我已经查过了,我认为我应该工作,但它不是,第一个条件(>= 80)正在评估,而第二个(<= 100)不是。
我希望每一行的任何列值都包含在80到100之间,但是,如果任何列值大于100,则排除它。
我应该只看到AP-2,AP-8和AP-9行。
import pandas as pd
df = pd.DataFrame({'AP-1': [30, 32, 34, 31, 33, 35, 36, 38, 37],
'AP-2': [30, 32, 34, 80, 33, 35, 36, 38, 37],
'AP-3': [30, 32, 81, 31, 33, 101, 36, 38, 37],
'AP-4': [30, 32, 34, 95, 33, 35, 103, 38, 121],
'AP-5': [30, 32, 34, 31, 33, 144, 36, 38, 37],
'AP-6': [30, 32, 34, 31, 33, 35, 36, 110, 37],
'AP-7': [30, 87, 34, 31, 111, 35, 36, 38, 122],
'AP-8': [30, 32, 99, 31, 33, 35, 36, 38, 37],
'AP-9': [30, 32, 34, 31, 33, 99, 88, 38, 37]}, index=['1', '2', '3', '4', '5', '6', '7', '8', '9'])
df1 = df.transpose()
print(df1)
print()
df2 = df1[(df1.values >= 80).any(1) & (df1.values <= 100).any(1)]
print(df2)
df2将以:1 2 3 4 5 6 7 8 9 AP-2 30 32 34 80 33 35 36 38 37 AP-3 30 32 81 31 33 101 36 38 37 AP-4 30 32 34 95 33 35 103 38 121 AP-5 30 32 34 31 33 144 36 38 37 AP-6 30 32 34 31 33 35 36 110 37 AP-7 30 87 34 31 111 35 36 38 122 AP-8 30 32 99 31 33 35 36 38 37 AP-9 30 32 34 31 33 99 88 38 37
的形式出现
发布于 2018-07-07 17:20:33
下面是另一个想法,分离掩码并使用&连接:
import pandas as pd
df = pd.DataFrame({'AP-1': [30, 32, 34, 31, 33, 35, 36, 38, 37],
'AP-2': [30, 32, 34, 80, 33, 35, 36, 38, 37],
'AP-3': [30, 32, 81, 31, 33, 101, 36, 38, 37],
'AP-4': [30, 32, 34, 95, 33, 35, 103, 38, 121],
'AP-5': [30, 32, 34, 31, 33, 144, 36, 38, 37],
'AP-6': [30, 32, 34, 31, 33, 35, 36, 110, 37],
'AP-7': [30, 87, 34, 31, 111, 35, 36, 38, 122],
'AP-8': [30, 32, 99, 31, 33, 35, 36, 38, 37],
'AP-9': [30, 32, 34, 31, 33, 99, 88, 38, 37]},
index=['1', '2', '3', '4', '5', '6', '7', '8', '9'])
# This is the actual frame you want
df = df.transpose()
m1 = (df >= 80).any(1)
m2 = ~(df >= 100).any(1) #<-- Invert the statement with ~
df2 = df.loc[m1&m2]
print(df2)
指纹:
1 2 3 4 5 6 7 8 9
AP-2 30 32 34 80 33 35 36 38 37
AP-8 30 32 99 31 33 35 36 38 37
AP-9 30 32 34 31 33 99 88 38 37
发布于 2018-07-07 16:53:57
啊,我知道了。我需要.all(1)作为<= 100。
https://stackoverflow.com/questions/51225130
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