得到一个又一个匹配的行，直到行与其他模式匹配。
得到一个又一个匹配的行，直到行与其他模式匹配。
提问于 2017-10-24 13:01:13
故事-从日志文件中提取信息-在本例中，maven构建。基本上，我希望在一个给定的模式首先匹配之后，得到所有匹配一个模式的行。
换句话说，我想匹配在[WARNING]行之后以[WARNING] Javadoc Warnings开头的所有行。
我试过用这个：
(?<=\[WARNING\] Javadoc Warnings).*(\r|\n|.)(?=(\[WARNING\].*))但它只返回下一行。
[WARNING] E:\workspaces\1
[WARNING] E:\workspaces\4输入：
[WARNING] E:\workspaces\asd
[WARNING] E:\workspaces\dsa
[INFO]
12 warnings
[WARNING] Javadoc Warnings
[WARNING] E:\workspaces\1
[WARNING] E:\workspaces\2
[WARNING] E:\workspaces\3
[INFO] Building jar: E:\workspaces\asdf
[INFO]
[INFO] >>> maven-source-plugin:3.0.1:j
[INFO]
[INFO] <<< maven-source-plugin:3.0.1:j
[INFO]
12 warnings
[WARNING] Javadoc Warnings
[WARNING] E:\workspaces\4
[WARNING] E:\workspaces\5
[WARNING] E:\workspaces\6
[INFO] Building jar: E:\workspaces\asdf
[INFO]
[INFO] >>> maven-source-plugin:3.0.1:j
[INFO]
[INFO] <<< maven-source-plugin:3.0.1:j所期望的结果是
[WARNING] E:\workspaces\1
[WARNING] E:\workspaces\2
[WARNING] E:\workspaces\3
[WARNING] E:\workspaces\4
[WARNING] E:\workspaces\5
[WARNING] E:\workspaces\6回答 1
Stack Overflow用户
回答已采纳
发布于 2017-10-24 14:03:49
您可以使用以下解决方案：
(?:\G(?!\A)|\[WARNING] Javadoc Warnings)\R(\[WARNING].*)详细信息
(?:\G(?!\A)|\[WARNING] Javadoc Warnings)-一个[WARNING] Javadoc Warnings子字符串(\[WARNING] Javadoc Warnings)或(|)上一次成功匹配的结束(\G(?!\A))\R-断线(\[WARNING].*)- Group 1：[WARNING]子字符串和行结束后的任何0+字符
String s = "[WARNING] E:\\workspaces\\asd\r\n[WARNING] E:\\workspaces\\dsa\r\n\r\n[INFO] \r\n12 warnings\r\n[WARNING] Javadoc Warnings\r\n[WARNING] E:\\workspaces\\1\r\n[WARNING] E:\\workspaces\\2\r\n[WARNING] E:\\workspaces\\3\r\n\r\n[INFO] Building jar: E:\\workspaces\\asdf\r\n[INFO] \r\n[INFO] >>> maven-source-plugin:3.0.1:j\r\n\r\n[INFO] \r\n[INFO] <<< maven-source-plugin:3.0.1:j\r\n[INFO] \r\n12 warnings\r\n[WARNING] Javadoc Warnings\r\n[WARNING] E:\\workspaces\\4\r\n[WARNING] E:\\workspaces\\5\r\n[WARNING] E:\\workspaces\\6\r\n[INFO] Building jar: E:\\workspaces\\asdf\r\n[INFO] \r\n[INFO] >>> maven-source-plugin:3.0.1:j\r\n[INFO] \r\n[INFO] <<< maven-source-plugin:3.0.1:j";
Pattern pattern = Pattern.compile("(?:\\G(?!\\A)|\\[WARNING] Javadoc Warnings)\\R(\\[WARNING].*)");
Matcher matcher = pattern.matcher(s);
while (matcher.find()){
System.out.println(matcher.group(1));
} 页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/46911304
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