使用Java调用
使用Java调用
提问于 2017-10-27 01:54:19
我有一个java，它应该调用一个ASP.NET添加的Web服务。当我运行java服务并输入url http://localhost:8080/addition/9/6时，就会得到{"firstNumber":9,"secondNumber":6,"sum":15}作为输出数据。现在，我希望在运行ASP.NET Web应用程序时使用ASP.NET Web来调用和显示这些数据。我该怎么做呢？
这是我的密码：
ASP.NET Web代码
RestfulClient.cs
public class RestfulClient
{
private string BASE_URL = "http://localhost:8080/addition/";
public Task<string> addition()
{
{
try
{
var client = new HttpClient();
client.BaseAddress = new Uri(BASE_URL);
client.DefaultRequestHeaders.Accept.Add(
new MediaTypeWithQualityHeaderValue("application/json"));
HttpResponseMessage response = client.GetAsync("addition").Result;
return response.Content.ReadAsStringAsync();
}
catch (Exception e)
{
HttpContext.Current.Server.Transfer("ErrorPage.html");
}
return null;
}
}
}ApiController.cs
private RestfulClient restfulClient = new RestfulClient();
public ActionResult Index()
{
var Result1 = restfulClient.addition().Result;
return Content(Result1);
}Java服务代码
AdditionController.java
@RestController
public class AdditionController {
private static final String template = " %s";
private static int getSum;
@RequestMapping("/addition/{param1}/{param2}")
@ResponseBody
public Addition getSum
(@PathVariable("param1") int firstNumber,@PathVariable("param2") int secondNumber) {
return new Addition(
(String.format(template, firstNumber)), String.format(template, secondNumber));
}
} 谁来帮帮我。提前谢谢你。
回答 1
Stack Overflow用户
回答已采纳
发布于 2017-10-27 04:11:52
根据Java服务，您从客户端调用的URL没有根据您的基本URL和GetAsync中使用的URL正确格式化。
public class RestfulClient {
private static HttpClient client;
private static string BASE_URL = "http://localhost:8080/";
static RestfulClient() {
client = new HttpClient();
client.BaseAddress = new Uri(BASE_URL);
client.DefaultRequestHeaders.Accept.Add(
new MediaTypeWithQualityHeaderValue("application/json"));
}
public async Task<string> addition(int a, int b) {
try {
var endpoint = string.Format("addition/{0}/{1}", a, b);
var response = await client.GetAsync(endpoint);
return await response.Content.ReadAsStringAsync();
} catch (Exception e) {
HttpContext.Current.Server.Transfer("ErrorPage.html");
}
return null;
}
}还需要更新控制器。
public async Task<ActionResult> Index() {
int a = 9;
int b = 6;
var result = await restfulClient.addition(a, b);
return Content(result);
}注意注释中建议的HttpClient的正确使用，以及异步/等待的使用。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/46966362
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