我有下面的结构,我只想在每个锚元素上添加一个额外的类
<ul class="pagination">
<li class="paginate_button page-item previous disabled" aria-controls="users" tabindex="0" id="users_previous">
<a href="#">Prev</a>
</li>
<li class="paginate_button page-item active" aria-controls="users" tabindex="0">
<a href="#">1</a>
</li>
<li class="paginate_button page-item next disabled" aria-controls="users" tabindex="0" id="users_next">
<a href="#">Next</a>
</li>
</ul>谢谢你,卡莱姆
发布于 2018-07-11 11:21:14
您可以轻松地在每个锚标记上添加一个类,如下所示:
$('.pagination a').addClass('myNewClassName');这只会将它们添加到具有类pagination的父类中。
要做到这一点,可以使用可数据的方式:
$('#myDataTable').DataTable({
...
"drawCallback": function () {
$('.dataTables_paginate > .pagination a').addClass('myNewClassName');
}
});发布于 2018-07-11 11:24:09
试试看
$('#Mytable').DataTable({
addClassFunction(); // call this function in DataTable/pagination method
});
function addClassFunction(){
$('.pagination a').addClass('newClass');
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul class="pagination">
<li class="paginate_button page-item previous disabled" aria-controls="users" tabindex="0" id="users_previous">
<a href="#">Prev</a>
</li>
<li class="paginate_button page-item active" aria-controls="users" tabindex="0">
<a href="#">1</a>
</li>
<li class="paginate_button page-item next disabled" aria-controls="users" tabindex="0" id="users_next">
<a href="#">Next</a>
</li>
</ul>
https://stackoverflow.com/questions/51284132
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