blocks|key|155593|text|没有从XML到JSON的直接转换。对于这个响应，您应该使用XML解析器。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|155594|解析XML+(C#)：|offset|length|style|BOLD|155595|https://learn.microsoft.com/en-us/dotnet/csharp/programming-guide/concepts/linq/parsing-xml|155596|我还建议多读一些关于序列化的内容，因为这个问题实际上是毫无意义的。|155597|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|A|0|0|2J|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@$D|U|E|V|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@]|9|@$D|X|E|Y|1|Z]]|A|$]]|$1|J|3|K|5|6|7|10|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|M|$N|$5|O|P|Q|A|$R|I]]]]

There is no direct conversion from XML to JSON. And you should be using a XML parser for this response.

Parsing XML (C#) :

<a href="https://learn.microsoft.com/en-us/dotnet/csharp/programming-guide/concepts/linq/parsing-xml" rel="nofollow noreferrer">https://learn.microsoft.com/en-us/dotnet/csharp/programming-guide/concepts/linq/parsing-xml</a>

I also suggest reading a little bit more about serialization, since this question actually makes no sense.

blocks|key|1266153|text|任何将JSON作为输入并返回XML作为响应的webapi都会让我非常困惑。但是，如果这正是您所要看到的，那么您需要采取将该XML响应序列化为XmlDocument或更新的XDocument/XNode的方法，然后将其中一个实例序列化为JSON。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1266154|XmlDocument类型有一个使用XmlReader的加载方法。(它还提供了一个LoadXml。|offset|length|style|CODE|1266155|XDocument类型有一个使用XML的字符串的解析方法。|1266156|根据示例输入，可以使用两种方法：|1266157|var+xml+=+@"<response>
++++<data>
++++++++<status+no=""0""+substatus=""0"">
+++++++++++Connection+succeeded
++++++++</status>
++++</data>
</response>";

//+xmldocument
var+xmlReader+=+XmlReader.Create(new+StringReader(xml));
var+doc+=+new+XmlDocument();
doc.Load(xmlReader);
var+response+=+JsonConvert.SerializeXmlNode(doc);

response.Dump("XMLDoc+to+Json+");+//+LINQPad+output

//+or+XDOcument

response+=+JsonConvert.SerializeXNode(XDocument.Parse(xml));

response.Dump("XDocument+to+Json");//+LINQPad+output|code-block|syntax|javascript|1266158|这将是一个结果：|1266159|​|1266160|📷|atomic|1266161|1266162|entityMap|0|LINK|mutability|MUTABLE|url|https://msdn.microsoft.com/en-us/library/a8ta6tz4(v=vs.110).aspx|1|https://msdn.microsoft.com/en-us/library/system.xml.xmldocument.loadxml(v=vs.110%2529.aspx)%2520but%2520I%2520wanted%2520to%2520show%2520several%2520options%2520here|2|https://msdn.microsoft.com/en-us/library/bb345532(v=vs.110).aspx|3|IMAGE|IMMUTABLE|imageUrl|https://developer.qcloudimg.com/http-save/yehe-900000/223e0662e908ac35d736c5cb5263f19e.png|imageAlt^0|0|15|7|S|2|0|15|7|1|0|O|2|2|0|0|0|0|0|0|1|3|0|0^^$0|@$1|2|3|4|5|6|7|1G|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1H|8|@$D|1I|E|1J|F|G]]|9|@$D|1K|E|1L|1|1M]|$D|1N|E|1O|1|1P]]|A|$]]|$1|H|3|I|5|6|7|1Q|8|@]|9|@$D|1R|E|1S|1|1T]]|A|$]]|$1|J|3|K|5|6|7|1U|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|1V|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|1W|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|1X|8|@]|9|@]|A|$]]|$1|U|3|V|5|W|7|1Y|8|@]|9|@$D|1Z|E|20|1|21]]|A|$]]|$1|X|3|T|5|6|7|22|8|@]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|23|8|@]|9|@]|A|$]]]|Z|$10|$5|11|12|13|A|$14|15]]|16|$5|11|12|13|A|$14|17]]|18|$5|11|12|13|A|$14|19]]|1A|$5|1B|12|1C|A|$1D|1E|1F|-4]]]]

I would be highly confused by any webapi that expect JSON as input and return XML as its response. But if that is really what you're looking at then you need to take the approach in Serializing that XML response into either an XmlDocument or the newer XDocument/XNode and then Serialize an instance of one of those into JSON. 

The XmlDocument type has a <a href="https://msdn.microsoft.com/en-us/library/a8ta6tz4(v=vs.110).aspx" rel="nofollow noreferrer">Load</a> method that consumes a XmlReader. (it also offers a <a href="https://msdn.microsoft.com/en-us/library/system.xml.xmldocument.loadxml(v=vs.110).aspx" rel="nofollow noreferrer"><code>LoadXml</code></a> but I wanted to show several options here).

The XDocument type has a <a href="https://msdn.microsoft.com/en-us/library/bb345532(v=vs.110).aspx" rel="nofollow noreferrer">Parse</a> method that consumes a string with XML.

Based on your example input you can use two approaches:

<pre><code>var xml = @"&lt;response&gt;
 &lt;data&gt;
 &lt;status no=""0"" substatus=""0""&gt;
 Connection succeeded
 &lt;/status&gt;
 &lt;/data&gt;
&lt;/response&gt;";

// xmldocument
var xmlReader = XmlReader.Create(new StringReader(xml));
var doc = new XmlDocument();
doc.Load(xmlReader);
var response = JsonConvert.SerializeXmlNode(doc);

response.Dump("XMLDoc to Json "); // LINQPad output

// or XDOcument

response = JsonConvert.SerializeXNode(XDocument.Parse(xml));

response.Dump("XDocument to Json");// LINQPad output
</code></pre>

And this will be the result:

<a href="https://i.stack.imgur.com/JV93u.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/JV93u.png" alt="enter image description here"></a>

blocks|key|1266183|text|我已经解决了这个问题。rene的回答有助于理解如何从xml转换到json。但问题在于我的反应。我能够通过从响应中删除/“和不必要的双引号来修复它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1266184|+response+=+response.Replace("<response>\"",+"<response>")
+++++++++++++++++.Replace("\"<response>",+"<response>")
+++++++++++++++++.Replace("\\",+"")
+++++++++++++++++.Replace("rn",+string.Empty);

var+xmlReader+=+XmlReader.Create(new+StringReader(response));
var+doc+=+new+XmlDocument();
doc.Load(xmlReader);

var+jsonResponse+=+JsonConvert.SerializeXmlNode(doc);|code-block|syntax|javascript|1266185|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I have figured out the issue. rene's answer helped to figure out the how to convert from xml to json. But the issue was with my response. I was able to fix it by removing the /" and unwanted double quotes from the response.

<pre><code> response = response.Replace("&lt;response&gt;\"", "&lt;response&gt;")
 .Replace("\"&lt;response&gt;", "&lt;response&gt;")
 .Replace("\\", "")
 .Replace("rn", string.Empty);

var xmlReader = XmlReader.Create(new StringReader(response));
var doc = new XmlDocument();
doc.Load(xmlReader);

var jsonResponse = JsonConvert.SerializeXmlNode(doc);
</code></pre>

I'm working on project where i have to make an API request. When I post a JSON request to the server I get the following XML as response:

<pre><code>"&lt;response&gt;
 \r\n 
 &lt;data&gt;
 \r\n 
 &lt;status no=\"0\" substatus=\"0\"&gt;
 Connection succeeded
 &lt;/status&gt;\r\n 
 &lt;/data&gt;
 \r\n
&lt;/response&gt;"
</code></pre>

I need to convert the response back to JSON. But when I try to parse it i'm getting an error saying

<blockquote>
 'Unexpected character encountered while parsing value: &lt;. Path '',
 line 0, position 0.'
</blockquote>

I'm using NewtonSoftJSON for conversion.

This is the code I'm using to convert the XML string back to JSON: 

<pre><code>var response = JsonConvert.DeserializeXmlNode(xmlResponse);
</code></pre>

How can I achieve this?

Parsing a XML response back to JSON

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在做一个项目，在那里我必须提出一个API请求。当我向服务器发送JSON请求时，我得到以下XML作为响应："<response> \r\n <data> \r\n <status no=\"0\" substatus=\"0\"> Connectio...

问将XML响应解析回JSON
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