UnknownEntityTypeException:无法找到持久化程序
UnknownEntityTypeException:无法找到持久化程序
提问于 2018-07-25 07:34:32
我想把JPA和Spring一起用在野蝇上。我尝试过这种配置：
application.properties：
spring.jmx.enabled=false
spring.datasource.jndi-name=java:/global/production
spring.datasource.driver-class-name=org.mariadb.jdbc.Driver
spring.jpa.show-sql = true
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.MariaDBDialect
spring.jpa.hibernate.ddl-auto = create-dropPOM档案：
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.0.3.RELEASE</version>
<relativePath />
</parent>
<dependencies>
<dependency>
<groupId>com.fasterxml.jackson.module</groupId>
<artifactId>jackson-module-jaxb-annotations</artifactId>
<version>2.9.5</version>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-actuator</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-thymeleaf</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.session</groupId>
<artifactId>spring-session-core</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
</dependencies>配置：
@Configuration
@ComponentScan("org.rest.api.server.*")
public class AppConfig {
@Bean
public EntityManager entityManager(EntityManagerFactory emf) {
return emf.createEntityManager();
}
}但是，当我尝试执行查询时，我得到：
Caused by: org.hibernate.UnknownEntityTypeException: Unable to locate persister: org.rest.api.server.repository.Terminals
10:28:27,539 ERROR [stderr] (default task-1) at org.hibernate.metamodel.internal.MetamodelImpl.locateEntityPersister(MetamodelImpl.java:642)配置实体的正确方法是什么？也许我需要手动绘制地图？
回答 4
Stack Overflow用户
发布于 2020-04-24 03:19:31
当实体没有被拾取，数据库表没有被spring引导自动配置创建或映射时，就会引发此错误。为了解决这个问题，您需要在Spring应用程序类中将@EntityScan(basePackages = {"**entities_package_name"})添加到@SpringBootApplication下面。
package com.bill.app;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.autoconfigure.domain.EntityScan;
@SpringBootApplication
@EntityScan( basePackages = {"com.bill.entity"} ) // entities package name
public class BillWebApplication {
public static void main(String[] args) {
SpringApplication.run(BillWebApplication.class, args);
}
}Stack Overflow用户
发布于 2020-12-09 17:57:22
当您的persistence.xml文件缺少您试图使用的某些实体时，可能会发生此错误。
Stack Overflow用户
发布于 2018-07-25 08:57:35
这就是我配置entityManager的方式。您传递的dataSource是配置中的另一个bean。你可以看看BasicDataSource。
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
LocalContainerEntityManagerFactoryBean em = new LocalContainerEntityManagerFactoryBean();
em.setDataSource(dataSource);
em.setJpaDialect(new HibernateJpaDialect());
em.setPackagesToScan("org.rest.api.server.folder");
JpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter(); // JPA implementation
em.setJpaVendorAdapter(vendorAdapter);
return em;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51513289
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