嘿,谢谢你抽出时间来帮助我,我会直截了当地说:这只是一个小项目,在我的GCSE之前,我已经开始练习我的Python技巧--我目前的问题是把一个数字添加到一个列表中,因为我已经完成了程序的每个部分,我设法解决了所有当前的问题,但是,我一直无法解决这个问题--关于这个问题的所有/任何反馈/让程序更有效率将不胜感激。谢谢。
##code##
name = input("hello user what is your name?")
print("thank you for using our program:",name.title(),)
userchoice = input("which program would you like to use: add numbers,minus
numbers, alphabetical word order?")
#add numbers#
numList = []
addnewnumber = input ("would you like to add a new number?")
while addnewnumber == 'yes':
newnumber = input("what is your number?")
numList.append()
if addnewnumber == 'no':
numListsum = sum(numList)
print (numListsum)
##Console message##
RESTART: C:/Users/SWILS/AppData/Local/Programs/Python/Python36/python
coding/1.0.py
hello user what is your name?sean
thank you for using our program: Sean
which program would you like to use: add numbers,minus numbers, alphabetical
word order?add numbers
would you like to add a new number?yes
what is your number?6
Traceback (most recent call last):
File "C:/Users/SWILS/AppData/Local/Programs/Python/Python36/python
coding/1.0.py", line 11, in <module>
numList.append()
TypeError: append() takes exactly one argument (0 given)发布于 2017-08-23 16:45:19
你的numList.append()必须有一个参数。
所以,切换到这个numList.append(newnumber)。
发布于 2019-11-12 16:15:46
这对我有用->
append((item1 , item2))发布于 2017-08-23 16:38:02
错误消息的意思正是它所说的:.append()希望您传递一个参数,但实际上没有传递任何参数。试试这个:
numList.append(newnumber)https://stackoverflow.com/questions/45845124
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