blocks|key|1417125|text|after()只执行一次函数，并且运行一些不使用after()再次执行函数的lambda。最好在(2000,+blink)之后和blink内部计算它被执行了多少次|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1417126|编辑：您可以在after()中使用两个函数|BOLD|1417127|blink将使用after调用remove，remove将使用after调用blink。|1417128|这样，您就可以使用它两个不同的时间来显示和隐藏数字。|1417129|import+tkinter+as+tk
from+random+import+randint

def+blink():
++++number.config(text=randint(1,10))
++++number.after(2000,+remove)+

def+remove():
++++global+repeat

++++number.config(text='')

++++repeat+-=+1
++++if+repeat+>+0:
++++++++number.after(2000,+blink)+

repeat+=+3
root+=+tk.Tk()

number+=+tk.Label(root,+width=20,+height=10)
number.pack()

blink()

root.mainloop()|code-block|syntax|javascript|1417130|entityMap^0|0|7|O|7|12|6|1C|D|1S|5|0|0|3|7|7|0|0|5|8|5|F|6|M|6|V|5|12|5|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|14|8|@$9|15|A|16|B|H]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|I|3|J|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|K|3|L|5|6|7|1M|8|@]|D|@]|E|$]]|$1|M|3|N|5|O|7|1N|8|@]|D|@]|E|$P|Q]]|$1|R|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]]|S|$]]

<code>after()</code> executes function only once and you run some <code>lambda</code> which doesn't uses <code>after()</code> to execute function again. Better use after<code>(2000, blink)</code> and inside <code>blink</code> count how many times it was executed

EDIT: you can use two functions with <code>after()</code> 

<code>blink</code> will use <code>after</code> to call <code>remove</code> and <code>remove</code> will use <code>after</code> to call <code>blink</code>. 

This way you can use it two different times to display and to hide the number.

<pre><code>import tkinter as tk
from random import randint

def blink():
 number.config(text=randint(1,10))
 number.after(2000, remove) 

def remove():
 global repeat

 number.config(text='')

 repeat -= 1
 if repeat &gt; 0:
 number.after(2000, blink) 

repeat = 3
root = tk.Tk()

number = tk.Label(root, width=20, height=10)
number.pack()

blink()

root.mainloop()
</code></pre>

blocks|key|1417152|text|见下面的例子：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1417153|import+tkinter+as+tk
import+random

def+blink():
++++if+lbl['text']:
++++++++lbl['text']+=+''
++++else:
++++++++lbl['text']+=+random.randint(1,+10)
++++++++lbl.after(1000,+blink)


root+=+tk.Tk()


lbl+=+tk.Label(root)
lbl.pack()

tk.Button(root,+text="button",+command=blink).pack()
root.mainloop()|code-block|syntax|javascript|1417154|当按下按钮时，它会生成一个随机数(如果还没有)，如果已经有一个，它会删除这个数字。|1417155|如果函数生成新的数字，则函数在1s后递归地调用自己，从而删除该数字。|1417156|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

See below example:

<pre><code>import tkinter as tk
import random

def blink():
 if lbl['text']:
 lbl['text'] = ''
 else:
 lbl['text'] = random.randint(1, 10)
 lbl.after(1000, blink)


root = tk.Tk()


lbl = tk.Label(root)
lbl.pack()

tk.Button(root, text="button", command=blink).pack()
root.mainloop()
</code></pre>

When the button is pressed it generates a random number if there's not one already, and it removes the number if there's already one.

The function also calls itself after 1s recursively if it generated new number, thus removing the number.

blocks|key|3452897|text|另一种方法是构建要显示的值列表，然后逐个显示它们：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3452898|from+tkinter+import+*
from+random+import*

display+=+['',+randint(1,10),+'',+randint(1,10),+'',+randint(1,10)]

def+blink():
++++if+display:
++++++++number.config(text=display.pop())
++++++++number.after(2000,+blink)

root+=+Tk()

number+=+Label(root,width=20,height=10)
number.pack()

blink()
root.mainloop()|code-block|syntax|javascript|3452899|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another way to do this is to build a list of values you want to display, and just display them one after the other: 

<pre><code>from tkinter import *
from random import*

display = ['', randint(1,10), '', randint(1,10), '', randint(1,10)]

def blink():
 if display:
 number.config(text=display.pop())
 number.after(2000, blink)

root = Tk()

number = Label(root,width=20,height=10)
number.pack()

blink()
root.mainloop()
</code></pre>

I'm trying to write simple GUI game in python using tkinter library. I want to generate random numbers and after each generation i want to delete this number. I put my function into a for loop so i want to call it 3 times, but it works just when i call it first. It generates the number then delete it and do not generate a new number again. Could you please explain what is the problem, i am really new to python.

<pre><code>from tkinter import *
from random import*

def blink():
 number.config(text=randint(1,10))
 number.after(2000, lambda: number.config(text=' ')) 


root = Tk()

number = Label(root,width=20,height=10)
number.pack()

for i in range(3):
 blink()

root.mainloop()
</code></pre>

Multiple calling of same function in python

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图用tkinter库在python中编写简单的GUI游戏。我想要生成随机数，每一代之后我都想删除这个数字。我把我的函数放入一个for循环中，所以我想调用它3次，但是当我首先调用它时，它就工作了。它生成数字，然后删除它，不再生成新的数字。请你解释一下问题出在哪里，我对python真的很陌生。from tkinter ...

问python中同一个函数的多次调用
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