空手道阵列场成为目标
空手道阵列场成为目标
提问于 2018-05-29 09:05:58
我有个很奇怪的问题。
我想把两个列表添加到一个列表中，但是似乎Karate不支持这个函数，所以我编写了一个JS函数。
function(lists){
var arr = []
for each (var list in lists){
for each (var item in list){
arr.push(item);
}
}
return arr;
}我编写了这个特性文件用于测试：
Feature:
Scenario:
* def appendList = read('../utils/append-list.js')
* def arr = [{a: 'a'}, {b: 'b'}, {c: 'c'}]
* def arr1 = [{a: 'a'}, {b: 'b'}, {c: 'c'}]
* def arr2 = appendList([arr, arr1])
* print 'arr2', arr2
* def xx = { aa: '#(arr2)' }
* print 'xx', xx
* copy yy = xx
* print 'yy', yy
* match xx == yy这是日志：
16:00:28.424 [main] INFO com.intuit.karate - [print] arr2 [
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
},
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
}
]
16:00:28.444 [main] INFO com.intuit.karate - [print] xx {
"aa": {
"0": {
"a": "a"
},
"1": {
"b": "b"
},
"2": {
"c": "c"
},
"3": {
"a": "a"
},
"4": {
"b": "b"
},
"5": {
"c": "c"
}
}
}
16:00:28.466 [main] INFO com.intuit.karate - [print] yy {
"aa": [
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
},
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
}
]
}
16:00:28.469 [main] ERROR com.intuit.karate - assertion failed: path: $.aa, actual: [object Array], expected: [{"a":"a"},{"b":"b"},{"c":"c"},{"a":"a"},{"b":"b"},{"c":"c"}], reason: actual value is not list-like
com.intuit.karate.exception.KarateException: path: $.aa, actual: [object Array], expected: [{"a":"a"},{"b":"b"},{"c":"c"},{"a":"a"},{"b":"b"},{"c":"c"}], reason: actual value is not list-like
at com.intuit.karate.StepDefs.matchNamed(StepDefs.java:540)
at com.intuit.karate.StepDefs.matchEquals(StepDefs.java:526)
at ✽.* match xx == yy(kromotus/test/test.feature:12)
com.intuit.karate.exception.KarateException: path: $.aa, actual: [object Array], expected: [{"a":"a"},{"b":"b"},{"c":"c"},{"a":"a"},{"b":"b"},{"c":"c"}], reason: actual value is not list-like
at com.intuit.karate.StepDefs.matchNamed(StepDefs.java:540)
at com.intuit.karate.StepDefs.matchEquals(StepDefs.java:526)
at ✽.* match xx == yy(kromotus/test/test.feature:12)我不明白为什么有时数组是数组，有时它变成对象？
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-05-29 13:49:51
您可以尝试将JavaScript函数中的返回数据转换为JSON。下面是我所理解的空手道上发生的事情：
* def appendList = read('../utils/append-list.js')
* def arr = [{a: 'a'}, {b: 'b'}, {c: 'c'}]
* def arr1 = [{a: 'a'}, {b: 'b'}, {c: 'c'}]
* def arr2 = appendList([arr, arr1]) # return JS[] variable type instead of JSON object
* print 'arr2', arr2
* def xx = { aa: '#(arr2)' }
* print 'xx', xx
* copy yy = xx
* print 'yy', yy
* match xx == yy下面是如何修复它：
* def appendList = read('append-list.js')
* json arr = [{a: 'a'}, {b: 'b'}, {c: 'c'}]
* json arr1 = [{a: 'a'}, {b: 'b'}, {c: 'c'}]
* json arr2 = appendList([arr, arr1]) # convert to JSON
* print 'arr2', arr2
* json xx = { aa: '#(arr2)' }
* print 'xx', xx
* copy yy = xx
* print 'yy', yy
* match xx == yy日志信息：
20:37:02.034 [main] WARN com.intuit.karate - skipping bootstrap configuration: could not find or read file: karate-config.js, prefix: CLASSPATH
20:37:02.139 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.142 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.149 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.149 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.168 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.169 [main] INFO com.intuit.karate - [print] arr2 [
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
},
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
}
]
20:37:02.173 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.177 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.178 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $['aa']
20:37:02.179 [main] DEBUG com.jayway.jsonpath.internal.JsonContext - Set path $['aa'] new value [{a=a}, {b=b}, {c=c}, {a=a}, {b=b}, {c=c}]
20:37:02.182 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.183 [main] INFO com.intuit.karate - [print] xx {
"aa": [
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
},
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
}
]
}
20:37:02.188 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.188 [main] INFO com.intuit.karate - [print] yy {
"aa": [
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
},
{
"a": "a"
},
{
"b": "b"
},
{
"c": "c"
}
]
}
20:37:02.189 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
20:37:02.189 [main] DEBUG com.jayway.jsonpath.internal.path.CompiledPath - Evaluating path: $
1 Scenarios ([32m1 passed[0m)
10 Steps ([32m10 passed[0m)
0m0.680s
html report: (paste into browser to view)
Stack Overflow用户
发布于 2018-05-29 10:08:56
是的，在默认情况下，JSON在内部转换为Java列表，这可能会让人感到困惑。最佳实践是尽可能使用'Java样式‘。在迭代时，使用带索引的for-循环。例如，尝试以下几个：
* def first = [{a: 1}, {b: 2}]
* def second = [{c: 3}, {d: 4}]
* eval first.addAll(second)
* print first这与上面的效果相同，但更令人费解：
* def append = function(f, s){ for (var i = 0; i < s.length; i++) { f.add(s[i]) }; return f }
* def first = [{a: 1}, {b: 2}]
* def second = [{c: 3}, {d: 4}]
* def result = append(first, second)
* print result注意，我们使用的是Java List.add()和List.addAll()方法，而不是JS push。当然，您可以编写您的自定义函数，在幕后完成此操作。
顺便说一句，空手道的下一个版本将引入karate.forEach，甚至map和filter操作，以使迭代更容易。也许我们需要一个karate.append()和karate.merge() (用于合并2个JSON对象)。请随时提出特性请求。
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原文链接：
https://stackoverflow.com/questions/50580415
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