blocks|key|677697|text|已更新|type|unstyled|depth|inlineStyleRanges|entityRanges|data|677698|使用此|offset|length|style|BOLD|677699|func+testingRegex6(text:String)+->String{
++++do{
++++++++var+finalText+=+text
++++++++let+componentNSString+=+NSString.init(string:text)
++++++++let+regex+=+try+NSRegularExpression(pattern:+"\\d%2B",+options:[.dotMatchesLineSeparators])
++++++++let+matches+=+regex.matches(in:+text+,options:+[],+range:+NSMakeRange(0,+componentNSString.length)).reversed()
++++++++if(matches.filter({$0.range.length+>=+3}).count+>+0)+{+//here+we+check+if+we+have+any+substring+containing+3+o+more+digits
++++++++++++for+result3+in+matches+{
++++++++++++++++finalText+=+finalText.replacingOccurrences(of:+componentNSString.substring(with:+result3.range),+with:+Array(repeating:+"X",+count:+result3.range.length).joined())
++++++++++++}
++++++++}
++++++++return+finalText
++++}
++++catch{
++++++++return+""
++++}
++++return+""
}|code-block|syntax|javascript|677700|输入+"abcdef+12+quews+4567“Log+"abcdef+XX+quews+XXXX”
输入+"abcdef+12+que82ws+45“Log+"abcdef+12+que82ws+45”|blockquote|677701|entityMap^0|0|0|3|0|0|0|2|P|3|1G|2|25|3|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|V|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|O|7|W|8|@$D|X|E|Y|F|G]|$D|Z|E|10|F|G]|$D|11|E|12|F|G]|$D|13|E|14|F|G]]|9|@]|A|$]]|$1|P|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|Q|$]]

<h1>UPDATED</h1>
Use this
<pre><code>func testingRegex6(text:String) -&gt;String{
 do{
 var finalText = text
 let componentNSString = NSString.init(string:text)
 let regex = try NSRegularExpression(pattern: &quot;\\d+&quot;, options:[.dotMatchesLineSeparators])
 let matches = regex.matches(in: text ,options: [], range: NSMakeRange(0, componentNSString.length)).reversed()
 if(matches.filter({$0.range.length &gt;= 3}).count &gt; 0) { //here we check if we have any substring containing 3 o more digits
 for result3 in matches {
 finalText = finalText.replacingOccurrences(of: componentNSString.substring(with: result3.range), with: Array(repeating: &quot;X&quot;, count: result3.range.length).joined())
 }
 }
 return finalText
 }
 catch{
 return &quot;&quot;
 }
 return &quot;&quot;
}
</code></pre>
<blockquote>
Input &quot;abcdef 12 quews 4567&quot; Log &quot;abcdef XX quews XXXX&quot;
Input &quot;abcdef 12 que82ws 45&quot; Log &quot;abcdef 12 que82ws 45&quot;
</blockquote>

blocks|key|2313462|text|用这个，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2313463|let+testString+=+"abcdef+12+quews+4567"
let+output+=+testString.replacingOccurrences(of:+"[\\[\\]%5E[0-9]]",+with:+"X",+options:+.regularExpression,+range:+nil)

print(output)|code-block|syntax|javascript|2313464|你的输出是这样的，|2313465|abcdef+XX+quews+XXXX|2313466|更新|offset|length|style|BOLD|2313467|查找字符串扩展类，|2313468|extension+String+{
++++func+matches(for+regex:+String)+->+[String]+{
++++++++do+{
++++++++++++let+regex+=+try+NSRegularExpression(pattern:+regex)
++++++++++++let+results+=+regex.matches(in:+self,+range:+NSRange(self.startIndex...,+in:+self))
++++++++++++return+results.map+{
++++++++++++++++String(self[Range($0.range,+in:+self)!])
++++++++++++}
++++++++}+catch+let+error+{
++++++++++++print("invalid+regex:+\(error.localizedDescription)")
++++++++++++return+[]
++++++++}
++++}
}|2313469|找到下面的代码，|2313470|let+temp+=+"abc44def+12+quews+4564+1254"
let+array+=+temp.matches(for:+"\\d{3,}")
var+output+=+temp

for+val+in+array.enumerated()+{
+++var+string+=+""
+++for+_+in+0..<val.element.count+{
++++++string%2B="X"
+++}
+++output+=+output.replacingOccurrences(of:+val.element,+with:+string)
}
print(output)|2313471|你会得到这样的输出，|2313472|abc44def+12+quews+XXXX+XXXX|2313473|entityMap^0|0|0|0|0|0|2|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|18|8|@$M|19|N|1A|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|1D|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1E|8|@]|9|@]|A|$E|F]]|$1|Y|3|Z|5|6|7|1F|8|@]|9|@]|A|$]]|$1|10|3|11|5|D|7|1G|8|@]|9|@]|A|$E|F]]|$1|12|3|-4|5|6|7|1H|8|@]|9|@]|A|$]]]|13|$]]

Use this,

<pre><code>let testString = "abcdef 12 quews 4567"
let output = testString.replacingOccurrences(of: "[\\[\\]^[0-9]]", with: "X", options: .regularExpression, range: nil)

print(output)
</code></pre>

Your output looks like this,

<pre><code>abcdef XX quews XXXX
</code></pre>

Update

Find String extension class,

<pre><code>extension String {
 func matches(for regex: String) -&gt; [String] {
 do {
 let regex = try NSRegularExpression(pattern: regex)
 let results = regex.matches(in: self, range: NSRange(self.startIndex..., in: self))
 return results.map {
 String(self[Range($0.range, in: self)!])
 }
 } catch let error {
 print("invalid regex: \(error.localizedDescription)")
 return []
 }
 }
}
</code></pre>

and find below code,

<pre><code>let temp = "abc44def 12 quews 4564 1254"
let array = temp.matches(for: "\\d{3,}")
var output = temp

for val in array.enumerated() {
 var string = ""
 for _ in 0..&lt;val.element.count {
 string+="X"
 }
 output = output.replacingOccurrences(of: val.element, with: string)
}
print(output)
</code></pre>

you will get output like this,

<pre><code>abc44def 12 quews XXXX XXXX
</code></pre>

blocks|key|677754|text|和雷格在一起。表达式|type|unstyled|depth|inlineStyleRanges|entityRanges|data|677755|let+txt+=+"abc+12+wqer+987asd+asdf1233sadf"
do+{
++++let+regx+=+try+NSRegularExpression(pattern:+"[0-9]",+options:+.caseInsensitive)

++++let+result+=+regx.stringByReplacingMatches(in:+txt,+options:+.withTransparentBounds,+range:+NSMakeRange(0,+txt.count),+withTemplate:+"X")

++++print(result)

}+catch+{
++++print(error)
}|code-block|syntax|javascript|677756|没有reg。表达式|677757|let+txt+=+"abc+12+wqer+987asd+asdf1233sadf"

let+replacedStr+=+String(txt.map+{

++let+c+=+String($0)
++if+let+digit+=+Int(c),+digit+>=+0,+digit+<=+9+{
++++++return+"X"
++}+else+{
++++++return+$0
++}
})
print(replacedStr)|677758|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

With Reg. expression

<pre><code>let txt = "abc 12 wqer 987asd asdf1233sadf"
do {
 let regx = try NSRegularExpression(pattern: "[0-9]", options: .caseInsensitive)

 let result = regx.stringByReplacingMatches(in: txt, options: .withTransparentBounds, range: NSMakeRange(0, txt.count), withTemplate: "X")

 print(result)

} catch {
 print(error)
}
</code></pre>

Without reg. expression

<pre><code>let txt = "abc 12 wqer 987asd asdf1233sadf"

let replacedStr = String(txt.map {

 let c = String($0)
 if let digit = Int(c), digit &gt;= 0, digit &lt;= 9 {
 return "X"
 } else {
 return $0
 }
})
print(replacedStr)
</code></pre>

blocks|key|3727133|text|let+str+=+"this+is+123+my+vie22w"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3727134|将字符串转换为字符串数组|unstyled|3727135|let+characters+=+Array(str)|3727136|如果数字大于3，则使用带计数器的循环和替换字符串。|3727137|var+count+=+0
for+i+in+characters+{

+++++if+i+>=+"0"+&&+i+<=+"9"+{
+++++++++count+%2B=+1
++++++}
}
if+count+>+3+{

+let+output+=+str.replacingOccurrences(of:+"[\\[\\]%5E[0-9]]",+with:+"X",+options:+.regularExpression,+range:+nil)
++++++++print(output)
}|3727138|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>let str = "this is 123 my vie22w"
</code></pre>

Convert string into string array

<pre><code>let characters = Array(str)
</code></pre>

Use loop with counter and replace string if digits are more than 3.

<pre><code>var count = 0
for i in characters {

 if i &gt;= "0" &amp;&amp; i &lt;= "9" {
 count += 1
 }
}
if count &gt; 3 {

 let output = str.replacingOccurrences(of: "[\\[\\]^[0-9]]", with: "X", options: .regularExpression, range: nil)
 print(output)
}
</code></pre>

blocks|key|2313570|text|谢谢你所有的答案，通过你的输入，我能够用下面的代码来解决这个问题|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2313571|extension+String+{

++++func+replaceDigits()+->+String+{
++++++++do+{
++++++++++++let+regex+=+try+NSRegularExpression(pattern:+"\\d{3,}",+options:+[])
++++++++++++let+matches+=+regex.numberOfMatches(in:+self,+options:+[],+range:+NSRange(location:+0,+length:+self.count))
++++++++++++if+matches+>+0+{
++++++++++++++++return+replacingOccurrences(of:+"\\d",+with:+"X",+options:+.regularExpression,+range:+nil)
++++++++++++}
++++++++}+catch+{
++++++++++++return+self
++++++++}
++++++++return+self
++++}
}|code-block|syntax|javascript|2313572|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Thank you for all your answers, with all your inputs I was able to solve this with following code

<pre><code>extension String {

 func replaceDigits() -&gt; String {
 do {
 let regex = try NSRegularExpression(pattern: "\\d{3,}", options: [])
 let matches = regex.numberOfMatches(in: self, options: [], range: NSRange(location: 0, length: self.count))
 if matches &gt; 0 {
 return replacingOccurrences(of: "\\d", with: "X", options: .regularExpression, range: nil)
 }
 } catch {
 return self
 }
 return self
 }
}
</code></pre>

I am new to regular expressions and need to perform a specific task with the same. I would require a regex that performs global search and checks if there are 3 or more consecutive digits in a string and if yes, then replaces all the digits with "xxxx".

For example, the string

<blockquote>
 abcdef 12 quews 4567
</blockquote>

should be changed to 

<blockquote>
 abcdef XX quews XXXX
</blockquote>

Any help would be appreciated. Thanks.

Regex to find and replace digits

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我对正则表达式很陌生，需要用正则表达式来执行特定的任务。我需要一个正则表达式来执行全局搜索，并检查字符串中是否有3个或更多的连续数字，如果是，则将所有数字替换为"xxxx“。例如，字符串abcdef 12 quews 4567应改为abcdef XX quews XXXX任何帮助都将不胜感激。谢谢。

问查找和替换数字的Regex
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