解析日志并存储Dict
解析日志并存储Dict
提问于 2018-04-06 19:55:29
BGP日志文件: bgplog.log
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of BGP UPDATE messages received changed from '110376' to '110393'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of BGP UPDATE messages received changed from '133736' to '134146'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of BGP UPDATE messages sent changed from '108252' to '108348'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of BGP UPDATE messages sent changed from '2094' to '2132'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.103: the number of BGP UPDATE messages sent changed from '91440' to '91462'
Host local.domain.net [11.130.55.2] with interface to BGP peer eth1-local.domain.net [11.8.44.10]: the number of BGP UPDATE messages sent changed from '1411' to '1413'
Host local.domain.net [11.130.55.2] with interface to BGP peer 10.81.244.18: the number of BGP UPDATE messages sent changed from '112347' to '112506'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of messages received from the remote peer changed from '538672' to '538691'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of messages received from the remote peer changed from '547397' to '547814'目标：
- 找出具体的IP，比方说: 11.130.44.93
- 任何行都与上面的IP匹配，拆分行并将某些值存储到每个键中。
- 按密钥排序
下面是我尝试过的代码:似乎我被卡住了
import re
import os
def find(line):
findThis = ""
found = re.match(r'.*?11.130.44.103.*', line)
# Find is true:
if found:
# found a item and adds in to findThis
findThis = found.group()
else:
findThis = "NONE"
return findThis
def generateDicts(log):
currentDict = {}
for line in log:
if line.startswith(find(line)):
currentDict = {
"host": line.split(" ")[1][:24],
"ip": line.split(" ", 9)[2],
"peer": line.split(" ")[8],
"info": line.split(" ", 9)[-1]}
else:
# currentDict = {"info":line.split("-",6)[-1]}
currentDict = line
with open("bgplog.txt") as f:
print list(generateDicts(f))我只得到最后一个值，不知怎么的，它不是附加的。什么是最好的方法？
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-04-06 20:27:58
我猜您需要一个生成器，在这种情况下，您需要使用yield关键字。试试这个：
def generateDicts(log):
for line in log:
if line.startswith(find(line)):
yield {
"host": line.split(" ")[1][:24],
"ip": line.split(" ", 9)[2],
"peer": line.split(" ")[8],
"info": line.split(" ", 9)[-1]}Stack Overflow用户
发布于 2018-04-06 20:48:01
一种方法可以是在列表中附加这个数据集。不使用regex如果没有必要..。
with open("bgplog.txt") as log:
ip_to_search = '11.130.55.2'
result = []
for log_line in log:
if ip_to_search in log_line:
currentDict = {
"host": log_line.split(" ")[1][:24],
"ip": log_line.split(" ", 9)[2],
"peer": log_line.split(" ")[8],
"info": log_line.split(" ", 9)[-1]}
result.append(currentDict)
for element in result:
print(element)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/49700164
复制相关文章
相似问题
腾讯云开发者
