# include <iostream>
using std::endl;
using std::cout;
using std::cin;
int main()
{
int numUserInt; // Number of integers the user inputs
int integers;
int number;
int maxNumber = 0;
int minNumber = 0;
// Get the number of integers
cout << "How many integers would you like to enter?" << endl;
cin >> numUserInt;
cout << "Please enter " << numUserInt << " integers." << endl;
integers = 1;
while (integers <= numUserInt)
{
cin >> number;
if (numUserInt == 1)
maxNumber = minNumber = number;
if (number > maxNumber)
maxNumber = number;
if (number < minNumber)
minNumber = number;
integers++;
}
cout << "min: " << minNumber << endl;
cout << "max: " << maxNumber << endl;
return 0;
}
对于作业作业,我应该问用户“他们想输入多少整数”,然后在不使用数组的情况下从数量中找到最大值和最小数。在大多数情况下,我的程序可以工作,但是当用户输入-6-6时,输出是min:-6和max: 0。我希望这样说,最小和最大为-6,但我不知道如何使其余的代码工作。有谁知道怎么做的吗?
发布于 2017-07-09 04:56:27
如果您将
if (numUserInt == 1)
通过
if (integers == 1)
。
这样,来自评论和其他答案的建议,
第一次输入到最小和最大,
已实现。
输出:
How many integers would you like to enter?
2
Please enter 2 integers.
-6
-6
min: -6
max: -6
发布于 2017-07-09 03:49:25
将min
和max
变量的值设置为初始输入,然后将min
和max
与用户每次输入的内容进行比较,以检查是否需要更新。
https://stackoverflow.com/questions/44992772
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