blocks|key|2014604|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2014605|console.log($("ul.outer>li").length)
console.log($("ul.inner>li").length)|code-block|syntax|javascript|2014606|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul+class='outer'>
++<li>branch+1
++++<ul+class="inner">
++++++<li>leaf+1</li>
++++++<li>leaf+2</li>
++++</ul>
++</li>
++<li>leaf+3</li>
</ul>|2014607|2014608|要计算直接子级使用>|ordered-list-item|offset|length|style|CODE|2014609|entityMap^0|0|0|0|0|9|1|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|I|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>console.log($("ul.outer&gt;li").length)
console.log($("ul.inner&gt;li").length)</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;
&lt;ul class='outer'&gt;&lt;!-- Leaf Count 3 --&gt;
  &lt;li&gt;branch 1
    &lt;ul class="inner"&gt;&lt;!-- Leaf Count 2 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
      &lt;li&gt;leaf 2&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;</code></pre>
</div>
</div>
</p>

<ol>
<li>To count direct child use <code>&gt;</code></li>
</ol>


blocks|key|2014675|text|如果倾向于不更改HTML，则可以使用jQuery的filter：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2014676|​|2014677|function+filterLeaf(ele)+{
++if+($(ele).children().length+===+0)+{
++++return+true;
++}
++return+false;
}

var+nouter+=+$('#outer').find('li').filter(function()+{
++return+filterLeaf(this);
}).length;
var+ninner+=+$('#inner').find('li').filter(function()+{
++return+filterLeaf(this);
}).length;
console.log(nouter);
console.log(ninner);|code-block|syntax|javascript|2014678|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<ul+id="outer">
++<li>branch+1
++++<ul+id="inner">
++++++<li>leaf+1</li>
++++++<li>leaf+2</li>
++++</ul>
++</li>
++<li>leaf+3</li>
</ul>|2014679|2014680|或者，在生成HTML时，将类名如“叶子”添加到叶元素中，然后使用jQuery的.find|2014681|2014682|var+nouter+=+$('#outer').find('.leaf').length;
var+ninner+=+$('#inner').find('.leaf').length;
console.log(nouter);
console.log(ninner);|2014683|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul+id="outer">
++<li>branch+1
++++<ul+id="inner">
++++++<li+class="leaf">leaf+1</li>
++++++<li+class="leaf">leaf+2</li>
++++</ul>
++</li>
++<li+class="leaf">leaf+3</li>
</ul>|2014684|2014685|entityMap^0|P|6|0|0|0|0|0|13|5|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|12|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|13|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|O|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|P|3|Q|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@]|E|$]]|$1|R|3|G|5|6|7|19|8|@]|D|@]|E|$]]|$1|S|3|T|5|J|7|1A|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|J|7|1B|8|@]|D|@]|E|$K|L]]|$1|W|3|G|5|6|7|1C|8|@]|D|@]|E|$]]|$1|X|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|Y|$]]

<p>If it is preferred not to change HTML, jQuery's <code>filter</code> can be used:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function filterLeaf(ele) {
  if ($(ele).children().length === 0) {
    return true;
  }
  return false;
}

var nouter = $('#outer').find('li').filter(function() {
  return filterLeaf(this);
}).length;
var ninner = $('#inner').find('li').filter(function() {
  return filterLeaf(this);
}).length;
console.log(nouter);
console.log(ninner);</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;

&lt;ul id="outer"&gt;&lt;!-- Leaf Count 3 --&gt;
  &lt;li&gt;branch 1
    &lt;ul id="inner"&gt;&lt;!-- Leaf Count 2 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
      &lt;li&gt;leaf 2&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;</code></pre>
</div>
</div>
</p>

<p>Or, when generate the HTML, add class name such as "leaf" to the leaf element, and then using jQuery's <code>.find</code>:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var nouter = $('#outer').find('.leaf').length;
var ninner = $('#inner').find('.leaf').length;
console.log(nouter);
console.log(ninner);</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;
&lt;ul id="outer"&gt;&lt;!-- Leaf Count 3 --&gt;
  &lt;li&gt;branch 1
    &lt;ul id="inner"&gt;&lt;!-- Leaf Count 2 --&gt;
      &lt;li class="leaf"&gt;leaf 1&lt;/li&gt;
      &lt;li class="leaf"&gt;leaf 2&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li class="leaf"&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;</code></pre>
</div>
</div>
</p>


blocks|key|1971348|text|您可以使用TreeWalker+api，并将没有自己的子级的<ul>的所有子级相加。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1971349|​|1971350|const+treeWalker+=+document.createTreeWalker(
++document.body,
++NodeFilter.SHOW_ELEMENT
);

const+result+=+[];

while+(treeWalker.nextNode())+{
++const+node+=+treeWalker.currentNode;

++if+(node.nodeName+===+'UL')+{
++++result.push([...node.querySelectorAll('li')].filter((node)+=>+!node.children.length).length);
++}
};

console.log(result);|code-block|syntax|javascript|1971351|<ul>
++
++<li>branch+1
++++<ul>
++++++
++++++<li>leaf+1</li>
++++++<li>leaf+2</li>
++++++<li>branch+2
++++++++<ul>
++++++++++
++++++++++<li>leaf+1</li>
++++++++++<li>leaf+2</li>
++++++++</ul>
++++++</li>
++++++<li>branch+3
++++++++<ul>
++++++++++
++++++++++<li>leaf+1</li>
++++++++++<li>leaf+2</li>
++++++++</ul>
++++++</li>
++++</ul>
++</li>
++<li>leaf+3</li>
</ul>|1971352|1971353|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en/docs/Web/API/TreeWalker^0|U|4|5|E|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@$9|10|A|11|1|12]]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|J|7|15|8|@]|D|@]|E|$K|L]]|$1|O|3|G|5|6|7|16|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|Q|$R|$5|S|T|U|E|$V|W]]]]

<p>You can use the <a href="https://developer.mozilla.org/en/docs/Web/API/TreeWalker" rel="nofollow noreferrer">TreeWalker api</a>, and sum all the children of a <code>&lt;ul&gt;</code> that don't have children of their own.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const treeWalker = document.createTreeWalker(
  document.body,
  NodeFilter.SHOW_ELEMENT
);

const result = [];

while (treeWalker.nextNode()) {
  const node = treeWalker.currentNode;

  if (node.nodeName === 'UL') {
    result.push([...node.querySelectorAll('li')].filter((node) =&gt; !node.children.length).length);
  }
};

console.log(result);</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;ul&gt;
  &lt;!-- Leaf Count 7 --&gt;
  &lt;li&gt;branch 1
    &lt;ul&gt;
      &lt;!-- Leaf Count 6 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
      &lt;li&gt;leaf 2&lt;/li&gt;
      &lt;li&gt;branch 2
        &lt;ul&gt;
          &lt;!-- Leaf Count 2 --&gt;
          &lt;li&gt;leaf 1&lt;/li&gt;
          &lt;li&gt;leaf 2&lt;/li&gt;
        &lt;/ul&gt;
      &lt;/li&gt;
      &lt;li&gt;branch 3
        &lt;ul&gt;
          &lt;!-- Leaf Count 2 --&gt;
          &lt;li&gt;leaf 1&lt;/li&gt;
          &lt;li&gt;leaf 2&lt;/li&gt;
        &lt;/ul&gt;
      &lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;</code></pre>
</div>
</div>
</p>


blocks|key|2014708|text|我认为接受的答案并不是更有效。有更简单的方法来做到这一点。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2014709|我们可以使用jquery简单选择的li:not(:has(*))。这将找到所有没有子元素(叶节点)的li元素。|offset|length|style|CODE|2014710|使用$("#dvMain").find('ul').each，它将找到所有的ul元素，然后循环遍历它。|2014711|​|2014712|$(document).ready(function()+{
++++$("#dvMain").find('ul').each(function(item)+{
++++++++console.log($(this).find('li:not(:has(*))').length);
++++});
});|code-block|syntax|javascript|2014713|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div+id="dvMain">
<ul>
++<li>branch+1
++++<ul>
++++++<li>leaf+1</li>
++++++<li>leaf+2</li>
++++</ul>
++</li>
++<li>branch+1
++++<ul>
++++++<li>leaf+1</li>
++++</ul>
++</li>
++<li>leaf+3</li>
</ul>
</div>|2014714|2014715|entityMap^0|0|H|F|0|2|S|12|2|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@$D|10|E|11|F|G]|$D|12|E|13|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|14|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|15|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|N|7|16|8|@]|9|@]|A|$O|P]]|$1|S|3|K|5|6|7|17|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|U|$]]

<p>I think accepted answer is not more efficient. There is even simpler way of doing this.</p>

<p>We can use jquery simple selectee <code>li:not(:has(*))</code>. This will find all li element that doesn't have children(leaf node).</p>

<p>Use <code>$("#dvMain").find('ul').each</code> which will find all <code>ul</code> element and then loop through it.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>$(document).ready(function() {
    $("#dvMain").find('ul').each(function(item) {
        console.log($(this).find('li:not(:has(*))').length);
    });
});</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;

&lt;div id="dvMain"&gt;
&lt;ul&gt;&lt;!-- Leaf Count 4 --&gt;
  &lt;li&gt;branch 1
    &lt;ul&gt;&lt;!-- Leaf Count 2 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
      &lt;li&gt;leaf 2&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;branch 1
    &lt;ul&gt;&lt;!-- Leaf Count 1 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;
&lt;/div&gt;</code></pre>
</div>
</div>
</p>


blocks|key|1971406|text|你甚至可以用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1971407|$('ul').each(function(a){
count+=+0;
$(this).find('li').each(function(){
if($(this).children().length+==0){
count%2B%2B;
}

});
console.log('+ul+level+'%2Ba%2B'+count+:+'%2Bcount);

});|code-block|syntax|javascript|1971408|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
++<li>branch+1
++++<ul>
++++++<li>leaf+1</li>
++++++<li>leaf+2</li>
++++</ul>
++</li>
++<li>leaf+3</li>
</ul>|1971409|​|1971410|工作演示|offset|length|1971411|entityMap|0|LINK|mutability|MUTABLE|url|https://jsfiddle.net/4j2o1qbs/1/^0|0|0|0|0|0|4|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

<p>You can use even this 
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>$('ul').each(function(a){
count = 0;
$(this).find('li').each(function(){
if($(this).children().length ==0){
count++;
}

});
console.log(' ul level '+a+' count : '+count);

});</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;
&lt;ul&gt;&lt;!-- Leaf Count 3 --&gt;
  &lt;li&gt;branch 1
    &lt;ul&gt;&lt;!-- Leaf Count 2 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
      &lt;li&gt;leaf 2&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;</code></pre>
</div>
</div>
</p>

<p><strong><a href="https://jsfiddle.net/4j2o1qbs/1/" rel="nofollow noreferrer">Working Demo</a></strong></p>


<p>Given a html structure that looks like the following html, but is of arbitrary depth. (i.e. it could go many levels deeper). Because it is of arbitray depth, I would prefer a solution that doesn't require adding any extra markup to the html (e.g. classes)</p>

<pre><code>&lt;ul&gt;&lt;!-- Leaf Count 3 --&gt;
  &lt;li&gt;branch 1
    &lt;ul&gt;&lt;!-- Leaf Count 2 --&gt;
      &lt;li&gt;leaf 1&lt;/li&gt;
      &lt;li&gt;leaf 2&lt;/li&gt;
    &lt;/ul&gt;
  &lt;/li&gt;
  &lt;li&gt;leaf 3&lt;/li&gt;
&lt;/ul&gt;
</code></pre>

<p>How can I count all the leaves that are a child of each ul? So in this example the outer most ul would have 3 leaves and the nested one two leaves. This seems like a recursion issue, but I can't think through it.</p>


Find the leaf count for each parent ul in a nested ul structure

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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给定类似于以下html的html结构，但具有任意深度。(也就是说，它可以走得更深)。因为它具有仲裁深度，所以我更喜欢不需要向html (例如类)添加任何额外标记的解决方案。<ul>  <li>branch 1    <ul>      ...

问在嵌套ul结构中查找每个父ul的叶数。
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问在嵌套ul结构中查找每个父ul的叶数。EN