当试图将char数组的元素转换为int时出错
当试图将char数组的元素转换为int时出错
提问于 2018-05-28 12:57:18
下面是我到目前为止使用的代码：
public static String encrypt(String password) {
String encrypted = null;
char passChars[] = password.toCharArray();
int ascii[] = null;
for(int i=0;i<passChars.length;i++) {
ascii[i] = Integer.parseInt(String.valueOf(passChars[i]));
ascii[i] = ascii[i] + 17;
passChars[i] = (char)ascii[i];
encrypted = encrypted + String.valueOf(passChars[i]);
}
return encrypted;
}当我试图运行它时，它正在运行，但是当我使用encrypt方法时，我得到了以下错误：
Exception in thread "AWT-EventQueue-0" java.lang.NumberFormatException: For input string: "M"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at com.package.program.Encryptor.encrypt(Encrypter.java:46)
at com.package.program.Main$3.actionPerformed(Main.java:136)
at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
at javax.swing.AbstractButton$Handler.actionPerformed(Unknown Source)
at javax.swing.DefaultButtonModel.fireActionPerformed(Unknown Source)
at javax.swing.DefaultButtonModel.setPressed(Unknown Source)
at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(Unknown Source)
at java.awt.Component.processMouseEvent(Unknown Source)
at javax.swing.JComponent.processMouseEvent(Unknown Source)
at java.awt.Component.processEvent(Unknown Source)
at java.awt.Container.processEvent(Unknown Source)
at java.awt.Component.dispatchEventImpl(Unknown Source)
at java.awt.Container.dispatchEventImpl(Unknown Source)
at java.awt.Component.dispatchEvent(Unknown Source)
at java.awt.LightweightDispatcher.retargetMouseEvent(Unknown Source)
at java.awt.LightweightDispatcher.processMouseEvent(Unknown Source)
at java.awt.LightweightDispatcher.dispatchEvent(Unknown Source)
at java.awt.Container.dispatchEventImpl(Unknown Source)
at java.awt.Window.dispatchEventImpl(Unknown Source)
at java.awt.Component.dispatchEvent(Unknown Source)
at java.awt.EventQueue.dispatchEventImpl(Unknown Source)
at java.awt.EventQueue.access$500(Unknown Source)
at java.awt.EventQueue$3.run(Unknown Source)
at java.awt.EventQueue$3.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(Unknown Source)
at java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(Unknown Source)
at java.awt.EventQueue$4.run(Unknown Source)
at java.awt.EventQueue$4.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(Unknown Source)
at java.awt.EventQueue.dispatchEvent(Unknown Source)
at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.run(Unknown Source)我试过改变一些东西，比如改变它的字符转换成int的方式，但是似乎没有什么效果.我做错了什么？
回答 3
Stack Overflow用户
回答已采纳
发布于 2018-05-28 13:00:51
如果您想通过对每个字符进行一定量的偏移来“加密”字符串，那么只需直接这样做：
String encrypted = null;
char passChars[] = password.toCharArray();
for (int i=0; i < passChars.length; i++) {
passChars[i] += 17;
}
encrypted = new String(passChars);
Demo
请注意，在某些ASCII字符中添加17个字符可能会使您遇到一些不可打印的东西。这里还不清楚你想要实现什么；如果你想系统地把密码加到其他字符中，那么我们可能得用模数来包装。
Stack Overflow用户
发布于 2018-05-28 13:03:32
这句话是错的：
ascii[i] = Integer.parseInt(String.valueOf(passChars[i]));你想把密码的字母转换成整数。不能保证密码只由数字组成。
相反，您可以这样做：
ascii[i] = passChars[i] + 17;直接了当。
Stack Overflow用户
发布于 2018-05-28 13:09:39
用有效的大小初始化ascii[]，否则，您可能会将索引排除在绑定异常之外，此程序将仅作为数字字符串用于密码。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50567054
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