我正在废除英格兰的联合数据,当我一次只做一家医院的工作时,我会以正确的格式得到结果。我最终想对所有医院进行迭代,但首先决定由三个不同的医院组成一个数组,并计算出迭代。
当我只有一家医院时,下面的代码给出了熊猫DataFrame的最终结果的正确格式:
import requests
from bs4 import BeautifulSoup
import pandas
import numpy as np
r=requests.get("http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?
hospitalName=Norfolk%20and%20Norwich%20Hospital")
c=r.content
soup=BeautifulSoup(c,"html.parser")
all=soup.find_all(["div"],{"class":"toggle_container"})[1]
i=0
temp = []
for item in all.find_all("td"):
if i%4 ==0:
temp.append(soup.find_all("span")[4].text)
temp.append(soup.find_all("h5")[0].text)
temp.append(all.find_all("td")[i].text.replace(" ",""))
i=i+1
table = np.array(temp).reshape(12,6)
final = pandas.DataFrame(table)
final在我的迭代版本中,我无法找到将每个结果集附加到最终DataFrame中的方法:
hosplist = ["http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Norfolk%20and%20Norwich%20Hospital",
"http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Barnet%20Hospital",
"http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Altnagelvin%20Area%20Hospital"]
temp2 = []
df_final = pandas.DataFrame()
for item in hosplist:
r=requests.get(item)
c=r.content
soup=BeautifulSoup(c,"html.parser")
all=soup.find_all(["div"],{"class":"toggle_container"})[1]
i=0
temp = []
for item in all.find_all("td"):
if i%4 ==0:
temp.append(soup.find_all("span")[4].text)
temp.append(soup.find_all("h5")[0].text)
temp.append(all.find_all("td")[i].text)
i=i+1
table = np.array(temp).reshape((int(len(temp)/6)),6)
temp2.append(table)
#df_final = pandas.DataFrame(df)最后,“表”拥有我想要的所有数据,但操作起来不容易,所以我想把它放在DataFrame中。然而,我得到一个"ValueError:必须通过2-d输入“错误。
我认为这个错误是说我有3个数组,这将使它成为三维的。这只是一个实践迭代,有超过400家医院的数据,我计划把数据,但我现在被困在这里。
发布于 2017-11-23 01:05:55
我对代码进行了一些重新组织,并且能够在不需要编码的情况下创建dataframe。
解决方案:
hosplist = ["http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Norfolk%20and%20Norwich%20Hospital",
"http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Barnet%20Hospital",
"http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Altnagelvin%20Area%20Hospital"]
temp = []
temp2 = []
df_final = pandas.DataFrame()
for item in hosplist:
r=requests.get(item)
c=r.content
soup=BeautifulSoup(c,"html.parser")
all=soup.find_all(["div"],{"class":"toggle_container"})[1]
i=0
for item in all.find_all("td"):
if i%4 ==0:
temp.append(soup.find_all("span")[4].text)
temp.append(soup.find_all("h5")[0].text)
temp.append(all.find_all("td")[i].text.replace("-","NaN").replace("+",""))
i=i+1
temp2.append(temp)
table = np.array(temp2).reshape((int(len(temp2[0])/6)),6)
df_final = pandas.DataFrame(table, columns=['h1', 'h2', 'h3', 'h4', 'h5', 'h6'])
df_final发布于 2017-11-23 00:10:55
你的问题的简单答案是HERE。
最困难的部分是拿出你的代码,找出不正确的地方。
使用完整的代码,我修改了它,如下所示。请与你的复制和区别。
import requests
from bs4 import BeautifulSoup
import pandas
import numpy as np
hosplist = ["http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Norfolk%20and%20Norwich%20Hospital",
"http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Barnet%20Hospital",
"http://www.njrsurgeonhospitalprofile.org.uk/HospitalProfile?hospitalName=Altnagelvin%20Area%20Hospital"]
temp2 = []
df_final = pandas.DataFrame()
for item in hosplist:
r=requests.get(item)
c=r.content
soup=BeautifulSoup(c,"html.parser")
all=soup.find_all(["div"],{"class":"toggle_container"})[1]
i=0
temp = []
for item in all.find_all("td"):
if i%4 ==0:
temp.append(soup.find_all("span")[4].text)
temp.append(soup.find_all("h5")[0].text)
temp.append(all.find_all("td")[i].text)
i=i+1
table = np.array(temp).reshape((int(len(temp)/6)),6)
for array in table:
newArray = []
for x in array:
try:
x = x.encode("ascii")
except:
x = 'cannot convert'
newArray.append(x)
temp2.append(newArray)
df_final = pandas.DataFrame(temp2, columns=['h1', 'h2', 'h3', 'h4', 'h5', 'h6'])
print df_final我试图为ascii转换使用一个列表理解,这对于字符串显示在dataframe中是绝对必要的,但是理解是抛出了一个错误,所以我构建了一个异常,而异常从未显示。
https://stackoverflow.com/questions/47444269
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