有没有办法用字符串中的单个数字替换数字的范围?数字可以从n-n,很可能在1-15,4-10也有可能。
范围可以用a表示)-
a <- "I would like to buy 1-3 cats"
或加上一个词b),例如: to,bis,jusqu'à
b <- "I would like to buy 1 jusqu'à 3 cats"
结果应该是
"I would like to buy 1,2,3 cats"
我发现了这个:Replace range of numbers with certain number,但在R中不能真正使用它。
发布于 2018-03-18 03:41:02
事实上,这有点棘手,除非有人已经编写了这样的包(我不知道)。
a <- "I would like to buy 1-3 cats"
pos <- unlist(gregexpr("\\d+\\D+", a))
a_split <- unlist(strsplit(a, ""))
replacement <- paste(seq.int(a_split[pos[1]], a_split[pos[2]]), collapse = ",")
gsub("\\d+\\D+\\d+", replacement, a)
# [1] "I would like to buy 1,2,3 cats"
编辑:要显示相同的解决方案适用于两个数字之间的任意非数字字符:
b <- "I would like to buy 1 jusqu'à 3 cats"
pos_b <- unlist(gregexpr("\\d+\\D+", b))
b_split <- unlist(strsplit(b, ""))
replacement <- paste(seq.int(b_split[pos_b[1]], b_split[pos_b[2]]), collapse = ",")
gsub("\\d+\\D+\\d+", replacement, b)
# [1] "I would like to buy 1,2,3 cats"
如果愿意,可以为非数字字符的运行添加任意要求。如果你需要帮助,只需分享在数字之间的单词或符号的限制!
发布于 2018-03-18 03:41:11
不是最有效率的但是..。
s <- c("I would like to buy 1-3 cats",
"I would like to buy 1 jusqu'à 3 cats",
"foo 22-33",
"quux 11-3 bar")
gre <- gregexpr("([0-9]+(-| to | bis | jusqu'à )[0-9]+)", s)
gre2 <- gregexpr('[0-9]+', regmatches(s, gre))
regmatches(s, gre) <- lapply(regmatches(regmatches(s, gre), gre2),
function(a) paste(do.call(seq, as.list(as.integer(a))), collapse = ","))
s
# [1] "I would like to buy 1,2,3 cats" "I would like to buy 1,2,3 cats"
# [3] "foo 22,23,24,25,26,27,28,29,30,31,32,33" "quux 11,10,9,8,7,6,5,4,3 bar"
https://stackoverflow.com/questions/49344140
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