正确的语法是什么?我知道这是错误的,因为我打电话了,但我需要这样的东西
SELECT *
FROM `wp_postmeta`
WHERE `meta_key` = 'request_count' AND (`meta_key` = 'approval' AND `meta_value` = '1');我试过这个
SELECT *
FROM `wp_postmeta`
WHERE `meta_key` IN ('request_count','approval') AND `meta_value` = '1';但它不能做我想做的事。
编辑
ID |Meta_key | Meta_value|
1 |request_count | 1 |
1 |approval | 1 |
2 |approval | 1 |
3 |request_count | 2 |
3 |approval | 2 |我想显示ID 1,因为它有一个request_count in meta_key,它在meta_key中的审批 is 等于与1
发布于 2018-07-24 04:35:23
根据示例数据,下面的查询应该可以工作:
SELECT pm.*, (select pm2.value FROM wp_postmeta pm2 WHERE pm2.post_id = pm.post_id AND pm2.`key` = 'approval' AND pm2.`value` = '1') AS approval
FROM wp_postmeta pm
WHERE pm.`key` = 'request_count'
HAVING approval = 1即使这个查询也能工作,我相信数据结构是不正确的。顺便说一句,那是另一个问题。
https://stackoverflow.com/questions/51489958
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