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社区首页 >问答首页 >检查4行(用Java连接4)

检查4行(用Java连接4)
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Stack Overflow用户
提问于 2018-01-29 17:20:41
回答 2查看 3.9K关注 0票数 0

我正在用Java做一个Connect 4克隆,我遇到了一些问题。我已经完成了大部分代码,但是我不知道如何检查获胜条件。这是我的代码:

代码语言:javascript
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import java.util.Scanner;

public class ConnectFour
{
    private static char board[][];
    private static final int BOARD_WIDTH = 7;
    private static final int BOARD_HEIGHT = 6;
    private static boolean gameEnd = false;
public static void main(String[] args)
{
    // Element #0 in the two-dimensional 'board' array is not used
    // so that the column numbers selected by the players match
    // with the actual internal element numbers of the array

    board = new char[BOARD_HEIGHT + 1][BOARD_WIDTH + 1];
    Scanner input = new Scanner(System.in);
    char turn = 'x';
    int dropColumn = 0;

    System.out.println("TWO PLAYER CONNECT FOUR GAME!");
    InitializeBoard();
    while (gameEnd == false)
    {
        DisplayBoard();
        dropColumn = GetDropColumn(turn, input) - 1;

        if (DropChecker(turn, dropColumn) == true)
        {
            turn = 'x' == turn ? 'o' : 'x'; //ternary operator
        }
        else {
            System.out.println("Column full. Please input again.");
        }
    }
}

// Set all elements of the two-dimensional 'board' array to spaces
private static void InitializeBoard()
{
    char a = ' ';
    for (int i = 0; i < board.length; i++)
    {
        for (int e = 0; e < board[i].length; e++)
            board[i][e] = a;
    }
}

// Display the game board (the board itself, along with the elements of
// the two-dimensional 'board' array); note that the lines of the game
// board are NOT stored in the two-dimensional 'board' array
private static void DisplayBoard()
{
    for (int row = 0; row < board.length; row++)
    {
        for (int col = 0; col < board.length; col++)
        {
            System.out.print("|");
            System.out.printf("%2c", board[row][col]);
        }
        System.out.println();
    }
}

// Get (from the appropriate player) the number (1 – 'BOARD_WIDTH') of
// the column in which a checker should be dropped, and then return that
// number; if the player does not enter an integer, report the error and
// keep asking for a column number until an integer is entered; note that
// the check for an invalid column number (< 1 or > 'BOARD_WIDTH') can be
// performed in this method or in 'main', from where this method is called
private static int GetDropColumn(char turn, Scanner input)
{
    int numInput = 0;
    int realInput = 0;
    while (realInput == 0)
    {
        try
        {
            System.out.println("Player " + turn + "'s turn: In which column would you like to place a checker? (1-7)");
            numInput = input.nextInt();
            if (numInput < 1 || numInput > BOARD_WIDTH)
            {
                numInput = 0;
                System.out.println("The number was out of bounds. Please try again.");
            }
        }
        catch (NumberFormatException e)
        {
            System.out.println("Invalid input. Please try again.");
        }
        realInput = numInput;
    }
    return realInput;
}

// "Drop" a checker into the designated column by setting the
// appropriate element of the two-dimensional 'board' array to
// either an 'x' or an 'o'; if the "drop" was successful, this
// method returns "true"; an attempt to "drop" the checker into
// a full column results in "false" being returned
private static boolean DropChecker(char turn, int dropColumn)
{
    int indexToPaceChecker = BOARD_HEIGHT;
    while (indexToPaceChecker >= 0)
    {
        if (board[indexToPaceChecker][dropColumn] == ' ')
        {
            //drop the checker
            board[indexToPaceChecker][dropColumn] = turn;
            return true;
        }
        indexToPaceChecker--;
    }
    return false;
}

// Check for a (horizontal, vertical, or diagonal) line of four
// consecutive checkers in the game board; if found, "true" is
// returned; if not found, "false" is returned
private static boolean CheckForLineOfFour()
{

}
}

我已经尝试过多种思路,但我无法让它发挥作用。如何正确地检查这一点?它需要检查垂直(这是有意义的),水平(这也有意义),但对角线检查似乎不必要的困难。

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Stack Overflow用户

回答已采纳

发布于 2018-01-30 13:35:21

请注意,如果您总是在转弯后立即检查,您知道行必须包括您刚刚放置的部分。很容易编写一种方法来计算从特定位置开始的直线长度,并沿着特定的方向进行:

代码语言:javascript
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int lengthOfLineStartingAt(int x, int y, int xStep, int yStep) {
     char colour = grid[x][y];
     int i = 0;
     while(grid[x][y] == colour) { 
        x = x + xStep;
        y = y + yStep;
        i++;
     }
     return i;
}

这假设单元格在(x,y)处设置为期望值,因此总是至少返回1。您也可以将所需的值作为参数传递。

虽然这说明了基本算法,但您需要对其进行增强,以避免数组索引超出界限的错误。

您还可以通过限制它的最大步行数4来节省一些执行时间,因为您不需要知道更长的行数。尽管Connect 4的本质意味着不可能得到一条大于7的线(当你的作品连接到现有的两行3)。

一条线可以从(x,y)开始,也可以向两个方向延伸。您可以通过以下方式获得完整的长度:

代码语言:javascript
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int lengthOfLineContaining(int x, int y, int xStep, int yStep) {
    return lengthOfLineStartingAt(x,y,xStep,yStep)
         + lengthOfLineStartingAt(x,y,-xStep,-yStep)
         - 1;
}

用纸和铅笔试一试,看看为什么会这样。

有四个xStep/yStep组合,您需要使用以下四个组合:上/下、左/右和对角。

代码语言:javascript
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boolean isFourInARow(int x, int y) {
    return 
       lengthOfLineContaining(int x, int y, 0, 1) >= 4 ||
       lengthOfLineContaining(int x, int y, 1, 1) >= 4 ||
       lengthOfLineContaining(int x, int y, 1, 0) >= 4 ||
       lengthOfLineContaining(int x, int y, 1, -1) >= 4;
}

(左作为一个练习-在一个循环中这样做。提出一个方法,将表示8个方向的数字0-7转换为0或-1的x和y值)

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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/48506672

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