blocks|key|584492|text|您应该使用filter方法，它接受一个callback函数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|584493|filter()方法创建一个新数组，其中包含所有通过所提供函数实现的测试的元素。|blockquote|584494|另外，使用typeof+运算符从数组中找出项的类型。类型的运算符返回一个字符串，指示未计算的操作数的类型。|BOLD|584495|​|584496|let+total+=+["10%25",+"1000",+"5%25",+"2000"];
let+percentage+=+total.filter(function(item){
++return+typeof+item+==+'string'+&&+item.includes('%25');
});
console.log(percentage);
let+absolute+=+total.filter(function(item){
++return+typeof+item+==+'number'+%7C%7C+!isNaN(item);
});
console.log(absolute);|code-block|syntax|javascript|584497|584498|entityMap^0|5|6|J|8|0|0|5|6|C|3|Q|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$]]|$1|I|3|J|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|K]|$9|16|A|17|B|K]]|D|@]|E|$]]|$1|L|3|M|5|6|7|18|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|19|8|@]|D|@]|E|$Q|R]]|$1|S|3|M|5|6|7|1A|8|@]|D|@]|E|$]]|$1|T|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|U|$]]

<p>You should use <code>filter</code> method, which accepts a <code>callback</code> function.</p>

<blockquote>
  <p>The filter() method creates a new array with all elements that pass
  the test implemented by the provided function.</p>
</blockquote>

<p>Also, use <code>typeof</code> <strong>operator</strong> in order to find out the type of item from array. The <strong>typeof</strong> operator returns a string indicating the type of the unevaluated operand.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let total = ["10%", "1000", "5%", "2000"];
let percentage = total.filter(function(item){
  return typeof item == 'string' &amp;&amp; item.includes('%');
});
console.log(percentage);
let absolute = total.filter(function(item){
  return typeof item == 'number' || !isNaN(item);
});
console.log(absolute);</code></pre>
</div>
</div>
</p>


blocks|key|1370454|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1370455|let+total+=+["10%25",+1000,+"5%25",+2000];

let+percents+=+total.filter(item+=>+item.toString().includes('%25'));
let+numbers+=+total.filter(item+=>+!item.toString().includes('%25'));
console.log(percents,+numbers);|code-block|syntax|javascript|1370456|1370457|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let total = ["10%", 1000, "5%", 2000];

let percents = total.filter(item =&gt; item.toString().includes('%'));
let numbers = total.filter(item =&gt; !item.toString().includes('%'));
console.log(percents, numbers);</code></pre>
</div>
</div>
</p>


blocks|key|1370586|text|Make+two+arrays+from+one+array+by+separating+number+and+string+using+advance++
js.|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1370587|​|unstyled|1370588|let+total+=+["10%25",+1000,+"5%25",+2000];
var+percentage+=+total.filter(e+=>+isNaN(e));
var+absolute+=+total.filter(e+=>+!isNaN(e));
console.log({percentage+,+absolute});|1370589|1370590|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|N|8|@]|9|@]|A|$B|C]]|$1|I|3|E|5|F|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|F|7|P|8|@]|9|@]|A|$]]]|K|$]]

<pre><code>Make two arrays from one array by separating number and string using advance  
js.
</code></pre>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let total = ["10%", 1000, "5%", 2000];
var percentage = total.filter(e =&gt; isNaN(e));
var absolute = total.filter(e =&gt; !isNaN(e));
console.log({percentage , absolute});</code></pre>
</div>
</div>
</p>


blocks|key|1370491|text|您可以使用正则表达式，因为数组中只有字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1370492|%25：|1370493|total.filter(function(element){
++++return+/%5E[0-9]%2B\%25$/gi.test(element);
});|code-block|syntax|javascript|1370494|绝对：|1370495|total.filter(function(element){
++++return+/%5E[0-9]%2B$/gi.test(element);
});|1370496|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>You can use regular expressions since you have only strings in your array.</p>

<p>For % :</p>

<pre><code>total.filter(function(element){
    return /^[0-9]+\%$/gi.test(element);
});
</code></pre>

<p>For absolute : </p>

<pre><code>total.filter(function(element){
    return /^[0-9]+$/gi.test(element);
});
</code></pre>


blocks|key|584640|text|可以使用Array#reduce拆分数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|584641|​|584642|const+total+=+["10%25",+1000,+"5%25",+2000];

const+{+absolute,+percentage+}+=+total.reduce((arrs,+item)+=>+{
++const+key+=+typeof+item+===+'number'+?+'absolute'+:+'percentage';
++
++arrs[key].push(item);
++
++return+arrs;
},+{+percentage:+[],+absolute:+[]+});

console.log(absolute);

console.log(percentage);|code-block|syntax|javascript|584643|584644|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>You can use Array#reduce to split the array:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const total = ["10%", 1000, "5%", 2000];

const { absolute, percentage } = total.reduce((arrs, item) =&gt; {
  const key = typeof item === 'number' ? 'absolute' : 'percentage';
  
  arrs[key].push(item);
  
  return arrs;
}, { percentage: [], absolute: [] });

console.log(absolute);

console.log(percentage);</code></pre>
</div>
</div>
</p>


blocks|key|672966|text|你可以用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|672967|​|672968|let+total+=+["10%25",+1000,+"5%25",+2000]


let+result1+=+total.filter(function(element){
++++if(typeof+element+==+"number"){
++++++++return+1;
++++}
++++return+0;
})
let+result2+=+total.filter(function(element){
++++if(typeof+element+==+"string"+&&+element.match(/\%25$/)){
++++++++return+1;
++++}
++++return+0;
})
console.log(result1,+result2);|code-block|syntax|javascript|672969|672970|第一个数组过滤所有数字
第二个数组过滤器元素，它是一个字符串，结尾有一个"%25“|blockquote|672971|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>you can do it using </p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let total = ["10%", 1000, "5%", 2000]


let result1 = total.filter(function(element){
    if(typeof element == "number"){
        return 1;
    }
    return 0;
})
let result2 = total.filter(function(element){
    if(typeof element == "string" &amp;&amp; element.match(/\%$/)){
        return 1;
    }
    return 0;
})
console.log(result1, result2);</code></pre>
</div>
</div>
</p>

<blockquote>
  <p>the first array filter all the number <br>
  the 2nd array filter elements which are a string and have a "%" in the end</p>
</blockquote>


blocks|key|584684|text|使用此代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|584685|$array+=+array('10%25',+'1000',+'20%25','2000');|code-block|syntax|javascript|584686|//表示数组中的整数|584687|print_r(array_filter($array，function+($var)+){false+(stripos($var，'%25')+===+false)；})；|584688|//表示显示%25数组|584689|print_r(array_filter($array，function+($var)+{$var+(stripos($var，'%25')+==+true)；})；|584690|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

<p>use this code</p>

<pre><code>$array = array('10%', '1000', '20%','2000');
</code></pre>

<p>//for show integer from array</p>

<p>print_r(array_filter($array, function ($var) { return (stripos($var, '%') === false); }));</p>

<p>//for show % array</p>

<p>print_r(array_filter($array, function ($var) { return (stripos($var, '%') == true); }));</p>


blocks|key|1370603|text|let+total+=+["10%25",+"1000",+"5%25",+"2000"];
let+percentage+=+total.filter(function(item){
++return+typeof+item+==+'string'+&&+item.includes('%25');
});
console.log(percentage);
let+absolute+=+total.filter(function(item){
++return+typeof+item+==+'number'+%7C%7C+!isNaN(item);
});
console.log(absolute);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1370604|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>let total = [&quot;10%&quot;, &quot;1000&quot;, &quot;5%&quot;, &quot;2000&quot;];
let percentage = total.filter(function(item){
  return typeof item == 'string' &amp;&amp; item.includes('%');
});
console.log(percentage);
let absolute = total.filter(function(item){
  return typeof item == 'number' || !isNaN(item);
});
console.log(absolute);
</code></pre>


<p>This is an array:</p>
<pre><code>total = [&quot;10%&quot;, 1000, &quot;5%&quot;, 2000]
</code></pre>
<p>How can I filter these into two arrays like:</p>
<pre><code>percentage = [&quot;10%&quot;,&quot;5%&quot;]
absolute = [1000,2000]
</code></pre>
<p>...using JavaScript array filter.</p>


How to filter an array in javascript?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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这是一个数组：total = ["10%", 1000, "5%", 2000]如何将这些数据过滤为两个数组，如：percentage = ["10%","5%"]absolute = [1000,2000]...using JavaScript阵列滤波器

问如何过滤javascript中的数组？
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问如何过滤javascript中的数组？
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