用Python解析来自http请求的文本响应
用Python解析来自http请求的文本响应
提问于 2017-08-30 07:56:18
我试图从APU中获取数据，但作为响应，我得到了纯文本。我想逐行阅读所有的文本。
这是url变量：http://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640
第一段：
from pymongo import MongoClient
import requests
from bs4 import BeautifulSoup as bs
url = "https://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640"
request = requests.get(url)
soup = bs(request.text,"lxml")
for line in soup:
print line
break结果：它打印出整个文本
第二段：
request = requests.get(url)
for line in request.text():
print line
break结果：它打印出一个字符
request = requests.get(url)
requestText = request.text()
allMf = requestText.splitlines()结果：异常：'unicode‘对象不可调用
我尝试过很少的案例，但无法逐行阅读文本。
回答 3
Stack Overflow用户
回答已采纳
发布于 2017-08-30 08:02:27
request.text是一个属性而不是一个方法，request.text返回一个unicode字符串，request.text()抛出错误'unicode' object is not callable。
for line in request.text.splitlines():
print lineStack Overflow用户
发布于 2017-08-30 08:13:36
import requests
from bs4 import BeautifulSoup as bs
url = "https://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640"
request = requests.get(url)
soup = bs(request.text,"lxml")
# soup.text is to get the returned text
# split function, splits the entire text into different lines (using '\n') and stores in a list. You can define your own splitter.
# each line is stored as an element in the allLines list.
allLines = soup.text.split('\n')
for line in allLines: # you iterate through the list, and print the single lines
print(line)
break # to just print the first line, to show this worksStack Overflow用户
发布于 2017-08-30 08:08:04
试试这个：
from pymongo import MongoClient
import requests
from bs4 import BeautifulSoup as bs
url = "https://www.amfiindia.com/spages/NAVAll.txt?t=23052017073640"
request = requests.get(url)
soup = bs(request.text,"lxml")
for line in soup:
print line.text
break页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/45954949
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