|0|0|0|0|9|8|9|8|0|0|4|6|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|1A|8|@$F|1B|G|1C|H|I]|$F|1D|G|1E|H|I]]|9|@]|A|$]]|$1|J|3|K|5|L|7|1F|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1H|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|1I|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1J|8|@$F|1K|G|1L|H|I]]|9|@$F|1M|G|1N|1|1O]]|A|$]]|$1|W|3|X|5|6|7|1P|8|@$F|1Q|G|1R|H|I]]|9|@]|A|$]]|$1|Y|3|Z|5|L|7|1S|8|@]|9|@]|A|$M|N]]|$1|10|3|-4|5|6|7|1T|8|@]|9|@]|A|$]]]|11|$12|$5|13|14|15|A|$16|17]]]]

In android ,for non java-8 

1.) Traverse you array values

2.) Apply <code>toLowerCase()</code> to convert value to lowercase and Check if it contains <code>ne</code> , if no then remove the element from list

<pre><code>for (String s: numbers) {
 if (!s.toLowerCase().contains("ne")) {
 arrayList.remove(s);
 }
}
</code></pre>

list elements

<pre><code>One
Nine
</code></pre>

<hr>

Java 8

1.) Never use <a href="https://stackoverflow.com/questions/2770321/what-is-a-raw-type-and-why-shouldnt-we-use-it"><code>Raw type</code></a> 

2.) Apply the above logic in <code>filter</code> 

<pre><code>ArrayList&lt;String&gt; arrayList=new ArrayList&lt;&gt;(Arrays.asList(numbers));
List&lt;String&gt; non_ne = arrayList.stream()
 .filter(x-&gt;!x.toLowerCase().contains("ne"))
 .collect(Collectors.toList());
</code></pre>

blocks|key|4204245|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4204246|Iterator<String>+iter+=+arrayList.iterator();
while+(iter.hasNext())+{
++String+s+=+iter.next();
++if+(s.toLowerCase().contains("ne"))+iter.remove();
}|code-block|syntax|javascript|4204247|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>Iterator&lt;String&gt; iter = arrayList.iterator();
while (iter.hasNext()) {
 String s = iter.next();
 if (s.toLowerCase().contains("ne")) iter.remove();
}
</code></pre>

blocks|key|3214347|text|在查看您的代码时，我认为您最好一开始就不添加它们。你实际上是在说：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3214348|String[]+numbers+=+new+String[]+{"One",+"Two",+"Three",+...};+//array
List+list+=+Arrays.asList(numbers)+//create+a+list
ArrayList+arrayList+=+new+ArrayList<>(list);+//create+an+ArrayList

//remove+those+not+matching+from+the+ArrayList|code-block|syntax|javascript|3214349|我更倾向于只添加我需要加入的方法：|3214350|List<String>+list+=+new+ArrayList<>();+//a+LinkedList+may+be+more+appropriate+
for+(String+number+:+numbers)+{
++++if+(number.toLowerCase().contains("ne"))+{
++++++++list.add(number+);
++++}
}|3214351|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Looking at your code I am thinking you are probably better off not adding them in the first place. you are effectively saying:

<pre><code>String[] numbers = new String[] {"One", "Two", "Three", ...}; //array
List list = Arrays.asList(numbers) //create a list
ArrayList arrayList = new ArrayList&lt;&gt;(list); //create an ArrayList

//remove those not matching from the ArrayList
</code></pre>

I would prefer the approach of only adding the ones I need to be in the list:

<pre><code>List&lt;String&gt; list = new ArrayList&lt;&gt;(); //a LinkedList may be more appropriate 
for (String number : numbers) {
 if (number.toLowerCase().contains("ne")) {
 list.add(number );
 }
}
</code></pre>

Android Studio - Java

How can I remove all entries from an ArrayList except the ones that contain certain characters independently from upper and lower case?

<pre><code>String[] numbers = new String[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve"};

ArrayList arrayList=new ArrayList&lt;&gt;(Arrays.asList(numbers));


ArrayList.remove();
</code></pre>

E.g. if I choose the letters "Ne" I would like to remove all the entries from the arraylist except the entries containing the charachter string "ne".

ArrayList remove except if contains character

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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Android Java除了包含独立于大写和小写的特定字符的条目外，我如何从ArrayList中删除所有条目？String[] numbers = new String[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", ...

问除包含字符外，ArrayList删除
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问除包含字符外，ArrayList删除EN