gRPC:终止于(StatusCode.INTERNAL，接收到带有错误代码2的RST_STREAM )的会合
gRPC:终止于(StatusCode.INTERNAL，接收到带有错误代码2的RST_STREAM )的会合
提问于 2018-01-09 18:05:56
我正在用python实现gRPC客户机和服务器。服务器成功地从客户端接收数据，但客户端收到“带有错误代码2的RST_STREAM”。
它到底意味着什么，我该如何修复它？
这是我的proto文件：
service MyApi {
rpc SelectModelForDataset (Dataset) returns (SelectedModel) {
}
}
message Dataset {
// ...
}
message SelectedModel {
// ...
}My Services实现如下所示：
class MyApiServicer(my_api_pb2_grpc.MyApiServicer):
def SelectModelForDataset(self, request, context):
print("Processing started.")
selectedModel = ModelSelectionModule.run(request, context)
print("Processing Completed.")
return selectedModel我使用以下代码启动服务器：
import grpc
from concurrent import futures
#...
server = grpc.server(futures.ThreadPoolExecutor(max_workers=100))
my_api_pb2_grpc.add_MyApiServicer_to_server(MyApiServicer(), server)
server.add_insecure_port('[::]:50051')
server.start()我的当事人看起来是这样的：
channel = grpc.insecure_channel(target='localhost:50051')
stub = my_api_pb2_grpc.MyApiStub(channel)
dataset = my_api_pb2.Dataset()
# fill the object ...
model = stub.SelectModelForDataset(dataset) # call server客户端调用之后，服务器将开始处理直到完成(大约需要一分钟)，但是客户端将立即返回，其中包含以下错误：
Traceback (most recent call last):
File "Client.py", line 32, in <module>
run()
File "Client.py", line 26, in run
model = stub.SelectModelForDataset(dataset) # call server
File "/usr/local/lib/python3.5/dist-packages/grpc/_channel.py", line 484, in __call__
return _end_unary_response_blocking(state, call, False, deadline)
File "/usr/local/lib/python3.5/dist-packages/grpc/_channel.py", line 434, in _end_unary_response_blocking
raise _Rendezvous(state, None, None, deadline)
grpc._channel._Rendezvous: <_Rendezvous of RPC that terminated with (StatusCode.INTERNAL, Received RST_STREAM with error code 2)>如果我异步执行请求并等待将来，
model_future = stub.SelectModelForDataset.future(dataset) # call server
model = model_future.result()客户端等待直到完成，但在完成之后仍然返回一个错误：
Traceback (most recent call last):
File "AsyncClient.py", line 35, in <module>
run()
File "AsyncClient.py", line 29, in run
model = model_future.result()
File "/usr/local/lib/python3.5/dist-packages/grpc/_channel.py", line 276, in result
raise self
grpc._channel._Rendezvous: <_Rendezvous of RPC that terminated with (StatusCode.INTERNAL, Received RST_STREAM with error code 2)>UPD:启用跟踪GRPC_TRACE=all之后，我发现了以下内容：
客户，在请求后立即：
E0109 17:59:42.248727600 1981 channel_connectivity.cc:126] watch_completion_error: {"created":"@1515520782.248638500","description":"GOAWAY received","file":"src/core/ext/transport/chttp2/transport/chttp2_transport.cc","file_line":1137,"http2_error":0,"raw_bytes":"Server shutdown"}
E0109 17:59:42.451048100 1979 channel_connectivity.cc:126] watch_completion_error: "Cancelled"
E0109 17:59:42.451160000 1979 completion_queue.cc:659] Operation failed: tag=0x7f6e5cd1caf8, error={"created":"@1515520782.451034300","description":"Timed out waiting for connection state change","file":"src/core/ext/filters/client_channel/channel_connectivity.cc","file_line":133}
...(last two messages keep repeating 5 times every second)服务器：
E0109 17:59:42.248201000 1985 completion_queue.cc:659] Operation failed: tag=0x7f3f74febee8, error={"created":"@1515520782.248170000","description":"Server Shutdown","file":"src/core/lib/surface/server.cc","file_line":1249}
E0109 17:59:42.248541100 1975 tcp_server_posix.cc:231] Failed accept4: Invalid argument
E0109 17:59:47.362868700 1994 completion_queue.cc:659] Operation failed: tag=0x7f3f74febee8, error={"created":"@1515520787.362853500","description":"Server Shutdown","file":"src/core/lib/surface/server.cc","file_line":1249}
E0109 17:59:52.430612500 2000 completion_queue.cc:659] Operation failed: tag=0x7f3f74febee8, error={"created":"@1515520792.430598800","description":"Server Shutdown","file":"src/core/lib/surface/server.cc","file_line":1249}
... (last message kept repeating every few seconds) UPD2：
我的Server.py文件的全部内容：
import ModelSelectionModule
import my_api_pb2_grpc
import my_api_pb2
import grpc
from concurrent import futures
import time
class MyApiServicer(my_api_pb2_grpc.MyApiServicer):
def SelectModelForDataset(self, request, context):
print("Processing started.")
selectedModel = ModelSelectionModule.run(request, context)
print("Processing Completed.")
return selectedModel
# TODO(shalamov): what is the best way to run a python server?
def serve():
server = grpc.server(futures.ThreadPoolExecutor(max_workers=100))
my_api_pb2_grpc.add_MyApiServicer_to_server(MyApiServicer(), server)
server.add_insecure_port('[::]:50051')
server.start()
print("gRPC server started\n")
try:
while True:
time.sleep(24 * 60 * 60) # run for 24h
except KeyboardInterrupt:
server.stop(0)
if __name__ == '__main__':
serve()UPD3:似乎是ModelSelectionModule.run造成了这个问题。我试着把它隔离成一个单独的线程，但是没有帮助。selectedModel最终是计算出来的，但当时客户端已经不在了。如何防止此调用干扰grpc?
pool = ThreadPool(processes=1)
async_result = pool.apply_async(ModelSelectionModule.run(request, context))
selectedModel = async_result.get()这个调用相当复杂，它生成和连接许多线程，调用不同的库，如scikit-learn和smac等。如果我把所有的东西都贴在这里，那就太过分了。
在调试过程中，我发现在客户端请求之后，服务器保持两个连接处于打开状态(fd 3和fd 8)。如果我手动关闭fd 8或向它写入一些字节，我在客户机中看到的错误将变成Stream removed (而不是Received RST_STREAM with error code 2)。看来，套接字(fd 8)以某种方式被子进程破坏了。怎么可能？如何保护套接字不被子进程访问？
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-01-18 19:38:25
这是在流程处理程序中使用fork()的结果。gRPC不支持这个用例。
Stack Overflow用户
发布于 2020-01-08 08:04:29
我刚才遇到了这个问题并解决了，您使用了with_call()方法吗？
错误码：
response = stub.SayHello.with_call(request=request, metadata=metadata)反应是一个元组。
成功代码:不要使用with_call()
response = stub.SayHello(request=request, metadata=metadata)响应是响应对象。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/48174240
复制相关文章
相似问题
腾讯云开发者
