blocks|key|4473801|text|JSON.parse()接受json字符串作为参数，并返回一个JSON对象。如果json字符串是正确的，这应该可以工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4473802|var+key+=+JSON.parse(objArray);
for+(key+in+objArray)+{
++if+(objArray.hasOwnProperty(key))+{
++++console.log(key+%2B+"+->+"+%2B+objArray[key]);
++}
}|code-block|syntax|javascript|4473803|entityMap^0|0|C|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

<code>JSON.parse()</code> takes json string as argument and returns a JSON object. 
This should work if json string is proper.

<pre><code>var key = JSON.parse(objArray);
for (key in objArray) {
 if (objArray.hasOwnProperty(key)) {
 console.log(key + " -&gt; " + objArray[key]);
 }
}
</code></pre>

blocks|key|3897220|text|首先，您需要从JSON.parse返回值，然后必须迭代objArray的bit数组，因为现在您只查看顶层的键。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3897221|​|3897222|var+objArray+=+'{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}'
objArray+=+JSON.parse(objArray);

for+(var+bit+in+objArray.bit)+{
++for+(var+key+in+objArray.bit[bit])+{
++++if+(objArray.bit[bit].hasOwnProperty(key))+{
++++++console.log(key+%2B+"+->+"+%2B+objArray.bit[bit][key]);
++++}
++}
}|code-block|syntax|javascript|3897223|3897224|entityMap^0|7|A|R|8|10|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|X|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|Y|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|O|$]]

First off you need to return the value from <code>JSON.parse</code> and then you have to iterate the <code>bit</code> array of <code>objArray</code>, as right now you're only looking at the keys on the top level.

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var objArray = '{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}'
objArray = JSON.parse(objArray);

for (var bit in objArray.bit) {
 for (var key in objArray.bit[bit]) {
 if (objArray.bit[bit].hasOwnProperty(key)) {
 console.log(key + " -&gt; " + objArray.bit[bit][key]);
 }
 }
}</code></pre>
</div>
</div>

blocks|key|4473828|text|如果objArray是字符串，JSON.parse将将json解析为字符串：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4473829|++++var+output+=+Object.values(JSON.parse(objArray)["bit"]).map(elt+=>+{
+++++++return+elt.id+%2B+'->'+%2B+elt.value;
++++}).join(';');

++++console.log(output);|code-block|syntax|javascript|4473830|entityMap^0|2|8|F|A|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

If <code>objArray</code> is a string, <code>JSON.parse</code> will parse the json as a string :

<pre><code> var output = Object.values(JSON.parse(objArray)["bit"]).map(elt =&gt; {
 return elt.id + '-&gt;' + elt.value;
 }).join(';');

 console.log(output);
</code></pre>

blocks|key|4473892|text|每次我试图迭代时，我都没有定义，或者我从json中得到了每个字符，这不是我假装的。|type|blockquote|depth|inlineStyleRanges|entityRanges|data|4473893|JSON+String原因:您正在尝试解析JSON+Object而不是JSON+Object的|unstyled|offset|length|style|BOLD|CODE|4473894|演示|4473895|​|4473896|var+jsonStr+=+'{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}';

for+(var+key+in+jsonStr)+{
++if+(jsonStr.hasOwnProperty(key))+{
++++console.log(key+%2B+"+->+"+%2B+jsonStr[key]);
++}
}|code-block|syntax|javascript|4473897|4473898|正确解决方案:|4473899|首先在JSON+String方法的帮助下将JSON.parse()转换为JSON+Object，然后解析它。|4473900|4473901|4473902|var+jsonStr+=+'{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}';

var+jsonObj+=+JSON.parse(jsonStr);

for+(var+key+in+jsonObj)+{
++++++if+(jsonObj.hasOwnProperty(key))+{
++++++++console.log(key+%2B+"+->+"+,+jsonObj[key]);
++++++}
++++}|4473903|4473904|entityMap^0|0|0|B|L|B|Z|B|0|B|L|B|Z|B|0|0|2|0|0|0|0|0|7|0|3|B|L|C|10|B|0|0|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@$E|16|F|17|G|H]|$E|18|F|19|G|H]|$E|1A|F|1B|G|H]|$E|1C|F|1D|G|I]|$E|1E|F|1F|G|I]|$E|1G|F|1H|G|I]]|9|@]|A|$]]|$1|J|3|K|5|D|7|1I|8|@$E|1J|F|1K|G|H]]|9|@]|A|$]]|$1|L|3|M|5|D|7|1L|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|1M|8|@]|9|@]|A|$Q|R]]|$1|S|3|M|5|D|7|1N|8|@]|9|@]|A|$]]|$1|T|3|U|5|D|7|1O|8|@$E|1P|F|1Q|G|H]]|9|@]|A|$]]|$1|V|3|W|5|D|7|1R|8|@$E|1S|F|1T|G|I]|$E|1U|F|1V|G|I]|$E|1W|F|1X|G|I]]|9|@]|A|$]]|$1|X|3|K|5|D|7|1Y|8|@$E|1Z|F|20|G|H]]|9|@]|A|$]]|$1|Y|3|M|5|D|7|21|8|@]|9|@]|A|$]]|$1|Z|3|10|5|P|7|22|8|@]|9|@]|A|$Q|R]]|$1|11|3|M|5|D|7|23|8|@]|9|@]|A|$]]|$1|12|3|-4|5|D|7|24|8|@]|9|@]|A|$]]]|13|$]]

<blockquote>
 And everytime i try to iterate i get undefined or i get every single character from the json and this is not what i pretend
</blockquote>

Reason : You are trying to parse <code>JSON String</code> instead of <code>JSON Object</code>

DEMO

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var jsonStr = '{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}';

for (var key in jsonStr) {
 if (jsonStr.hasOwnProperty(key)) {
 console.log(key + " -&gt; " + jsonStr[key]);
 }
}</code></pre>
</div>
</div>


Correct solution :

First convert <code>JSON String</code> into <code>JSON Object</code> with the help of <code>JSON.parse()</code> method then parse it.

DEMO

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var jsonStr = '{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}';

var jsonObj = JSON.parse(jsonStr);

for (var key in jsonObj) {
 if (jsonObj.hasOwnProperty(key)) {
 console.log(key + " -&gt; " , jsonObj[key]);
 }
 }</code></pre>
</div>
</div>

I have this a json that i want iterate and get the value from it and set and some variables but i'm facing some problems reading it

Here is my json:

<pre><code>{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}
</code></pre>

And everytime i try to iterate i get undefined or i get every single character from the json and this is not what i pretend:

Here is what i already tried:

1)

<pre><code> JSON.stringify(objArray);
 for (var key in objArray) {
 if (objArray.hasOwnProperty(key)) {
 console.log(key + " -&gt; " + objArray[key]);
 }
 }
</code></pre>

Output: 

<pre><code>0 -&gt; {
1 -&gt; "
2 -&gt; b
3 -&gt; i
4 -&gt; t
5 -&gt; "
 ...
</code></pre>

2)

<pre><code>JSON.parse(objArray);
for (var key in objArray) {
 if (objArray.hasOwnProperty(key)) {
 console.log(key + " -&gt; " + objArray[key]);
 }
}
</code></pre>

Same output as before

3

<pre><code>for (var key in objArray) {
 if (objArray.hasOwnProperty(key)) {
 console.log(key + " -&gt; " + objArray[key]);
 }
 }
</code></pre>

Same output

i already tried other iterators i saw on another post:

And i what to iterate and get 81,aaa ; 83,bbb

Thanks in advance

js iterate json get every single character from json

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个json，我想要迭代，从它得到值，集合和一些变量，但是我在阅读它时会遇到一些问题这是我的儿子：{"bit":[{"id":81,"value":"aaaa"},{"id":83,"value":"bbbb"}]}每次我试图迭代时，我都没有定义，或者我从json中得到了每个字符，这不是我所假装的：以下是我已经尝试...

问js迭代json从json获取每个字符。
EN

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问js迭代json从json获取每个字符。EN